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CCGPS Geometry Solving Quadratics Notes and Practice Name: ________________________________________________ Date: _______________________ Solving Quadratics by Factoring and Graphing Let’s start by using our knowledge from Unit 5A and graphing quadratics. Graph the function y = x2 + 2x – 3 using a table. 3 x 1 0 1 fx Then, find the x-intercepts, which we will call the zeroes for the rest of this unit. x = ___ and x = ___ These same zeroes can be found by factoring the quadratic and using the Zero Product Property. The property states that if the product of two factors is zero, then at least one of the factors must be zero. For instance, if a x b = 0, then either a or b can be zero to make the product zero. To see how this applies to the above example, let’s set x2 + 2x – 3 equal to zero and factor it. (x + 3) (x -1) = 0 If we plug in -3 into (x + 3) or 1 into (x – 1), then the resulting product is 0. These are the same two zeroes that were found by graphing the function. Example 1: Solve: x2 + 3x – 18 = 0 Practice: 1) x2 + 10x + 16 = 0 Example 2: Solve: 2x2 + 5x – 12 = 0 2) 6x2 + 7x – 3 = 0 3) 5x2 + 10x = 0 CCGPS Geometry Solving Quadratics Notes and Practice Application 1: A ball is thrown up with an initial velocity of 32 ft/sec at a height of 240 ft. Use the equation h(t) = -16t2 + vot + ho to find when the ball hits the ground. Now, let’s say that we wanted to know when the ball was at certain height instead of hitting the ground. For instance, if we wanted to catch the ball on its way back down, we would want to know where it was at 240 feet again (the start height). Instead of setting the function equal to 0, we would set it equal to 240 and solve by factoring as shown below. -16t2 + 32t + 240 = 240 -16t2 + 32t = 0 -16t(t – 2) = 0 So, t = 0 or 2. In this case, 2 is the answer, as t = 0 is when the ball was first thrown. Application 2: Bill throws a water balloon from his hotel balcony with an initial velocity of 32 ft/sec at a height of 128 feet. When will the balloon reach his friend whose balcony is at 80 feet above the ground? This same approach can be used in finding the intersection of a quadratic function and any linear function. For example, what are the solutions of this system of equations? y = -3x2 + 4x + 20 y = -2x – 4 We will just sent them equal to each other and solve. -3x2 + 4x + 20 = -2x – 4 -3x2 + 6x + 24 = 0 -3(x2 – 2x – 8) = 0 -3(x – 4)(x + 2) = 0 (x – 4) = 0 and (x +2) = 0 So, x = -2 or 4 CCGPS Geometry Solving Quadratics Notes and Practice Practice: Solve each of the following by factoring. 1) x2 – 7x + 6 = 0 2) 2x2 – 5x + 2 = 0 3) 4x2 – 16x = 0 4) 3x2 +13x + 4 = 0 5) x2 – 6x = 9 6) 5x2 + 22 = 20x +2 7) The dimensions of a rectangular flower garden are 8 m by 15m. Each dimension was increased by the same amount. The garden now has an area of 198 m2. Find the dimensions of the new garden. 8) A rectangular pool measures 5 yd by 6 yd. A concrete deck is constructed around the pool. The deck and pool together cover an area of 72 yd.2 How wide is the deck?