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Screen Stage Lecturer’s desk Row A 14 13 12 11 10 9 8 7 6 5 4 3 2 1 Row B 9 8 7 6 5 4 3 2 1 Row C 28 27 26 25 24 23 22 Row C 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 Row C Row D 28 27 26 25 24 23 22 Row D 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 Row D Row E 28 27 26 25 24 23 22 Row E 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 Row E Row F 28 27 26 25 24 23 22 Row F 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 Row F Row G 28 27 26 25 24 23 22 Row G 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 Row G Row H 28 27 26 25 24 23 22 Row H 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 Row H Row J 28 27 26 25 24 23 22 Row J 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 Row J Row K 28 27 26 25 24 23 22 Row K 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 Row K Row L 28 27 26 25 24 23 22 Row L 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 Row L 9 8 7 6 5 4 3 2 1 Row M 2 1 Row M 28 27 26 25 24 23 22 table 3 broken desk 2 14 11 10 Row M 21 20 19 18 17 16 14 1 13 12 13 13 12 11 10 Projection Booth Modern Languages R/L handed table 3 2 1 MGMT 276: Statistical Inference in Management Spring 2015 Schedule of readings Before our next exam (March 24th) We’ll be jumping around some…we will start with chapter 7 Lind (5 – 11) Chapter 5: Survey of Probability Concepts Chapter 6: Discrete Probability Distributions Chapter 7: Continuous Probability Distributions Chapter 8: Sampling Methods and CLT Chapter 9: Estimation and Confidence Interval Chapter 10: One sample Tests of Hypothesis Chapter 11: Two sample Tests of Hypothesis Plous (10, 11, 12 & 14) Chapter 10: The Representativeness Heuristic Chapter 11: The Availability Heuristic Chapter 12: Probability and Risk Chapter 14: The Perception of Randomness Homework due – Tuesday (March 3rd) On class website: Please print and complete Homework Assignment 9 Chapter 5 Approaches to probabilities and Chapter 7 Interpreting probabilities using the normal curve Calculating z-score, raw scores and areas (probabilities) under normal curve Use this as your study guide By the end of lecture today 2/26/15 Counting ‘standard deviationses’ – z scores Connecting raw scores, z scores and probability Connecting probability, proportion and area of curve Percentiles Approaches to probability: Empirical, Subjective and Classical Normal distribution Raw scores z-scores Have z Find raw score Formula probabilities Z Scores z table Have z Find area Have area Find z Have raw score Find z Raw Scores Area & Probability Always draw a picture! Homework worksheet Homework worksheet .6800 1 Homework worksheet .9500 2 Homework worksheet .9970 3 Homework worksheet .5000 4 Homework worksheet 33-30 z = 1.5 z= 2 Go to table .4332 5 z= 33-30 z = 1.5 2 Go to table .4332 Add area Lower half .4332 + .5000 = .9332 6 Homework worksheet Go to 33-30 z= .4332 = 1.5 table 2 Subtract from .5000 .5000 - .4332 = .0668 7 z= 29-30 2 = -.5 Go to .1915 table Add to upper Half of curve .5000 - .1915 = .6915 8 25-30 2 31-30 = 2 = = -2.5 =.5 Go to table Go to table .4938 .1915 .4938 + .1915 = .6853 9 z= Go to 27-30 = -1.5 table 2 .4332 Subtract From .5000 .5000 - .4332 = .0668 10 z= 25-30 2 = -2.5 Go to table .4938 Add lower Half of curve .5000 + .4938 = .9938 11 z= Go to 32-30 = 1.0 table 2 .3413 Subtract from .5000 .5000 - .3413 = .1587 12 50th percentile = median 30 13 28 32 14 77th percentile Find area of interest .7700 - .5000 = .2700 x = mean + z σ = 30 + (.74)(2) = 31.48 Find nearest z = .74 15 13th percentile Find area of interest .5000 - .1300 = .3700 x = mean + z σ = 30 + (-1.13)(2) = 27.74 Find nearest z = -1.13 16 Please use the following distribution with a mean of 200 and a standard deviation of 40. .6800 17 .9500 18 .9970 19 = 230-200 = .75 40 Go to table .2734 20 190-200 = -.25 Go to z= table 40 .0987 Subtract from .5000 .5000 - .0987 = .4013 21 180-200 = -.5 Go to z= table 40 .1915 Add to upper .5000 + .1915 = .6915 Half of curve 22 236-200 = 0.9 z= 40 Go to table .3159 Subtract from .5000 .5000 - .3159 = .1841 23 192 - 200 40 = 222 - 200 40 z= z = -.2 =.55 Go to table Go to table .0793 .2088 .0793 + .2088 = .2881 24 z= 275-200 = 1.875 40 Go to table .4693 or .4699 Add area Lower half .4693 + .5000 = .9693 .4699 + .5000 = .9699 25 295-200 z = 2.375 z= 40 Go to table .4911 or .4913 .5000 - .4911 = .0089 Add area Lower half .5000 - .4913 = .0087 26 Add to upper 130-200 = -1.75 Go to .5000 + .4599 = .9599 z= .4599 table Half of curve 40 27 Subtract 130-200 = -1.75 Go to z= .4599 table from .5000 40 .5000 - .4599 = .0401 28 99th percentile Find area of interest .9900 - .5000 = .4900 x = mean + z σ = 200 + (2.33)(40) = 293.2 Find nearest z = 2.33 29 33rd percentile Find area of interest .5000 - .3300 = .1700 x = mean + z σ = 200 + (-.44)(40) = 182.4 Find nearest z = -.44 30 40th percentile Find area of interest .5000 - .4000 = .1000 x = mean + z σ = 200 + (-.25)(40) = 190 Find nearest z = -.25 31 67th percentile Find area of interest .6700 - .5000 = .1700 x = mean + z σ = 200 + (.44)(40) = 217.6 Find nearest z = .44 32 . .8276 .1056 .2029 .1915 .4332 44 - 50 4 .3944 = -1.5 z of 1.5 = area of .4332 55 - 50 4 = +1.25 z of 1.25 = area of .3944 .4332 +.3944 = .8276 .3944 .3944 55 - 50 4 = +1.25 1.25 = area of .3944 .5000 - .3944 = .1056 52 - 50 4 = +.5 z of .5 = area of .1915 55 - 50 4 = +1.25 z of 1.25 = area of .3944 .3944 -.1915 = .2029 What is probability 1. Empirical probability: relative frequency approach Number of observed outcomes Number of observations Probability of getting into an educational program Number of people they let in Number of applicants 400 600 66% chance of getting admitted Probability of getting a rotten apple Number of rotten apples Number of apples 5 100 5% chance of getting a rotten apple What is probability 1. Empirical probability: relative frequency approach “There is a 20% chance “More than 30% of the 10% of people who buy a that a new stock results from major Number of observed house with no pool build offered in outcomes an initial search engines for the one. What is the public offering (IPO) Number observations keyword phrase “ring likelihood that Bob will?of will reach or exceed tone” are fake its target price on Probability of hitting the corvette pages created by the first day.” spammers.” Number of carts that hit corvette Number of carts rolled 182 200 = .91 91% chance of hitting a corvette 2. Classic probability: a priori probabilities based on logic rather than on data or experience. All options are equally likely (deductive rather than inductive). Likelihood get Chosen at Lottery question right random to be on multiple team captain choice test Number of outcomes of specific event Number of all possible events In throwing a die what is the probability of getting a “2” Number of sides with a 2 Number of sides 1 16% chance of getting a two = 6 In tossing a coin what is probability of getting a tail Number of sides with a 1 Number of sides 1 = 2 50% chance of getting a tail 3. Subjective probability: based on someone’s personal judgment (often an expert), and often used when empirical and classic approaches are not available. Likelihood get a 60% chance Likelihood ”B” in the class that Patriots that company will play at will invent Super Bowl There Verizon new type ofis a 5% chance that battery with Sprint merge will Bob says he is 90% sure he could swim across the river Approach Example Empirical There is a 2 percent chance of twins in a randomly-chosen birth Classical There is a 50 % probability of heads on a coin flip. Subjective There is a 5% chance that Verizon will merge with Sprint The probability of an event is the relative likelihood that the event will occur. The probability of event A [denoted P(A)], must lie within the interval from 0 to 1: 0 < P(A) < 1 If P(A) = 0, then the event cannot occur. If P(A) = 1, then the event is certain to occur. The probabilities of all simple events must sum to 1 P(S) = P(E1) + P(E2) + … + P(En) = 1 For example, if the following number of purchases were made by credit card: 32% P(credit card) = .32 debit card: 20% Probability P(debit card) = .20 cash: 35% P(cash) = .35 check: 13% P(check) = .13 Sum = 100% Sum = 1.0 What is the complement of the probability of an event The probability of event A = P(A). The probability of the complement of the event A’ = P(A’) • A’ is called “A prime” Complement of A just means probability of “not A” • P(A) + P(A’) = 100% • P(A) = 100% - P(A’) • P(A’) = 100% - P(A) Probability of getting a rotten apple 5% chance of “rotten apple” 95% chance of “not rotten apple” 100% chance of rotten or not Probability of getting into an educational program 66% chance of “admitted” 34% chance of “not admitted” 100% chance of admitted or not Two mutually exclusive characteristics: if the occurrence of any one of them automatically implies the non-occurrence of the remaining characteristic Two events are mutually exclusive if they cannot occur at the same time (i.e. they have no outcomes in common). Two propositions that logically cannot both be true. Warranty No Warranty For example, a car repair is either covered by the warranty (A) or not (B). http://www.thedailyshow.com/video/index.jhtml?videoId=188474&title=an-arab-family-man Collectively Exhaustive Events Events are collectively exhaustive if their union is the entire sample space S. Two mutually exclusive, collectively exhaustive events are dichotomous (or binary) events. Warranty No Warranty For example, a car repair is either covered by the warranty (A) or not (B). Satirical take on being “mutually exclusive” Warranty Recently a public figure in the heat of the moment inadvertently made a statement that reflected extreme stereotyping that many would Arab find highly offensive. It is within this context that comical satirists have used the concept of being “mutually exclusive” to have fun with the statement. Transcript: Speaker 1: “He’s an Arab” Speaker 2: “No ma’am, no ma’am. He’s a decent, family man, citizen…” http://www.thedailyshow.com/video/index.jhtml?videoId=188474&title=an-arab-family-man No Warranty Decent , family man Union versus Intersection Union of two events means Event A or Event B will happen ∩ P(A B) Intersection of two events means Event A and Event B will happen Also called a “joint probability” P(A ∩ B) The union of two events: all outcomes in the sample space S that are contained either in event A or in event B or both (denoted A B or “A or B”). may be read as “or” since one or the other or both events may occur. 5A-55 The union of two events: all outcomes contained either in event A or in event B or both (denoted A B or “A or B”). What is probability of drawing a red card or a queen? what is Q R? It is the possibility of drawing either a queen (4 ways) or a red card (26 ways) or both (2 ways). Probability of picking a Queen Probability of picking a Red 26/52 4/52 2/52 P(Q) = 4/52 (4 queens in a deck) P(R) = 26/52 (26 red cards in a deck) P(Q R) = 2/52 Probability of picking both R and Q P(Q R) = P(Q) + P(R) – P(Q R) = 4/52 + 26/52 – 2/52 = 28/52 = .5385 or 53.85% (2 red queens in a deck) When you add the P(A) and P(B) together, you count the P(A and B) twice. So, you have to subtract P(A B) to avoid overstating the probability. Union versus Intersection Union of two events means Event A or Event B will happen ∩ P(A B) Intersection of two events means Event A and Event B will happen Also called a “joint probability” P(A ∩ B) The intersection of two events: all outcomes contained in both event A and event B (denoted A B or “A and B”) What is probability of drawing red queen? what is Q R? It is the possibility of drawing both a queen and a red card (2 ways). If two events are mutually exclusive (or disjoint) their intersection is a null set (and we can use the “Special Law of Addition”) P(A ∩ B) = 0 Intersection of two events means Event A and Event B will happen Examples: If A = Poodles mutually exclusive If B = Labradors Poodles and Labs: Mutually Exclusive (assuming purebred) If two events are mutually exclusive (or disjoint) their intersection is a null set (and we can use the “Special Law of Addition”) Intersection of two events means Event A and Event B will happen P(A ∩ B) = 0 Dog Pound Examples: If A = Poodles (let’s say 10% of dogs are poodles) If B = Labradors (let’s say 15% of dogs are labs) What’s the probability of picking a poodle or a lab at random from pound? P(A B) = P(A) +P(B) P(poodle or lab) = P(poodle) + P(lab) ∩ P(poodle or lab) = (.10) + (.15) = (.25) Poodles and Labs: Mutually Exclusive (assuming purebred) Conditional Probabilities Probability that A has occurred given that B has occurred P(A | B) = P(A ∩ B) P(B) Denoted P(A | B): The vertical line “ | ” is read as “given.” The sample space is restricted to B, an event that has occurred. A B is the part of B that is also in A. The ratio of the relative size of A B to B is P(A | B). Conditional Probabilities Probability that A has occurred given that B has occurred Of the population aged 16 – 21 and not in college: P(U) = .1350 Unemployed 13.5% No high school diploma 29.05% Unemployed with no high school diploma 5.32% P(ND) = .2905 P(UND) = .0532 What is the conditional probability that a member of this population is unemployed, given that the person has no diploma? P(A | B) = P(A ∩ B) P(B) = .0532 = .1831 .2905 or 18.31% Conditional Probabilities Probability that A has occurred given that B has occurred Of the population aged 16 – 21 and not in college: P(U) = .1350 Unemployed 13.5% No high school diploma 29.05% Unemployed with no high school diploma 5.32% P(ND) = .2905 P(UND) = .0532 What is the conditional probability that a member of this population is unemployed, given that the person has no diploma? P(A | B) = P(A ∩ B) P(B) = .0532 = .1831 .2905 or 18.31%