Download geometry semester 1 final practice

Name: ________________________ Class: ___________________ Date: __________
ID: A
Geometry Final Semester 1 Practice
Multiple Choice
Identify the choice that best completes the statement or answers the question.

→
5. Find a counterexample to show that the conjecture
is false.
Conjecture: The product of two positive numbers is
greater than the sum of the two numbers.
a. A counterexample exists, but it is not shown
above.
b. 3 and 5
c. 2 and 2
d. There is no counterexample. The conjecture is
true.
1. Name the ray that is opposite RS .
a.
b.
c.
d.


→
QS

→
6. Judging by appearance, classify the figure in as
many ways as possible.
RP

→
PS

→
RS
2. Write this statement as a conditional in if-then
form:
All triangles have three sides.
a. If a figure is a triangle, then it has three sides.
b. If a figure is a triangle, then all triangles have
three sides.
c. If a figure has three sides, then it is not a
triangle.
d. If a triangle has three sides, then all triangles
have three sides.
a.
b.
3. On a blueprint, the scale indicates that 6 cm
represent 18 feet. What is the length of a room that
is 7.8 cm long and 5 cm wide on the blueprint?
a. 6.5 ft
b. 1.3 ft
c. 19.3 ft
d. 23.4 ft
c.
d.
square, rectangle, quadrilateral
rectangle, square, quadrilateral, parallelogram,
rhombus
rectangle, square, parallelogram
rhombus, trapezoid, quadrilateral, square
7. Write an equation in point-slope form, y – y1 = m(x
– x1), of the line through points (5, –3) and (6, 9)
Use (5, –3) as the point (x1, y1).
a. (y + 3) = 12(x – 5)
b. (y – 3) = –12(x + 5)
c. (y – 3) = 12(x + 5)
d. (y + 3) = –12(x – 5)
4. A model is made of a car. The car is 8 feet long and
the model is 10 inches long. What is the ratio of the
length of the car to the length of the model?
a. 5 : 48
b. 48 : 5
c. 10 : 8
d. 8 : 10
1
Name: ________________________
ID: A
8. What can you conclude from the information in the
diagram?
a.
1. LM ≅ NM
2. ∠NQP is a right angle
3. ∠NPQ and ∠OPQ are vertical angles
b.
1. LM ≅ NM
2. PN ≅ PO
3. ∠PNO and ∠LNM are vertical angles
1. LM ≅ LN
2. PN ≅ PO
3. ∠PNO and ∠LNM are adjacent angles
1. LM ≅ LN
2. ∠NQP is a right angle
3. ∠NPQ and ∠OPQ are adjacent angles
c.
d.
9. Can you use the ASA Postulate, the AAS Theorem,
or both to prove the triangles congruent?
a.
b.
c.
d.
ASA only
AAS only
either ASA or AAS
neither
Solve the proportion.
10.
n−6
a.
b.
c.
d.
11.
5
a
a.
b.
c.
d.
3n
=
–3
9
n−5
12. A conditional can have a ____ of true or false.
a. truth value
b. conclusion
c. hypothesis
d. counterexample
3n + 1
17
2
13. The Polygon Angle-Sum Theorem states: The sum
of the measures of the angles of an n-gon is ____.
a. (n − 1)180
n−2
b.
180
c. (n − 2)180
180
d.
n−1
5
3
=
20
36
9
144
20
45
2
Name: ________________________
ID: A
14. The chips used in the board game MathFuries have
the shape of octagons. How many sides does each
MathFuries chip have?
a. 3
b. 5
c. 8
d. 10
15. If
a.
b.
c.
d.
a
b
=
4b
8b
7b
14b
4
7
, then 7a = ____.
Explain why the triangles are similar. Then find the value of x.
16.
a.
AA Postulate; 6
1
2
c.
SSS Postulate; 26
b.
AA Postulate; 26
d.
SAS Postulate; 6
1
2
17. Use the Law of Syllogism to draw a conclusion from the two given statements.
If a number is a multiple of 64,then it is a multiple of 8.
If a number is a multiple of 8, then it is a multiple of 2.
a. If a number is a multiple of 64, then it is a multiple of 2.
b. The number is a multiple of 8.
c. If a number is not a multiple of 2, then the number is not a multiple of 64.
d. The number is a multiple of 2.
18. Which statement is a counterexample for the following conditional?
If you live in Springfield, then you live in Illinois.
a. Jonah Lincoln lives in Springfield, Illinois.
b. Billy Jones lives in Chicago, Illinois.
c. Sara Lucas lives in Springfield.
d. Erin Naismith lives in Springfield, Massachusetts.
3
Name: ________________________
ID: A
State whether the triangles are similar. If so, write a similarity statement and the postulate or theorem you
used.
19.
21. Use the information in the diagram to determine
the height of the tree to the nearest foot.
a.
b.
c.
d.
a.
b.
c.
d.
72 ft
264 ft
60 ft
80 ft
22. m∠R = 160 and m∠S = 90. Find m∠T. The diagram
is not to scale.
∆ABC ∼ ∆MNO; SSS
∆ABC ∼ ∆MNO; SAS
∆ABC ∼ ∆MNO; AA
The triangles are not similar.
20.
a.
b.
c.
d.
a.
b.
c.
d.
∆ADB ∼ ∆CDB; SAS
∆ABD ∼ ∆CDB; SAS
∆ADB ∼ ∆CDB; SSS
The triangles are not similar.
4
90
20
80
10
Name: ________________________
ID: A
23. Find the value of x.
a.
b.
c.
d.
7
9.5
6
8
24. Use the Law of Detachment to draw a conclusion from the two given statements. If not possible, write not
possible.
I can go to the concert if I can afford to buy a ticket.
I can go to the concert.
a. I cannot afford to buy the ticket.
b. I can afford to buy a ticket.
c. If I can go to the concert, I can afford the ticket.
d. not possible
25. Which angles are corresponding angles?
a.
b.
c.
d.
26. Find the value of x.
∠3 and ∠4
∠4 and ∠12
∠8 and ∠4
none of these
a.
b.
c.
d.
5
46
134
–18
18
Name: ________________________
ID: A
27. Which three lengths could be the lengths of the
sides of a triangle?
a. 6 cm, 24 cm, 12 cm
b. 12 cm, 9 cm, 21 cm
c. 22 cm, 5 cm, 11 cm
d. 10 cm, 15 cm, 23 cm
30. Find the value of x, given that OP  NQ.
28. Find the values of x, y, and z. The diagram is not to
scale.
a.
b.
c.
d.
a.
b.
c.
d.
x = 20
x = 10
x = 13
x = 25.5
31. The vertices of the trapezoid are the origin along
with A(4d, 4e), B(4 f , 4e), and C(4g, 0). Find the
midpoint of the midsegment of the trapezoid.
x = 89, y = 77, z = 91
x = 77, y = 89, z = 91
x = 77, y = 91, z = 89
x = 89, y = 91, z = 77
29. A model is built having a scale of 1 : 15,000. How
high would a 25,400-ft mountain be in the model?
Give your answer to the nearest inch.
a. 304,800 in.
b. 2 in.
c. 20 in.
d. 10 in.
a.
b.
c.
d.
(d + f + g, e)
(d + f + g, 2e)
(2 f , 2e)
(2d + 2g, 2e)
32. Which statement is the Law of Detachment?
a. If p → q is a true statement and p is true, then
q is true.
b. If p → q is a true statement and q is true, then
p is true.
c. If p → q is a true statement and q is true, then
q → p is true.
d. If p → q and q → r are true, then p → r is
a true statement.
6
Name: ________________________
ID: A
Solve for a and b.
33.
35. DF bisects ∠EDG. Find the value of x. The
diagram is not to scale.
a.
a =
b.
a =
c.
a =
d.
a =
20
, b =
21
400
21
580
21
400
21
, b =
580
21
580
, b =
, b =
21
29
21
20
a.
21
b.
c.
d.
34. What other information do you need in order to
prove the triangles congruent using the SAS
Congruence Postulate?
a.
b.
c.
d.
∠BAC ≅ ∠DAC
∠CBA ≅ ∠CDA
AC ≅ BD
AC ⊥ BD
7
209
17
95
29
19
Name: ________________________
ID: A
36. Which is a correct two-column proof?
Given: r  s
Prove: ∠b and ∠h are supplementary.
a.
Statements
R e asons
1. r  s
1. Given
2. ∠b ≅ ∠h
2. Corresponding Angles
3. ∠c and ∠e are supplementary.
3. Same-Side Exterior Angles
4. ∠e ≅ ∠h
4. Vertical Angles
5. ∠c and ∠h are supplementary.
5. Substitution
Statements
R e asons
1. r  s
1. Given
2. ∠b ≅ ∠c
2. Vertical Angles
3. ∠d and ∠h are supplementary.
3. Alternate Interior Angles
4. ∠e ≅ ∠h
4. Vertical Angles
5. ∠b and ∠h are supplementary.
5. Same-Side Interior Angles
Statements
R e asons
1. r  s
1. Given
2. ∠b ≅ ∠c
2. Vertical Angles
3. ∠c and ∠e are supplementary.
3. Same-Side Interior Angles
4. ∠e ≅ ∠h
4. Vertical Angles
5. ∠b and ∠h are supplementary.
5. Substitution
b.
c.
d.
none of these
8
Name: ________________________
ID: A
41. ∠ACB ≅
37. What is the negation of this statement?
Miguel’s team won the game.
a. Miguel’s team did not play the game.
b. Miguel’s team lost the game.
c. Miguel’s team did not win the game.
d. It was not Miguel’s team that won the game.
?
38. Name the smallest angle of ∆ABC. The diagram is
not to scale.
a.
b.
c.
d.
∠NMP
∠PNM
∠PMN
∠MPN
42. Find the values of a and b.The diagram is not to
scale.
a.
b.
c.
d.
∠B
∠A
Two angles are the same size and smaller than
the third.
∠C
39. Find the missing angle measures. The diagram is
not to scale.
a.
b.
c.
d.
a.
b.
c.
d.
x = 92, y = 70
x = 102, y = 121
x = 70, y = 92
x = 70, y = 102
40. 3 and 7
a. 2 7
b.
c.
d.
21
21
2 6
9
a
a
a
a
= 110, b
= 110, b
= 125, b
= 125, b
= 70
= 55
= 70
= 55
Name: ________________________
ID: A
43. Which choice shows a true conditional with the
hypothesis and conclusion identified correctly?
a. Yesterday was Saturday if
tomorrow is Monday.
Hypothesis: Tomorrow is Monday.
Conclusion: Yesterday was Saturday.
b. If tomorrow is Monday, then
yesterday was Saturday.
Hypothesis: Yesterday was Saturday.
Conclusion: Tomorrow is not Monday.
c. If tomorrow is Monday, then
yesterday was Saturday.
Hypothesis: Yesterday was Saturday.
Conclusion: Tomorrow is Monday.
d. Yesterday was Sunday if tomorrow is Monday.
Hypothesis: Tomorrow is Monday.
Conclusion: Yesterday was Sunday.
45. Alfred is practicing typing. The first time he tested
himself, he could type 20 words per minute. After
practicing for a week, he could type 23 words per
minute. After two weeks he could type 26 words
per minute. Based on this pattern, predict how fast
Alfred will be able to type after 4 weeks of
practice.
a. 29 words per minute
b. 36 words per minute
c. 32 words per minute
d. 26 words per minute
46. Are the triangles similar? If so, explain why.
44. Name an angle supplementary to ∠COB.
a.
b.
c.
d.
a.
b.
c.
d.
∠AOE
∠COD
∠BOE
∠BOA
10
yes, by SSS
yes, by SAS
no
yes, by AA
Name: ________________________
ID: A
47. The two triangles are congruent as suggested by their appearance. Find the value of c. The diagrams are not to
scale.
a.
55
b.
25
c.
7
1. Given
2. PR ≅ SQ
2. Given
3. QR ≅ RQ
4. ∆PQR ≅ ∆SRQ
3.
4.
a.
b.
c.
d.
24
49. Find m∠A. The diagram is not to scale.
48. Justify the last two steps of the proof.
Given: PQ ≅ SR and PR ≅ SQ
Prove: ∆PQR ≅ ∆SRQ
Proof:
1. PQ ≅ SR
d.
a.
b.
c.
d.
?
?
Reflexive Property of ≅ ; SSS
Symmetric Property of ≅ ; SAS
Symmetric Property of ≅ ; SSS
Reflexive Property of ≅ ; SAS
11
63
73
117
107
Name: ________________________
ID: A
50. Find the values of the variables in the
parallelogram. The diagram is not to scale.
51. Which group contains triangles that are all similar?
a.
b.
a.
b.
c.
d.
x = 41, y = 41, z = 139
x = 35, y = 41, z = 139
x = 35, y = 41, z = 104
x = 41, y = 35, z = 104
c.
d.
12
Name: ________________________
ID: A
52. Based on the information in the diagram, can you prove that the figure is a parallelogram? Explain.
a.
b.
c.
d.
Yes; two opposite sides are both parallel and congruent.
No; you cannot prove that the quadrilateral is a parallelogram.
Yes; the diagonals are congruent.
Yes; the diagonals bisect each other.
53. Which description does NOT guarantee that a quadrilateral is a parallelogram?
a. a quadrilateral with consecutive angles supplementary
b. quadrilateral with two opposite sides parallel
c. a quadrilateral with both pairs of opposite sides congruent
d. a quadrilateral with the diagonals bisecting each other
54. When a conditional and its converse are true, you can combine them as a true ____.
a. hypothesis
c. counterexample
b. biconditional
d. unconditional
55. The two rectangles are similar. Which is a correct proportion for corresponding sides?
a.
12
4
=
x
8
b.
12
4
=
x
20
c.
12
8
=
x
4
d.
56. Based on the pattern, what is the next figure in the sequence?
a.
b.
c.
d.
13
4
12
=
x
8
Name: ________________________
ID: A
The polygons are similar, but not necessarily drawn to scale. Find the values of x and y.
57. Triangles ABC and DEF are similar. Find the
lengths of AB and EF.
a.
b.
c.
d.
59. For the parallelogram, find coordinates for P
without using any new variables.
a.
b.
c.
d.
AB = 10; EF = 2
AB = 20; EF = 4
AB = 2; EF = 10
AB = 4; EF = 20
60. Find the value of x. The diagram is not to scale.
58. LMNO is a parallelogram. If NM = x + 20 and OL =
4x + 5 find the value of x and then find NM and
OL.
a.
b.
c.
d.
(c, a)
(c, b)
(a + c, b)
(a – c, c)
x = 5, NM = 25, OL = 25
x = 7, NM = 27, OL = 27
x = 5, NM = 27, OL = 25
x = 7, NM = 25, OL = 27
a.
b.
c.
d.
14
66
70
35
76
Name: ________________________
ID: A
61. Use the information given in the diagram. Tell why
PR ≅ PR and ∠PQR ≅ ∠RSP.
a.
b.
c.
d.
62. Judging by appearances, which figure is a
trapezoid?
a.
Transitive Property, Reflexive Property
Reflexive Property, Transitive Property
Reflexive Property, Given
Given, Reflexive Property
b.
c.
d.
63. What is the inverse of this statement?
If he speaks Arabic, he can act as the interpreter.
a. If he does not speak Arabic, he can act as the interpreter.
b. If he does not speak Arabic, he can’t act as the interpreter.
c. If he speaks Arabic, he can’t act as the interpreter.
d. If he can act as the interpreter, then he does not speak Arabic.
15
Name: ________________________
ID: A
64. ABCDE ∼ GHJDF . Complete the statements.
a.
∠H ≅
b.
a.
∠B; AE
b.
E; DC
c.
E; AE
65. State whether ∆ABC and ∆AED are congruent.
Justify your answer.
a.
b.
c.
d.
d.
∠B; DC
66. From the information in the diagram, can you prove
∆FDG ≅ ∆FDE? Explain.
yes, by either SSS or SAS
yes, by SSS only
yes, by SAS only
No; there is not enough information to
conclude that the triangles are congruent.
a.
b.
c.
d.
yes, by AAA
yes, by SAS
yes, by ASA
no
67. Two sides of a triangle have lengths 10 and 16.
What must be true about the length of the third
side, x?
a. 6 < x < 10
b. 10 < x < 16
c. 6 < x < 16
d. 6 < x < 26
16
Name: ________________________
ID: A
68. The jewelry box has the shape of a regular
pentagon. It is packaged in a rectangular box as
shown here. The box uses two pairs of congruent
right triangles made of foam to fill its four corners.
Find the measure of the foam angle marked.
70. In each pair of triangles, parts are congruent as
marked. Which pair of triangles is congruent by
ASA?
a.
b.
a.
b.
c.
d.
72°
54°
18°
36°
69. Based on the pattern, what are the next two terms
of the sequence?
3 3 3
3
3, ,
,
,
,...
4 16 64 256
3
3
,
a.
1024 1028
3
3
,
b.
260 264
3
3
,
c.
260 1028
3
3
,
d.
1024 4096
c.
d.
17
Name: ________________________
ID: A
71. Are U, V , and W collinear? If so, name the line on which they lie.
a.
b.
c.
d.
No, the three points are not collinear.
Yes, they lie on the line UW.
Yes, they lie on the line V X .
Yes, they lie on the line U X .
73. Q is equidistant from the sides of ∠TSR. Find
m∠RST. The diagram is not to scale.
72. The length of DE is shown. What other length can
you determine for this diagram?
a.
b.
c.
d.
EF = 12
DF = 24
DG = 12
No other length can be determined.
a.
b.
c.
d.
74. If
a.
b.
c.
d.
14
34
17
7
g
h
=
6
, which equation must be true?
5
5h = 6g
h
5
=
g
6
gh = 6 × 5
h
g
=
6
5
75. Construct the line that is perpendicular to the given
line through the given point.
18
Name: ________________________
ID: A
a.
b.
c.
d.
19
Name: ________________________
ID: A
Solve for x.
76.
77. If BCDE is congruent to OPQR, then CD is
congruent to ? .
a.
b.
c.
d.
10
5
5 2
25
a.
b.
c.
OP
OR
PQ
d.
QR
78. Identify the hypothesis and conclusion of this conditional statement:
If two lines intersect at right angles, then the two lines are perpendicular.
a. Hypothesis: The two lines are perpendicular. Conclusion:
Two lines intersect at right angles.
b. Hypothesis: Two lines intersect at right angles. Conclusion:
The two lines are not perpendicular.
c. Hypothesis: Two lines intersect at right angles. Conclusion:
The two lines are perpendicular.
d. Hypothesis: The two lines are not perpendicular. Conclusion:
Two lines intersect at right angles.
79. What is the intersection of plane STXW and plane
TUYX ?
a.
b.
c.
d.
80. Find a counterexample to show that the conjecture
is false.
Conjecture: Any number that is divisible by 6 is
also divisible by 12.
a. 48
b. 30
c. 60
d. 36
←
→
SW
←
→
UY
←

→
TX
←

→
VZ
20
ID: A
Geometry Final Semester 1 Practice
Answer Section
MULTIPLE CHOICE
1. ANS:
REF:
STA:
KEY:
2. ANS:
OBJ:
KEY:
3. ANS:
OBJ:
KEY:
4. ANS:
OBJ:
KEY:
5. ANS:
OBJ:
TOP:
6. ANS:
OBJ:
TOP:
KEY:
7. ANS:
OBJ:
KEY:
8. ANS:
OBJ:
KEY:
9. ANS:
REF:
OBJ:
TOP:
10. ANS:
OBJ:
KEY:
11. ANS:
OBJ:
KEY:
12. ANS:
OBJ:
KEY:
13. ANS:
OBJ:
KEY:
B
PTS: 1
DIF: L2
1-4 Segments, Rays, Parallel Lines and Planes
OBJ: 1-4.1 Identifying Segments and Rays
CA GEOM 1.0
TOP: 1-4 Example 1
ray | opposite rays
A
PTS: 1
DIF: L2
REF: 2-1 Conditional Statements
2-1.1 Conditional Statements
TOP: 2-1 Example 2
hypothesis | conclusion | conditional statement
D
PTS: 1
DIF: L2
REF: 7-1 Ratios and Proportions
7-1.1 Using Ratios and Proportions
TOP: 7-1 Example 4
proportion | Cross-Product Property | word problem
B
PTS: 1
DIF: L2
REF: 7-1 Ratios and Proportions
7-1.1 Using Ratios and Proportions
TOP: 7-1 Example 1
ratio | word problem
C
PTS: 1
DIF: L3
REF: 1-1 Patterns and Inductive Reasoning
1-1.1 Using Inductive Reasoning
STA: CA GEOM 1.0| CA GEOM 3.0
1-1 Example 3
KEY: counterexample | conjecture
B
PTS: 1
DIF: L2
REF: 6-1 Classifying Quadrilaterals
6-1.1 Classifying Special Quadrilaterals
STA: CA GEOM 12.0
6-1 Example 1
special quadrilaterals | quadrilateral | parallelogram | rhombus | square | rectangle | kite | trapezoid
A
PTS: 1
DIF: L2
REF: 3-6 Lines in the Coordinate Plane
3-6.2 Writing Equations of Lines
TOP: 3-6 Example 5
point-slope form
B
PTS: 1
DIF: L2
REF: 1-6 Measuring Angles
1-6.2 Identifying Angle Pairs
TOP: 1-6 Example 5
vertical angles | supplementary angles | adjacent angles | right angle | congruent segments
C
PTS: 1
DIF: L3
4-3 Triangle Congruence by ASA and AAS
4-3.1 Using the ASA Postulate and the AAS Theorem
STA: CA GEOM 2.0| CA GEOM 5.0
4-3 Example 3
KEY: ASA | AAS | reasoning
A
PTS: 1
DIF: L3
REF: 7-1 Ratios and Proportions
7-1.1 Using Ratios and Proportions
TOP: 7-1 Example 3
proportion | Cross-Product Property
A
PTS: 1
DIF: L2
REF: 7-1 Ratios and Proportions
7-1.1 Using Ratios and Proportions
TOP: 7-1 Example 3
proportion | Cross-Product Property
A
PTS: 1
DIF: L2
REF: 2-1 Conditional Statements
2-1.1 Conditional Statements
TOP: 2-1 Example 3
conditional statement | truth value
C
PTS: 1
DIF: L2
REF: 3-5 The Polygon Angle-Sum Theorems
3-5.2 Polygon Angle Sums
STA: CA GEOM 12.0| CA GEOM 13.0
Polygon Angle-Sum Theorem
1
ID: A
14. ANS:
OBJ:
KEY:
15. ANS:
OBJ:
KEY:
16. ANS:
OBJ:
STA:
KEY:
17. ANS:
OBJ:
TOP:
18. ANS:
OBJ:
KEY:
19. ANS:
OBJ:
STA:
KEY:
20. ANS:
OBJ:
STA:
KEY:
21. ANS:
OBJ:
STA:
KEY:
22. ANS:
OBJ:
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C
PTS: 1
DIF: L2
REF: 3-5 The Polygon Angle-Sum Theorems
3-5.1 Classifying Polygons
STA: CA GEOM 12.0| CA GEOM 13.0
classifying polygons
A
PTS: 1
DIF: L2
REF: 7-1 Ratios and Proportions
7-1.1 Using Ratios and Proportions
TOP: 7-1 Example 2
proportion | Cross-Product Property
A
PTS: 1
DIF: L2
REF: 7-3 Proving Triangles Similar
7-3.2 Applying AA, SAS, and SSS Similarity
CA GEOM 2.0| CA GEOM 4.0| CA GEOM 5.0
TOP: 7-3 Example 3
Angle-Angle Similarity Postulate
A
PTS: 1
DIF: L2
REF: 2-3 Deductive Reasoning
2-3.2 Using the Law of Syllogism STA: CA GEOM 1.0
2-3 Example 4
KEY: deductive reasoning | Law of Syllogism
D
PTS: 1
DIF: L2
REF: 2-1 Conditional Statements
2-1.1 Conditional Statements
TOP: 2-1 Example 3
conditional statement | counterexample
A
PTS: 1
DIF: L2
REF: 7-3 Proving Triangles Similar
7-3.1 The AA Postulate and the SAS and SSS Theorems
CA GEOM 2.0| CA GEOM 4.0| CA GEOM 5.0
TOP: 7-3 Example 2
Side-Side-Side Similarity Theorem
A
PTS: 1
DIF: L2
REF: 7-3 Proving Triangles Similar
7-3.1 The AA Postulate and the SAS and SSS Theorems
CA GEOM 2.0| CA GEOM 4.0| CA GEOM 5.0
TOP: 7-3 Example 2
Side-Angle-Side Similarity Theorem | corresponding sides
D
PTS: 1
DIF: L2
REF: 7-3 Proving Triangles Similar
7-3.2 Applying AA, SAS, and SSS Similarity
CA GEOM 2.0| CA GEOM 4.0| CA GEOM 5.0
TOP: 7-3 Example 4
Angle-Angle Similarity Postulate | word problem
B
PTS: 1
DIF: L2
REF: 6-5 Trapezoids and Kites
6-5.1 Properties of Trapezoids and Kites
CA GEOM 7.0| CA GEOM 12.0| CA GEOM 13.0
KEY: kite | sum of interior angles
C
PTS: 1
DIF: L3
REF: 5-1 Midsegments of Triangles
5-1.1 Using Properties of Midsegments
STA: CA GEOM 17.0
midpoint | midsegment | Triangle Midsegment Theorem
D
PTS: 1
DIF: L3
REF: 2-3 Deductive Reasoning
2-3.1 Using the Law of Detachment
STA: CA GEOM 1.0
2-3 Example 3
KEY: deductive reasoning | Law of Detachment
B
PTS: 1
DIF: L2
REF: 3-1 Properties of Parallel Lines
3-1.1 Identifying Angles
STA: CA GEOM 2.0| CA GEOM 4.0| CA GEOM 7.0
3-1 Example 1
KEY: corresponding angles | transversal | parallel lines
D
PTS: 1
DIF: L2
REF: 2-5 Proving Angles Congruent
2-5.1 Theorems About Angles
STA: CA GEOM 1.0| CA GEOM 2.0| CA GEOM 4.0
2-5 Example 1
KEY: vertical angles | Vertical Angles Theorem
D
PTS: 1
DIF: L2
REF: 5-5 Inequalities in Triangles
5-5.2 Inequalities Involving Sides of Triangles
STA: CA GEOM 2.0| CA GEOM 6.0
5-5 Example 4
KEY: Triangle Inequality Theorem
2
ID: A
28. ANS:
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TOP:
A
PTS: 1
DIF: L2
3-4 Parallel Lines and the Triangle Angle-Sum Theorem
3-4.1 Finding Angle Measures in Triangles
STA: CA GEOM 12.0| CA GEOM 13.0
3-4 Example 1
KEY: triangle | sum of angles of a triangle
C
PTS: 1
DIF: L3
REF: 7-1 Ratios and Proportions
7-1.1 Using Ratios and Proportions
TOP: 7-1 Example 4
proportion | Cross-Product Property | scale | word problem
B
PTS: 1
DIF: L3
REF: 7-5 Proportions in Triangles
7-5.1 Using the Side-Splitter Theorem
CA GEOM 4.0| CA GEOM 5.0| CA GEOM 7.0
TOP: 7-5 Example 1
Side-Splitter Theorem
B
PTS: 1
DIF: L3
REF: 6-7 Proofs Using Coordinate Geometry
6-7.1 Building Proofs in the Coordinate Plane
STA: CA GEOM 17.0
algebra | coordinate plane | isosceles trapezoid | midsegment
A
PTS: 1
DIF: L2
REF: 2-3 Deductive Reasoning
2-3.1 Using the Law of Detachment
STA: CA GEOM 1.0
2-3 Example 2
KEY: Law of Detachment | deductive reasoning
B
PTS: 1
DIF: L3
REF: 7-4 Similarity in Right Triangles
7-4.1 Using Similarity in Right Triangles
STA: CA GEOM 4.0| CA GEOM 5.0
7-4 Example 2
KEY: corollaries of the geometric mean | proportion
D
PTS: 1
DIF: L2
4-2 Triangle Congruence by SSS and SAS
OBJ: 4-2.1 Using the SSS and SAS Postulates
CA GEOM 2.0| CA GEOM 5.0
TOP: 4-2 Example 2
SAS | reasoning
D
PTS: 1
DIF: L2
REF: 5-2 Bisectors in Triangles
5-2.1 Perpendicular Bisectors and Angle Bisectors
CA GEOM 2.0| CA GEOM 4.0| CA GEOM 5.0
TOP: 5-2 Example 2
Angle Bisector Theorem | angle bisector
C
PTS: 1
DIF: L2
REF: 3-1 Properties of Parallel Lines
3-1.2 Properties of Parallel Lines
STA: CA GEOM 2.0| CA GEOM 4.0| CA GEOM 7.0
3-1 Example 3
proof | two-column proof | supplementary angles | parallel lines | reasoning
C
PTS: 1
DIF: L2
5-4 Inverses, Contrapositives, and Indirect Reasoning
5-4.1 Writing the Negation, Inverse, and Contrapositive STA: CA GEOM 2.0
5-4 Example 1
KEY: negation
B
PTS: 1
DIF: L2
REF: 5-5 Inequalities in Triangles
5-5.1 Inequalities Involving Angles of Triangles
STA: CA GEOM 2.0| CA GEOM 6.0
5-5 Example 2
KEY: Theorem 5-10
A
PTS: 1
DIF: L2
REF: 3-5 The Polygon Angle-Sum Theorems
3-5.2 Polygon Angle Sums
STA: CA GEOM 12.0| CA GEOM 13.0
3-5 Example 4
KEY: exterior angle | Polygon Angle-Sum Theorem
B
PTS: 1
DIF: L3
REF: 7-4 Similarity in Right Triangles
7-4.1 Using Similarity in Right Triangles
STA: CA GEOM 4.0| CA GEOM 5.0
7-4 Example 1
KEY: geometric mean | proportion
D
PTS: 1
DIF: L2
REF: 4-1 Congruent Figures
4-1.1 Congruent Figures
STA: CA GEOM 4.0| CA GEOM 5.0| CA GEOM 12.0
4-1 Example 1
KEY: congruent figures | corresponding parts
3
ID: A
42. ANS: C
PTS: 1
DIF: L2
REF: 6-5 Trapezoids and Kites
OBJ: 6-5.1 Properties of Trapezoids and Kites
STA: CA GEOM 7.0| CA GEOM 12.0| CA GEOM 13.0
TOP: 6-5 Example 1
KEY: trapezoid | base angles | Theorem 6-15
43. ANS: A
PTS: 1
DIF: L3
REF: 2-1 Conditional Statements
OBJ: 2-1.1 Conditional Statements
KEY: conditional statement | truth value | hypothesis | conclusion
44. ANS: C
PTS: 1
DIF: L2
REF: 1-6 Measuring Angles
OBJ: 1-6.2 Identifying Angle Pairs
TOP: 1-6 Example 4
KEY: supplementary angles
45. ANS: C
PTS: 1
DIF: L2
REF: 1-1 Patterns and Inductive Reasoning
OBJ: 1-1.1 Using Inductive Reasoning
STA: CA GEOM 1.0| CA GEOM 3.0
TOP: 1-1 Example 4
KEY: conjecture | inductive reasoning | word problem | problem solving
46. ANS: D
PTS: 1
DIF: L2
REF: 7-3 Proving Triangles Similar
OBJ: 7-3.1 The AA Postulate and the SAS and SSS Theorems
STA: CA GEOM 2.0| CA GEOM 4.0| CA GEOM 5.0
TOP: 7-3 Example 2
KEY: Angle-Angle Similarity Postulate | Side-Side-Side Similarity Theorem | Side-Angle-Side Similarity
Theorem
47. ANS: C
PTS: 1
DIF: L2
REF: 4-1 Congruent Figures
OBJ: 4-1.1 Congruent Figures
STA: CA GEOM 4.0| CA GEOM 5.0| CA GEOM 12.0
TOP: 4-1 Example 1
KEY: congruent figures | corresponding parts
48. ANS: A
PTS: 1
DIF: L2
REF: 4-2 Triangle Congruence by SSS and SAS
OBJ: 4-2.1 Using the SSS and SAS Postulates
STA: CA GEOM 2.0| CA GEOM 5.0
TOP: 4-2 Example 1
KEY: SSS | reflexive property | proof
49. ANS: B
PTS: 1
DIF: L3
REF: 3-5 The Polygon Angle-Sum Theorems
OBJ: 3-5.2 Polygon Angle Sums
STA: CA GEOM 12.0| CA GEOM 13.0
KEY: pentagon | exterior angle | sum of angles of a polygon
50. ANS: C
PTS: 1
DIF: L2
REF: 6-2 Properties of Parallelograms
OBJ: 6-2.1 Properties: Sides and Angles STA: CA GEOM 7.0| CA GEOM 13.0
KEY: parallelogram | opposite angles | consectutive angles | transversal
51. ANS: D
PTS: 1
DIF: L2
REF: 7-3 Proving Triangles Similar
OBJ: 7-3.1 The AA Postulate and the SAS and SSS Theorems
STA: CA GEOM 2.0| CA GEOM 4.0| CA GEOM 5.0
TOP: 7-3 Example 2
KEY: Angle-Angle Similarity Postulate | Side-Angle-Side Similarity Theorem | Side-Side-Side Similarity
Theorem
52. ANS: D
PTS: 1
DIF: L2
REF: 6-3 Proving That a Quadrilateral is a Parallelogram
OBJ: 6-3.1 Is the Quadrilateral a Parallelogram?
STA: CA GEOM 7.0| CA GEOM 12.0
TOP: 6-3 Example 2
KEY: opposite angles | parallelogram | Theorem 6-8
53. ANS: B
PTS: 1
DIF: L3
REF: 6-4 Special Parallelograms
OBJ: 6-4.2 Is the Parallelogram a Rhombus or a Rectangle?
STA: CA GEOM 7.0| CA GEOM 12.0| CA GEOM 13.0
KEY: square | reasoning
54. ANS: B
PTS: 1
DIF: L2
REF: 2-2 Biconditionals and Definitions
OBJ: 2-2.1 Writing Biconditionals
TOP: 2-2 Example 1
KEY: conditional statement | biconditional statement
4
ID: A
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TOP:
A
PTS: 1
DIF: L2
REF: 7-2 Similar Polygons
7-2.1 Similar Polygons
TOP: 7-2 Example 1
similar polygons | corresponding sides
B
PTS: 1
DIF: L2
REF: 1-1 Patterns and Inductive Reasoning
1-1.1 Using Inductive Reasoning
STA: CA GEOM 1.0| CA GEOM 3.0
1-1 Example 1
KEY: pattern | inductive reasoning
A
PTS: 1
DIF: L2
REF: 7-2 Similar Polygons
7-2.1 Similar Polygons
TOP: 7-2 Example 3
corresponding sides | proportion | similar polygons
A
PTS: 1
DIF: L2
REF: 6-2 Properties of Parallelograms
6-2.1 Properties: Sides and Angles STA: CA GEOM 7.0| CA GEOM 13.0
6-2 Example 2
KEY: parallelogram | algebra | Theorem 6-1
C
PTS: 1
DIF: L2
6-6 Placing Figures in the Coordinate Plane
OBJ: 6-6.1 Naming Coordinates
6-6 Example 2
KEY: parallelogram | coordinate plane | algebra
B
PTS: 1
DIF: L2
REF: 5-1 Midsegments of Triangles
5-1.1 Using Properties of Midsegments
STA: CA GEOM 17.0
5-1 Example 1
KEY: midsegment | Triangle Midsegment Theorem
C
PTS: 1
DIF: L2
REF: 4-1 Congruent Figures
4-1.1 Congruent Figures
STA: CA GEOM 4.0| CA GEOM 5.0| CA GEOM 12.0
4-1 Example 4
KEY: congruent figures | corresponding parts | proof
C
PTS: 1
DIF: L2
REF: 6-1 Classifying Quadrilaterals
6-1.1 Classifying Special Quadrilaterals
STA: CA GEOM 12.0
trapezoid
B
PTS: 1
DIF: L2
5-4 Inverses, Contrapositives, and Indirect Reasoning
5-4.1 Writing the Negation, Inverse, and Contrapositive STA: CA GEOM 2.0
5-4 Example 2
KEY: contrapositive
D
PTS: 1
DIF: L2
REF: 7-2 Similar Polygons
7-2.1 Similar Polygons
TOP: 7-2 Example 1
similar polygons
A
PTS: 1
DIF: L2
4-2 Triangle Congruence by SSS and SAS
OBJ: 4-2.1 Using the SSS and SAS Postulates
CA GEOM 2.0| CA GEOM 5.0
TOP: 4-2 Example 3
SSS | SAS | reasoning
C
PTS: 1
DIF: L2
4-3 Triangle Congruence by ASA and AAS
4-3.1 Using the ASA Postulate and the AAS Theorem
STA: CA GEOM 2.0| CA GEOM 5.0
4-3 Example 3
KEY: ASA | reasoning
D
PTS: 1
DIF: L2
REF: 5-5 Inequalities in Triangles
5-5.2 Inequalities Involving Sides of Triangles
STA: CA GEOM 2.0| CA GEOM 6.0
5-5 Example 5
KEY: Triangle Inequality Theorem
D
PTS: 1
DIF: L2
REF: 3-5 The Polygon Angle-Sum Theorems
3-5.2 Polygon Angle Sums
STA: CA GEOM 12.0| CA GEOM 13.0
3-5 Example 5
KEY: angle | pentagon | Polygon Angle-Sum Theorem
D
PTS: 1
DIF: L2
REF: 1-1 Patterns and Inductive Reasoning
1-1.1 Using Inductive Reasoning
STA: CA GEOM 1.0| CA GEOM 3.0
1-1 Example 1
KEY: pattern | inductive reasoning
5
ID: A
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B
PTS: 1
DIF: L2
4-3 Triangle Congruence by ASA and AAS
4-3.1 Using the ASA Postulate and the AAS Theorem
STA: CA GEOM 2.0| CA GEOM 5.0
4-3 Example 1
KEY: ASA
B
PTS: 1
DIF: L2
REF: 1-3 Points, Lines, and Planes
1-3.1 Basic Terms of Geometry
STA: CA GEOM 1.0
1-4 Example 1
KEY: point | line | collinear points
A
PTS: 1
DIF: L2
REF: 5-2 Bisectors in Triangles
5-2.1 Perpendicular Bisectors and Angle Bisectors
CA GEOM 2.0| CA GEOM 4.0| CA GEOM 5.0
TOP: 5-2 Example 1
perpendicular bisector | Perpendicular Bisector Theorem
B
PTS: 1
DIF: L3
REF: 5-2 Bisectors in Triangles
5-2.1 Perpendicular Bisectors and Angle Bisectors
CA GEOM 2.0| CA GEOM 4.0| CA GEOM 5.0
TOP: 5-2 Example 2
Converse of the Angle Bisector Theorem | angle bisector
B
PTS: 1
DIF: L2
REF: 7-1 Ratios and Proportions
7-1.1 Using Ratios and Proportions
TOP: 7-1 Example 2
Cross-Product Property | proportion
B
PTS: 1
DIF: L2
3-8 Constructing Parallel and Perpendicular Lines
OBJ: 3-8.2 Constructing Perpendicular Lines
CA GEOM 16.0
TOP: 3-8 Example 3
construction | perpendicular lines
C
PTS: 1
DIF: L2
REF: 7-4 Similarity in Right Triangles
7-4.1 Using Similarity in Right Triangles
STA: CA GEOM 4.0| CA GEOM 5.0
7-4 Example 2
KEY: corollaries of the geometric mean | proportion
C
PTS: 1
DIF: L2
REF: 4-1 Congruent Figures
4-1.1 Congruent Figures
STA: CA GEOM 4.0| CA GEOM 5.0| CA GEOM 12.0
4-1 Example 1
KEY: congruent figures | corresponding parts | word problem
C
PTS: 1
DIF: L2
REF: 2-1 Conditional Statements
2-1.1 Conditional Statements
TOP: 2-1 Example 1
conditional statement | hypothesis | conclusion
C
PTS: 1
DIF: L2
REF: 1-3 Points, Lines, and Planes
1-3.2 Basic Postulates of Geometry
STA: CA GEOM 1.0
1-4 Example 3
KEY: plane | intersection of two planes
B
PTS: 1
DIF: L2
REF: 1-1 Patterns and Inductive Reasoning
1-1.1 Using Inductive Reasoning
STA: CA GEOM 1.0| CA GEOM 3.0
1-1 Example 3
KEY: conjecture | counterexample
6