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Using Rolle's Theorem To Inscribe An Ellipse
With Maximum Area In A Triangle
Jeff Morgan
Department of Mathematics
University of Houston
Definition: We say that a subset π of π
2 is an ellipse if and only
if there are points π and π in π
2 , and a scalar πΏ > |π β π|, so
that π is the set of points (π₯, π¦) in π
2 satisfying
|(π₯, π¦) β π| + |(π₯, π¦) β π| = πΏ
The points π and π in the definition are referred to as the foci
of the ellipse, and the center of the ellipse is given by π· =
1
(π
2
+ π) (the midpoint of the line segment ππ). Also, πΌ + π½ =
πΏ.
Theorem: The subset π in the π₯π¦ plane is an ellipse with center
π· = (π₯0 , π¦0 ) if and only if there are scalars π, π and π so that
π > 0, ππ β π 2 > 0, and π is the set of points (π₯, π¦) solving the
equation
π(π₯ β π₯0 )2 + π(π¦ β π¦0 )2 + 2π(π₯ β π₯0 )(π¦ β π¦0 ) = 1
The ElliptiGo 11R Bicycle β
http://www.elliptigo.com/
Magnified view.
Profile shot with graphic overlay.
Geogebra Demo
That was a big fail, but look at this demo?
Does it produce an ellipse?
Geogebra Demo β Perp Jig
Here is another.
Does it produce an ellipse?
Geogebra Demo β NonPerp Jig
OK. Enough⦠We need some facts.
Suppose π, π, π, π are real numbers and ππ β ππ β 0. If π is a
π π
subset of the π₯π¦ plane, then we define the action of (
) on π
π π
as the set
π’
{(π’, π£) | ( ) = (π
π£
π
π π₯
) ( ) for some (π₯, π¦) β π}
π π¦
1 β2
Exercise: Give the action of (
) on the line segment
1 1
connecting the points (β1,2) and (2, β3). Also, find the action
1 β2
of (
) on the midpoint of this line segment, and comment
1 1
on any observations.
π π
) on a line segment is a line
π π
segment, and the endpoints of the new line segment are the
1 β2
result of the action of (
) on the endpoints of the original
1 1
line segment. In addition, the midpoint of the original line
segment gets mapped to the midpoint of the new line segment.
In General: The action of (
1 β2
Exercise: Give the action of (
) on the triangle with
1 1
vertices (β1,2), (2, β3) and (4,1). Also, compare the areas.
In General: The action of (
π
π
π
) on a triangle π1 is a triangle
π
π2, and
area(π2 ) = |ππ β ππ |area(π1 )
1 β2
Exercise: Give the action of (
) on the set consisting of
1 1
the parabola π¦ = π₯ 2 and its tangent line at π₯ = 1. Graph the
results.
In General: The action of a matrix on a set preserves tangent
intersections of curves in the set.
π
More Fun Facts: The action of (
π
ellipse πΈ2 , and
π
) on an ellipse πΈ1 is an
π
area(πΈ2 ) = |ππ β ππ |area(πΈ1 )
A Simple Minimization Problem
Find a triangle of minimum area for which a given circle of is an
incircle.
Our Featured Maximization Problem!!
Find an ellipse of maximum area that is inscribed in a given
triangle.
Step 1: Note that maximizing the area of the ellipse is
equivalent to maximizing
area(ππππππ π)
area(π‘πππππππ)
Because the triangle is fixed.
Step 2: Believe there is an ellipse that has maximum area. Now,
take the given triangle and the ellipse (that you donβt have) and
π π
act a matrix (
) on the combination so that the ellipse (that
π π
you donβt have) becomes a circle. What is
area(ππππππ)
?
area(πππ€ π‘πππππππ)
Step 3: How does this help us solve our maximization problem?
Hint: See the earlier minimization problem.
Example: Find an ellipse of maximum area that is inscribed in
the triangle with vertices (β1,2), (2, β3) and (4,1).
A Much Simpler Solution
and Comments on Rolleβs Theorem
Example: Find an ellipse of maximum area that is inscribed in
the triangle with vertices (β1,2), (2, β3) and (4,1).
Step 1: Form the function
π (π§) = (π§ β (β1 + 2π ))(π§ β (2 β 3π ))(π§ β (4 + π ))
Step 2: Find the roots of πβ²(π§).
Step 3: Find the roots of πβ²β²(π§).
Step 4: How is this related to the solution?
Terms: Steiner Inellipse, Mardenβs Theorem