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QUANTITY PRECOMMITMENT AND BERTRAND COMPETITION YIELD COURNOT OUTCOMES: A CASE WITH PRODUCT DIFFERENTIATION: REPLY XIANGKANG YIN La Trobe University YEW-KWANG NG Monash University Since the publication of our paper (Yin and Ng, 1997), we have received some very helpful comments on the paper. In his recent comment, Schulz (2000) indicates that price reaction functions in the second-stage subgame of our model are discontinuous in certain circumstances so that Lemma 1 in the paper is incorrect. The editor, R. Damania, points out a mistake in the proof of Lemma 1 in his letter to us. We sincerely appreciate these criticisms, which are greatly helpful for us to re®ne our work. After a careful check, we ®nd that not only Lemma 1 is invalid but the price reaction function given in Theorem 1 also has to be revised. Fortunately, these errors do not affect the main results of the paper. The erratum to the previous mistakes is given below. Figure 1 below is borrowed from Schulz (2000), which can be obtained by applying demand functions (3)±(7) in our original paper. In the ®gure, line Ci (i 1, 2) plots the price pairs on which the demand for the ®rm i's product just hits its capacity while the demand for the ®rm j's product is not binding by either the upper or lower boundary; i.e. Ci : p1i ( p j ) (1 ÿ ã)á ã p j ÿ (1 ÿ ã2 )K i : (1) Z i in the ®gure (i 1, 2) is the line on which the demand for the ®rm i's product just becomes zero while the demand for the ®rm j's product hits neither the upper nor lower boundary; i.e. Z i : pi (1 ÿ ã)á ã p j : Or inversed, p2j ( pi ) [ pi ÿ (1 ÿ ã)á]=ã: (2) Axy gives the area, where the demand for ®rms 1 and 2's products has the characteristics of the ®rst and second subscripts, respectively. x and y in the subscript can be c, u, and z, indicating that the demand is constrained by the production capacity, unconstrained demand and zero demand, respectively. The equations below Axy show the demand functions in that area and the demand in Auu is q i á=(1 ã) ÿ ( pi ÿ ã p j )=(1 ÿ ã2 ). It should be noticed that Figure 1 presents a most comprehensive situation with nine areas, which requires small production capacities of both ®rms. When capacities are large, C1 and C2 move to left and down, respectively, so that some areas may disappear. An extreme is no capacity constraints and Figure 1 has only four areas: Auu, Auz, Azu, and Azz. With the help of Figure 1, we can revise the price reaction function as follows. # Blackwell Publishers Ltd, 108 Cowley Road, Oxford OX4 1JF, UK and 350 Main Street, Malden MA 02148, USA and the University of Adelaide and Flinders University of South Australia 2000. 114 AUSTRALIAN ECONOMIC PAPERS MARCH Figure 1. Theorem 19 (I) If 2Ki ãK j < á, the price reaction function is1 8 á ÿ K i ÿ ãK j p j 2 [0, á ÿ K j ÿ ãK i ] > > < 1 p j 2 (á ÿ K j ÿ ãK i , á ÿ ãK i ) Ri ( p j ) p i ( p j ) > > : 2 minf p i ( p j ), á=2g p j 2 [á ÿ ãK i , á] (II) If 2Ki ãK j . á, the price reaction function is 8 (á ÿ ãK j =2 p j 2 [0, á ÿ K j ÿ ãK i ] > > > > > > p j 2 (á ÿ K j ÿ ãK i , á ÿ ãK i )\ (á ÿ ãK j )=2 > > > > > > > ^p1 g) (á ÿ K j ÿ ãK i , minf~p1 , ^ > > < 1 3 p j 2 (á ÿ K j ÿ ãK i , á ÿ ãK i )\ Ri ( p j ) maxf p i ( p j ), p i ( p j )g > > > > ^p1 g, á ÿ ãK i , ) (minf~p1 , ^ > > > > > > > ^p1 g) p j 2 [á ÿ ãK i , á] \ (á ÿ ãK i , minf p1 , ^ (á ÿ ãK j )=2 > > > > : ^p1 g, á] minfmax[ p2 ( p j ), p3 ( p j )], á=2g p j 2 [á ÿ ãK i , á] \ (minf p1 , ^ i i 1 An interval (x, y) below should be understood as an empty set if x > y or both x and y are negative. If x , 0 but y . 0, the interval (x, y) should be understood as [0, y). # Blackwell Publishers Ltd/University of Adelaide and Flinders University of South Australia 2000. 2000 REPLY: QUANTITY PRECOMMITMENT AND BERTRAND COMPETITION 115 Proof. (I) Consider 2K 2 ãK 1 < á. p1 2 [0, á ÿ K 1 ÿ ãK 2 ] (i) For a given p1 , ®rm 2 chooses the optimal price p2 á ÿ K 2 ÿ ãK1 if q2 K 2 or p2 (á ÿ ãK 1 )=2 if q2 á ÿ p2 ãK 1 . The latter is the best price response iff it is in A cu . Since 2K 2 ãK 1 < á , á ÿ K 2 ÿ ãK1 > (á ÿ ãK 1 )=2, the price reaction function is á ÿ K 2 ÿ ãK1 . p1 2 (á ÿ K 1 ÿ ãK 2 , á ÿ ãK 2 ) (ii) There are two candidates of optimal price. One is to choose maximum price when the capacity is binding, which is the line C2 , i.e., p12 ( p1 ). The other is p32 ( p1 ) [(1 ÿ ã)á ã p1 ]=2, (3) 2 which maximises pro®ts for demand q2 á=(1 ã) ÿ ( p2 ÿ ã p1 )=(1 ÿ ã ). Recalling (1), p1 . á ÿ K 1 ÿ ãK 2 and 2K 2 ãK1 < á, we have p12 ( p1 ) [(1 ÿ ã)á ã p1 ]=2 [(1 ÿ ã)á ã p1 ÿ 2(1 ÿ ã2 )K 2 ]=2 . p32 ( p1 ) [á ÿ ãK 1 ÿ 2K 2 ã2 K2 ]=2 . p32 ( p1 ): Since p32 ( p1 ) is the best price response iff it falls in A uu , the above inequality implies that the price reaction function in this interval must be p12 ( p1 ). p1 2 [á ÿ ãK 2 , á] (iii) (I)±(ii) shows that p32 ( p1 ) , p12 ( p1 ) when p1 2 (á ÿ K 1 ÿ ãK 2 , á ÿ ãK 2 ). Thus, p32 ( p1 ) , á ÿ K 2 . Since p32 ( p1 ) is ¯atter than Z 1 , it is in A zc or A zu on this interval and cannot be the best price response. Noting that p2 á=2 maximises pro®t for demand q2 á ÿ p2, the best price response should be Z 1 if p2 á=2 is above Z 1 or p2 á=2 if it is below Z 1 ; i.e. minf p22 ( p1 ), á=2g. (II) Assuming 2K 2 ãK 1 . á (i) p1 2 [0, á ÿ K 1 ÿ ãK 2 ] As (I)±(i) shows the price reaction function on this interval is (á ÿ ãK 1 )=2. (ii) p1 2 (á ÿ K 1 ÿ ãK 2 , á ÿ ãK 2 ) In this interval, ®rm 2 has three possible price choices, i.e., p2 (á ÿ ãK1 )=2 or p12 ( p1 ) or p32 ( p1 ). Their corresponding pro®ts are, respectively (á ÿ ãK 1 )2 =4, K 2 p12 ( p1 ) K 2 [(1 ÿ ã)á ã p1 ÿ (1 ÿ ã2 )K 2 ], fá=(1 ã) ÿ [ p32 ( p1 ) ÿ ã p1 ]=(1 ÿ ã2 )g p32 ( p1 ) [(1 ÿ ã)á ã p1 ]2 =4(1 ÿ ã2 ) Let p~1 be the point where the ®rst pro®t ®gure is equal to the second, we have ~p1 [(á ÿ ãK 1 )2 =4K 2 (1 ÿ ã2 )K 2 ÿ (1 ÿ ã)á]=ã: (4) Thus, p2 (á ÿ ãK 1 )=2 leads to a larger pro®t than p12 ( p1 ) iff p1 , ~p1 . Let p^1 be the point where the ®rst pro®t ®gure is equal to the third, we have # Blackwell Publishers Ltd/University of Adelaide and Flinders University of South Australia 2000. 116 AUSTRALIAN ECONOMIC PAPERS MARCH ^p1 [(1 ÿ ã2 )1=2 (á ÿ ãK 1 ) ÿ (1 ÿ ã)á]=ã, (5) iff p1 , ^p1 . Let p1 be which implies that p2 (á ÿ ãK 1 )=2 brings more pro®t than the intersection of p12 ( p1 ) and p32 ( p1 ); i.e., p1 [2(1 ÿ ã2 )K1 ÿ (1 ÿ ã)á]=ã. Since p12 ( p1 ) is steeper than p32 ( p1 ), we can see that p32 ( p1 ) . p12 ( p1 ) on the left of p1 and p12 ( p1 ) > p32 ( p1 ) on the right. Moreover, for any p1, if p32 ( p1 ) falls in A uu , it results in more pro®t than p12 ( p1 ). It can also be shown that ~p1 . á ÿ K 1 ÿ ãK 2 and p32 (^p1 ) is below the line C1 (or its extension). Thus, the price reaction function shifts from p2 (á ÿ ãK1 )=2 to p32 ( p1 ) at p1 ^p1 if ^p1 , ~p1 and ^p1 2 (á ÿ K 1 ÿ ãK 2 , p2 ),2 and then switches to p12 ( p1 ) at = (áÿ K1 ÿ ãK 2 , p2 ), p1 p1 if p1 , á ÿ ãK 2 . But if ~p1 < ^p1 or ~p1 < á ÿ ãK 2 and ^p1 2 1 the price reaction function shifts from p2 (á ÿ ãK 1 )=2 to p2 ( p1 ) at p1 ~p1 and remains on it until the end of the interval. If ~p1 . á ÿ ãK 2 and ^p1 . á ÿ ãK 2 or ~p1 . á ÿ ãK 2 and ^p1 2 = (á ÿ K 1 ÿ ãK2 , p2 ), the reaction function remains on p2 (á ÿ ãK 1 )=2 for the whole interval. De®ne ( ^p1 ^p1 2 (á ÿ K 1 ÿ ãK 2 , p2 ) ^^p1 : (6) 1 otherwise p32 ( p1 ) The price reaction function in this interval is (á ÿ ãK 1 )=2 ^p1 g when p1 < minf~p1 , ^ ^p1 g maxf p22 ( p1 ), p32 ( p1 )g when p1 > minf~p1 , ^ : p1 2 [á ÿ ãK 2 , á] 2 Let p1 be determined by p2 ( p1 ) á=2 so that p1 (1 ÿ ã=2)á. As (I)±(iii) shows, the price reaction function cannot be p2 á=2 on the left of p1 . Hence, on the left of p1 there are three possible price choices, i.e., p2 (á ÿ ãK 1 )=2 or p22 ( p1 ) (i.e., line Z 1 ) or p32 ( p1 ). The pro®t of adopting p22 ( p1 ) is equal to fá ÿ [ p1 ÿ (1 ÿ ã)á]=ãg[ p1 ÿ (1 ÿ ã)á]=ã (á ÿ p1 )[ p1 ÿ (1 ÿ ã)á]=ã2 . Let p1 be the point where this pro®t is equal to (á ÿ ãK 1 )2 =4, i.e., p1 is the smaller solution of the equation (iii) p21 ÿ (2 ÿ ã)á p1 (1 ÿ ã)á2 ã2 (á ÿ ãK 1 ]=4 0: (7) 2 and is on the left of p1 and p2 ( p1 ) is It can be shown that the intersection of steeper than p32 ( p1 ). Then, if the price reaction function is p2 (á ÿ ãK1 )=2 at ^p1 , p1 . Afterwards, it switches to p1 á ÿ ãK 2 , it shifts to p32 ( p1 ) at the p1 ^^p1 when ^ ^p1 it shifts to p22 ( p1 ) at the intersection of p22 ( p1 ) and p32 ( p1 ) to reach p2 á=2. When p1 , ^ p22 ( p1 ) at p1 p1 and moves toward á=2. If the price reaction function at p1 á ÿ ãK 2 is p22 ( p1 ) or p32 ( p1 ), the development is similar, except that there is no shift. Thus, the price reaction function in this interval is p22 ( p1 ) (á ÿ ãK 1 )=2 p32 ( p1 ) ^p1 g when p1 < minf p1 , ^ ^p1 g: minfmax[ p22 ( p1 ), p32 ( p1 )], á=2g when p1 > minf p1 , ^ j With this new Theorem 19, Lemma 1 in our original paper should be changed to 2 The second condition is to ensure that p32 (^p1 ) falls in A uu . # Blackwell Publishers Ltd/University of Adelaide and Flinders University of South Australia 2000. 2000 REPLY: QUANTITY PRECOMMITMENT AND BERTRAND COMPETITION 117 Lemma 19. Firm i's price reaction function has one and only one discontinuity point at ^p j when 2K i ãK j . á and ãK j , á. Otherwise, it is conninuous. p j p j or ~p j or ^ Proof. Since maxf:, :g and minf:, :g are continuous operators, the discontinuity occurs at the point where the price reaction function shifts from pi (á ÿ ãK j )=2 to p1i ( p j ) or p2i ( p j ) or p3i ( p j ). But this can happens only once when 2K i ãK j . á and ãK j , á as Theorem 19 illustrated. j The bold lines in Figure 2 illustrates a typical price reaction curve of ®rm 2 when the ^p1 . If the discontinuity conditions in Lemma 19 are satis®ed. Thus, there is a shift at p1 ^ line p32 ( p1 ) is lower, the shift may occur at p1 ~p1 . p1 . A rare situation is that K 1 is very small but K 2 is suf®ciently large so that that the line C1 is long but C2 is short. In turn, the shift occurs on the right of p1 á ÿ ãK 2 . Because of the discontinuity of the price reaction curves, the price subgame in the second stage does not guarantee a unique pure strategy equilibrium as indicated in Theorem 2 in the original paper. However, this theorem is not a necessity for Theorem 3. Hence, Theorem 3 holds for the discontinuous price reaction functions but the proof should be revised. Theorem 3. In the equilibrium of the entire game, there are no idle capacities. Proof. Suppose ( p1e , p2e , K 1 , K 2 ) is the equilibrium of the entire game and at least one ®rm, say, ®rm 2, has certain idle production capacity. If the equilibrium leads to a pure price Figure 2. # Blackwell Publishers Ltd/University of Adelaide and Flinders University of South Australia 2000. 118 AUSTRALIAN ECONOMIC PAPERS MARCH strategy of ®rm 2, then ( p1e , p2e ) must be on the line p2 (á ÿ ãK 1 )=2 or p22 ( p1 ) or p32 ( p1 ) or p2 á=2. Hence, p2e is independent of ®rm 2's capacity and it has an incentive to reduce its idle capacity, which implies that ( p1e , p2e , K 1 , K 2 ) cannot be the equilibrium of the entire game. Consider now that ®rm 2 adopts a mixed price strategy in equilibrium. Since the mixed price strategy can only occur at the discontinuity point of the price reaction function, it ^p1 or p1 or ~p1. For the ®rst two cases, ( p1e , p2e ) is the intersection of the implies that p1e ^ ^ line C1 and p1 ^p1 or C1 and p1 p1 . Because C1 , ^^p1 and p1 are independent of K 2 (see (1), (5)±(7)), the price p2e is independent of ®rm 2's capacity. Turning to the case where p1e ~p1 . Figure 3 illustrates the most complicated situation in the sense that both ®rms have discontinuous price reaction functions, resulting in multiequilibria at E1 and E2 in the price subgame.3 Let us focus on E1 . The shift of price reaction curve at ~p1 from p2 (á ÿ ãK 1 )=2 to p12 ( p1 ) (i.e., line C2 ) implies that p12 (~p1 ) . p32 (~p1 ).4 Recalling (1), (3) and (4), this inequality gives (1 ÿ ã)á ã~p1 . 2(1 ÿ ã2 )K 2 and (á ÿ ãK 1 )2 =4K 2 . (1 ÿ ã2 )K 2 : (8) Since E1 is on C1 , we obtain from the reverse of p11 ( p2 ) that p2e [~p1 (1 ÿ ã2 )K 1 ÿ (1 ÿ ã)á]=ã: (9) The demand for good 2 along line C1 is q2e á ÿ p2e ÿ ãK 1 . Thus, the ®rm 2's equilibrium pro®t in the second-stage subgame is ð p2e q2e p2e (á ÿ p2e ÿ ãK 1 ), which gives @ð=@ K 2 (á ÿ 2 p2e ÿ ãK 1 )@ p2e =@ K 2 ãÿ2 (á ÿ 2 p2e ÿ ãK1 )[(1 ÿ ã2 ) ÿ (á ÿ ãK 1 )2 =4K 22 ] , 0: Figure 3. 3 In equilibrium E2 , the ®rm 2's capacity is binding. But actually, we can show that it is not the equilibrium of the entire game following the same arguments in the proof of E1 . If ®rm 1's price reaction function is continuous, then there exists only one equilibrium, E1 . The intersection of ~p1 and ~p2 cannot be an equilibrium point because it falls in the area A uu . 4 Otherwise, it shifts to p32 ( p1 ) before ~p1 . # Blackwell Publishers Ltd/University of Adelaide and Flinders University of South Australia 2000. 2000 REPLY: QUANTITY PRECOMMITMENT AND BERTRAND COMPETITION 119 To get the second equality, (4) and (9) are used. From (8) and q2e . á ÿ 2 p2e ÿ ãK 1, the inequality is immediate, which implies that ®rm 2 has an incentive to reduce the capacity j and ( p1e , p2e , K1 , K 2 ) is not an equilibrium. When the capacity constraints of both ®rms are binding, the price reaction function is Ri ( p j ) á ÿ K i ÿ ãK j , which leads to the price subgame equilibrium (11) in our original paper. Therefore, the main conclusions, Theorem 4 and Proposition 1 there, hold. RE F ERE N C E S Schulz, N. 2000, `A Comment on Yin, Xiangkang and Yew-Kwang Ng: Quantity Precommitment and Bertrand Competition Yield Cournot Outcomes: A Case with Product Differentiation' Australian Economic Papers, vol. 39, pp. 108±112. Yin, X. and Ng, Y.-K. 1997, `Quantity Precommitment and Bertrand Competition Yield Cournot Outcomes: A Case with Product Differentiation' Australian Economic Papers, vol. 36, pp. 14± 22. # Blackwell Publishers Ltd/University of Adelaide and Flinders University of South Australia 2000.