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GENERAL CHEMISTRY II QUIZ 1II February 20, 2007 INSTRUCTIONS: PRINT YOUR NAME ————> NAME __________________ . WORK 3 OF #1 THROUGH #4 (3 @ 25) SHOW YOUR WORK FOR PARTIAL CREDIT USE THE CORRECT NUMBER OF SIGNIFICANT FIGURES THE LAST PAGE is A PERIODIC TABLE R = 0.08206 lit•atm/(mol•K) R = 8.3145 J/mol•K 1 2 . . h = 6.626 X 10-34 J-s c = 2.9979 X 108 m/s 3 . 4 . J = (kg•m2)/s2 ΔHvap(H20) = 40.7 kJ/mol TOTAL(75) . 1. A solution of glucose (C6H12O6, molar mass = 180.2 g/mol) is prepared at 20 ºC. The solution has a mass % glucose of 23.0 % and a density of 1.093 g/mL. What is the Molarity (M) and molality (m) of this solution. (Hint assume 100 g of solution. 2. β-pinene (C10H16, molar mass = 136.3 g/mol) and α-terpinol (C10H18O, , molar mass = 154.2 g/mol) are two natural products that are added to consumer products to produce a clean pine scent. The vapor pressures of the pure compounds at 367 K are 100.3 torr for β-pinene and 9.80 torr for α-terpinol. Calculate the vapor pressure of a mixture of 10.0 g of each substance at 367 K. 3. A biochemical engineer isolates a bacterial gene fragment at 25 ºC and dissolves 10.0 mg in enough water to make 30.0 mL of solution. The osmotic pressure of the solution is 0.304 torr. Calculate the molar mass in g/mol of the gene fragment. (Watch the units!) 4. The freezing point of pure p-dichlorobenzene is 53.1 ºC. The Kf value is 7.10 ºC/m. A solution of 1.52 g of a new drug is dissolved in 10.0 g of p-dichlorobenzene and the freezing point of the mixture is 46.7 ºC. What is the molar mass (g/mol) of the drug. 1. A solution of glucose (C6H12O6, molar mass = 180.2 g/mol) is prepared at 20 ºC. The solution has a mass % glucose of 18.0 % and a density of 1.073 g/mL. What is the Molarity (M) and molality (m) of this solution. (Hint assume 100 g of solution. 2. β-pinene (C10H16, molar mass = 136.3 g/mol) and α-terpinol (C10H18O, , molar mass = 154.2 g/mol) are two natural products that are added to consumer products to produce a clean pine scent. The vapor pressures of the pure compounds at 367 K are 100.3 torr for β-pinene and 9.80 torr for α-terpinol. Calculate the vapor pressure of a mixture of 10.0 g of each substance at 367 K. 1. A solution of glucose (C6H12O6, molar mass = 180.2 g/mol) is prepared at 20 ºC. The solution has a mass % glucose of 36.0 % and a density of 1.153 g/mL. What is the Molarity (M) and molality (m) of this solution. (Hint assume 100 g of solution. 2. β-pinene (C10H16, molar mass = 136.3 g/mol) and α-terpinol (C10H18O, , molar mass = 154.2 g/mol) are two natural products that are added to consumer products to produce a clean pine scent. The vapor pressures of the pure compounds at 367 K are 100.3 torr for β-pinene and 9.80 torr for α-terpinol. Calculate the vapor pressure of a mixture of 10.0 g of each substance at 367 K. 1. A solution of glucose (C6H12O6, molar mass = 180.2 g/mol) is prepared at 20 ºC. The solution has a mass % glucose of 44.0 % and a density of 1.192 g/mL. What is the Molarity (M) and molality (m) of this solution. (Hint assume 100 g of solution. 2. β-pinene (C10H16, molar mass = 136.3 g/mol) and α-terpinol (C10H18O, , molar mass = 154.2 g/mol) are two natural products that are added to consumer products to produce a clean pine scent. The vapor pressures of the pure compounds at 367 K are 100.3 torr for β-pinene and 9.80 torr for α-terpinol. Calculate the vapor pressure of a mixture of 10.0 g of each substance at 367 K. GENERAL CHEMISTRY II QUIZ 1II February 20, 2007 INSTRUCTIONS: PRINT YOUR NAME ————> NAME __________________ . WORK 3 OF #1 THROUGH #4 (3 @ 25) SHOW YOUR WORK FOR PARTIAL CREDIT USE THE CORRECT NUMBER OF SIGNIFICANT FIGURES THE LAST TWO PAGES ARE A PERIODIC TABLE AND A SCRATCH SHEET R = 0.08206 lit•atm/(mol•K) R = 8.3145 J/mol•K . h = 6.626 X 10-34 J-s c = 2.9979 X 108 m/s J = (kg•m2)/s2 ΔHvap(H20) = 40.7 kJ/mol 1 . 2 3 4 TOTAL(75) . . . 1. A solution of glucose (C6H12O6, molar mass = 180.2 g/mol) is prepared at 20 ºC. The solution has a mass % glucose of 23.0 % and a density of 1.093 g/mL. What is the Molarity (M) and molality (m) of this solution. (Hint assume 100 g of solution. 2. β-pinene (C10H16, molar mass = 136.3 g/mol) and α-terpinol (C10H18O, , molar mass = 154.2 g/mol) are two natural products that are added to consumer products to produce a clean pine scent. The vapor pressures of the pure compounds at 367 K are 100.3 torr for β-pinene and 9.80 torr for α-terpinol. Calculate the vapor pressure of a mixture of 10.0 g of each substance at 367 K. 3. A biochemical engineer isolates a bacterial gene fragment at 25 ºC and dissolves 10.0 mg in enough water to make 30.0 mL of solution. The osmotic pressure of the solution is 0.304 torr. Calculate the molar mass in g/mol of the gene fragment. (Watch the units!) 4. The freezing point of pure p-dichlorobenzene is 53.1 ºC. The Kf value is 7.10 ºC/m. A solution of 1.52 g of a new drug is dissolved in 10.0 g of p-dichlorobenzene and the freezing point of the mixture is 46.7 ºC. What is the molar mass (g/mol) of the drug. 4. The freezing point of pure p-dichlorobenzene is 53.1 ºC. The Kf value is 7.10 ºC/m. A solution of 1.52 g of a new drug is dissolved in 10.0 g of p-dichlorobenzene and the freezing point of the mixture is 46.7 ºC. What is the molar mass (g/mol) of the drug.