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GENERAL CHEMISTRY II
QUIZ 1II
February 20, 2007
INSTRUCTIONS:
PRINT YOUR NAME ————>
NAME
__________________
.
WORK 3 OF #1 THROUGH #4 (3 @ 25)
SHOW YOUR WORK FOR PARTIAL CREDIT
USE THE CORRECT NUMBER OF SIGNIFICANT FIGURES
THE LAST PAGE is A PERIODIC TABLE
R = 0.08206 lit•atm/(mol•K)
R = 8.3145 J/mol•K
1
2
.
.
h = 6.626 X 10-34 J-s
c = 2.9979 X 108 m/s
3
.
4
.
J = (kg•m2)/s2
ΔHvap(H20) = 40.7 kJ/mol
TOTAL(75)
.
1. A solution of glucose (C6H12O6, molar mass = 180.2 g/mol) is prepared at 20 ºC. The
solution has a mass % glucose of 23.0 % and a density of 1.093 g/mL. What is the
Molarity (M) and molality (m) of this solution. (Hint assume 100 g of solution.
2. β-pinene (C10H16, molar mass = 136.3 g/mol) and α-terpinol (C10H18O, , molar mass =
154.2 g/mol) are two natural products that are added to consumer products to produce a
clean pine scent. The vapor pressures of the pure compounds at 367 K are 100.3 torr for
β-pinene and 9.80 torr for α-terpinol. Calculate the vapor pressure of a mixture of 10.0
g of each substance at 367 K.
3. A biochemical engineer isolates a bacterial gene fragment at 25 ºC and dissolves 10.0
mg in enough water to make 30.0 mL of solution. The osmotic pressure of the solution is
0.304 torr. Calculate the molar mass in g/mol of the gene fragment. (Watch the units!)
4. The freezing point of pure p-dichlorobenzene is 53.1 ºC. The Kf value is 7.10 ºC/m. A
solution of 1.52 g of a new drug is dissolved in 10.0 g of p-dichlorobenzene and the freezing
point of the mixture is 46.7 ºC. What is the molar mass (g/mol) of the drug.
1. A solution of glucose (C6H12O6, molar mass = 180.2 g/mol) is prepared at 20 ºC. The
solution has a mass % glucose of 18.0 % and a density of 1.073 g/mL. What is the
Molarity (M) and molality (m) of this solution. (Hint assume 100 g of solution.
2. β-pinene (C10H16, molar mass = 136.3 g/mol) and α-terpinol (C10H18O, , molar mass =
154.2 g/mol) are two natural products that are added to consumer products to produce a
clean pine scent. The vapor pressures of the pure compounds at 367 K are 100.3 torr for
β-pinene and 9.80 torr for α-terpinol. Calculate the vapor pressure of a mixture of 10.0
g of each substance at 367 K.
1. A solution of glucose (C6H12O6, molar mass = 180.2 g/mol) is prepared at 20 ºC. The
solution has a mass % glucose of 36.0 % and a density of 1.153 g/mL. What is the
Molarity (M) and molality (m) of this solution. (Hint assume 100 g of solution.
2. β-pinene (C10H16, molar mass = 136.3 g/mol) and α-terpinol (C10H18O, , molar mass =
154.2 g/mol) are two natural products that are added to consumer products to produce a
clean pine scent. The vapor pressures of the pure compounds at 367 K are 100.3 torr for
β-pinene and 9.80 torr for α-terpinol. Calculate the vapor pressure of a mixture of 10.0
g of each substance at 367 K.
1. A solution of glucose (C6H12O6, molar mass = 180.2 g/mol) is prepared at 20 ºC. The
solution has a mass % glucose of 44.0 % and a density of 1.192 g/mL. What is the
Molarity (M) and molality (m) of this solution. (Hint assume 100 g of solution.
2. β-pinene (C10H16, molar mass = 136.3 g/mol) and α-terpinol (C10H18O, , molar mass =
154.2 g/mol) are two natural products that are added to consumer products to produce a
clean pine scent. The vapor pressures of the pure compounds at 367 K are 100.3 torr for
β-pinene and 9.80 torr for α-terpinol. Calculate the vapor pressure of a mixture of 10.0
g of each substance at 367 K.
GENERAL CHEMISTRY II
QUIZ 1II
February 20, 2007
INSTRUCTIONS:
PRINT YOUR NAME ————> NAME
__________________ .
WORK 3 OF #1 THROUGH #4 (3 @ 25)
SHOW YOUR WORK FOR PARTIAL CREDIT
USE THE CORRECT NUMBER OF SIGNIFICANT
FIGURES
THE LAST TWO PAGES ARE A PERIODIC TABLE AND
A SCRATCH SHEET
R = 0.08206 lit•atm/(mol•K)
R = 8.3145 J/mol•K
.
h = 6.626 X 10-34 J-s
c = 2.9979 X 108 m/s
J = (kg•m2)/s2
ΔHvap(H20) = 40.7 kJ/mol
1
.
2
3
4
TOTAL(75)
.
.
.
1. A solution of glucose (C6H12O6, molar mass = 180.2 g/mol) is
prepared at 20 ºC. The solution has a mass % glucose of 23.0 %
and a density of 1.093 g/mL. What is the Molarity (M) and
molality (m) of this solution. (Hint assume 100 g of solution.
2. β-pinene (C10H16, molar mass = 136.3 g/mol) and α-terpinol
(C10H18O, , molar mass = 154.2 g/mol) are two natural products
that are added to consumer products to produce a clean pine scent.
The vapor pressures of the pure compounds at 367 K are 100.3 torr
for β-pinene and 9.80 torr for α-terpinol. Calculate the vapor
pressure of a mixture of 10.0 g of each substance at 367 K.
3. A biochemical engineer isolates a bacterial gene fragment at 25
ºC and dissolves 10.0 mg in enough water to make 30.0 mL of
solution. The osmotic pressure of the solution is 0.304 torr.
Calculate the molar mass in g/mol of the gene fragment. (Watch
the units!)
4. The freezing point of pure p-dichlorobenzene is 53.1 ºC. The Kf value is 7.10 ºC/m. A
solution of 1.52 g of a new drug is dissolved in 10.0 g of p-dichlorobenzene and the freezing
point of the mixture is 46.7 ºC. What is the molar mass (g/mol) of the drug.
4. The freezing point of pure p-dichlorobenzene is 53.1 ºC. The Kf
value is 7.10 ºC/m. A solution of 1.52 g of a new drug is dissolved
in 10.0 g of p-dichlorobenzene and the freezing point of the mixture
is 46.7 ºC. What is the molar mass (g/mol) of the drug.