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Math 1300 3.8 Word Problem Name: Solutions On roads on steep hills, you sometimes see a sign that reads “Steep hill: 20% Grade”. The grade of a hill is the slope (rise/run) written as a percentage, or, equivalently, as the number of feet the hill rises vertically per hundred feet horizontally. (a) Let x be the grade of a hill. Explain why the angle, θ degrees, that a hill makes with the horizontal is given by x 180 θ= arctan π 100 Since tangent equals opposite over adjacent, we can see from thepicture (which was on the x x handout) that tan(θ) = if θ is in radians, giving θ = arctan . Since we need θ in 100 100 180 to get the formula proposed above. degrees, we need to multiply by the conversion factor π dθ dθ in terms of x. Then find for grades of x = 0%, 10%, and 20%. dx dx We use the chain rule: (b) Find an equation for dθ 180 1 1 9 1 = · = · · dx π 1 + x 2 100 5π 1 + x 2 100 100 Now we plug in, using a calculator, to get dθ dθ dθ |x=0 = 0.5729578 |x=10 = 0.56728495 |x=20 = 0.55092096 dx dx dx dθ (c) You can estimate θ at x = 20% simply by multiplying at x = 0 by 20. How could you dx write this estimate as a linear approximation? How much error is there in the value of θ found by using this method rather than by using the exact formula that involves the inverse tangent function? The tangent line approximation to θ near x = 0 is θ(x) ≈ 0.5729578x The error is E(x) = x 180 arctan − 0.5729578x π 100 The error when x = 20 is E(20) = 180 arctan π 20 100 − 0.5729578(20) = −0.1492234 degrees The error when x = 100 is 180 E(100) = arctan π 100 100 − 0.5729578(100) = −12.29578 degrees Math 1300 3.8 Word Problem Name: Solutions (d) A rule of thumb you can use to estimate the number of degrees a hill makes with the horizontal is to divide the grade by 2. Where in your work for part (c) did you divide by approximately 2? When you use this method to determine the number of degrees for grades of 20% and 100%, how much error is there in the number? We divided by approximately 2 when we multiplied x by 0.5729578. Using this rule of thumb at x = 10, θ(20) ≈ 20/2 = 10. This gives an error of 180 20 − 10 = 1.3099 degrees arctan π 100 . When x = 100, this “rule of thumb” gives an error of exactly −5 degrees.