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1 Kuta Software - Infinite Calculus Differentiation - Inverse Trigonometric Functions 1) y = cos −1 −5x 3 2) y = sin −1 −2x 2 3) y = tan −1 2x 4 5) y = (sin −1 5x 2 ) 3 7) y = (cos −1 4x 2 ) 6) y = sin −1 (3x 5 + 1) 3 2 8) y = cos −1 (−2x 3 − 3) 3 Derivatives of inverse function – PROBLEMS 𝑓𝑓 (𝑔𝑔 (𝑥𝑥 )) = 𝑥𝑥 . 𝑓𝑓′(𝑔𝑔(𝑥𝑥))𝑔𝑔′(𝑥𝑥) = 1 𝑔𝑔′ (𝑥𝑥) = 1 𝑓𝑓′(𝑔𝑔(𝑥𝑥)) The beauty of this formula is that we don’t need to actually determine 𝑔𝑔(𝑥𝑥) to find the value of the derivative at a point. We simply use the reflection property of inverse function: Derivative of the inverse function at a point is the reciprocal of the derivative of the function at the corresponding point. Slope of the line tangent to 𝒇𝒇−𝟏 at 𝒙𝒙 = 𝒃𝒃 is the reciprocal of the slope of 𝒇𝒇 at 𝒙𝒙 = 𝒂𝒂. 1. Find tangent line at point (4, 2) of the graph of f -1 if f(x) = x3 + 2x – 8 2. Find the equation of the tangent line to the inverse at the given point. a. f(x) = x3 + 7x +2 @ (10, 1) b. f(x) = x5 + 3x3 + 7x +2 @ (13, 1) c. f(x) = e-2x – 9x3 + 4 d. f(x) = x7 + 2x + 9 e. f(x) = x5/3 𝑒 𝑥 𝑓𝑓. 𝑓𝑓(𝑥𝑥) = 2 −𝑒 −3𝑥 𝑥𝑥 2 + 1 g. f(x) = 7x + sin (2x) @ (5, 0) @ (12, 1) @ (e, 1) @ (−1, 0) @ (0,0) 2 h. f(x) = x3 + 8x + cos (3x) @ (1,0) i. f(x) = 10x + (arc tanx)2 @ (0,0) j. f(x) = 7x3 + (ln x)3 @ (7, 1) 3. A function 𝑓𝑓 and its derivative take on the values shown in the table. If 𝑔𝑔 is the inverse of 𝑓𝑓, find 𝑔𝑔′ (6). x 2 6 f(x) 6 8 f’(x) 1/3 3/2 4. Let y = f(x) = x3 + x + x – 2, and let g be the inverse function. Evaluate g’(0).