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Chapter 6 Work, Energy, and Power Copyright © 2010 Pearson Education, Inc. What Is Physics All About? • Matter • Energy • Force Copyright © 2010 Pearson Education, Inc. Work Done by a Constant Force The definition of work, when the force is parallel to the displacement: W = Fs SI unit: newton-meter (N·m) = joule, J s Copyright © 2010 Pearson Education, Inc. Work Done by a Constant Force If the force is at an angle to the displacement: W = (F cos θ)s s Copyright © 2010 Pearson Education, Inc. Sally pulls a car with a rope. Exerting a force of 150N, she accelerates the car from rest to a speed of 25.0 km/hr in 300m. The angle of the rope is 15.00. The force of kinetic friction is 90.0N. What is the mass of the car? What is the work done by Sally? Fy F = 150N θ = 15° Fx s = 300m Copyright © 2010 Pearson Education, Inc. • Solution vi = 0m/s vf = 6.944m/s s = 300m θ = 15.00 F = 150N Ff = 90.0N vf2 = vi2 + 2as 6.9442 = 0 + 2a(300) a = 0.0804 m/s Fnet = ma Fx – Ff = ma 150cos15.0° – 90.0 = m(0.0804) m = 683 kg WSally = (Fx + Ff)s WSally = (150cos15° + 90.0)(300) WSally = 7.05 X 104 J Copyright © 2010 Pearson Education, Inc. Work Done by a Constant Force The work done may be positive, zero, or negative, depending on the angle between the force and the displacement: s Copyright © 2010 Pearson Education, Inc. s s Positive work accelerates an object Copyright © 2010 Pearson Education, Inc. Negative work decelerates an object Copyright © 2010 Pearson Education, Inc. Kinetic Energy By definition, KE = ½mv2 The units of KE are the same as the units of work: joules Copyright © 2010 Pearson Education, Inc. How is Energy Related to Work? W = Fs F = ma W = mas vf2 = vi2 + 2as vf2 – vi2 = 2as ½(vf2 – vi2) = as W = m ½(vf2 – vi2) W = ½mvf2 – ½mvi2 Work-Kinetic Energy Theorem: The work done on an object is equal to its change in kinetic energy. Copyright © 2010 Pearson Education, Inc. Power Power is a measure of the rate at which work is done: SI unit: J/s = watt 1 horsepower = 1 hp = 746 watts Copyright © 2010 Pearson Education, Inc. Power If an object is moving at a constant speed against friction, gravity, and air resistance, the power exerted by the driving force can be written: s Copyright © 2010 Pearson Education, Inc. s • Problem – Jon pulls a sled along a snowy path using a rope that makes a 45.0° angle with the ground. Jon pulls with a force of 42.3N. The sled moves at 5.33 m/s. Assuming no friction, what power does Jon produce? Copyright © 2010 Pearson Education, Inc. • Solution F = 42.3N v = 5.33s θ = 45.00 Fs P= = F cosθ v = (42.3)(cos 45.0°)(5.33) = 159w t Copyright © 2010 Pearson Education, Inc. Potential Energy Kinetic energy (KE) is the energy of motion; potential energy (PE) is stored energy. A pine cone about to fall from a certain height has PE. As it falls, the PE is released as KE. A spring that is stretched to a certain distance has PE. As it unstretches, the PE is released as KE. Copyright © 2010 Pearson Education, Inc. Gravitational Potential Energy If we pick up a ball from one shelf and put it on a higher shelf, we have done work on the ball. There is no change in kinetic energy, but there is a change in potential energy, or PE. Like KE, it is measured in joules. PEG = mgh W = mg(hf – hi) hf – hi W = mghf – mghi = PEGf – PEGi hf hi Copyright © 2010 Pearson Education, Inc. Work-Energy Theorem: The total work done on an object is equal to its change in kinetic energy plus its change in potential energy plus any work done to overcome friction. Copyright © 2010 Pearson Education, Inc. Conservation of Mechanical Energy Definition of mechanical energy: Em = KE + PEG The mechanical energy of a system is conserved. KEf + PEGf = KEi + PEGi “Energy Skate Park” Copyright © 2010 Pearson Education, Inc. Conservation of Mechanical Energy Energy conservation can be used to solve many problems involving velocity and acceleration. Example: If I drop a 20.0 kg mass from a height of 50.0 meters, at what speed will it hit the ground? KEf + PEGf = KEi + PEGi KEf + 0 = 0 + PEGi ½mvf2 = mghi ½vf2 = ghi ½vf2 = (9.81)(50.0) v = 31.3 m/s Copyright © 2010 Pearson Education, Inc. Conservation of Mechanical Energy Example: If I shoot a 10.0 g bullet straight up into the air from a height of 2.30 meters with a velocity of 200 m/s, how high will it go? KEf + PEGf = KEi + PEGi 0 + mghf = ½mvi2 + mghi (0.01)(9.81)hf = ½(0.01)(200)2 + (0.01)(9.81)(2.30) hf = 2.04 km Copyright © 2010 Pearson Education, Inc. Homework pp. 203-207 23, 31, 49, 61, 75, 93, 95 Chapter 5 Review: pp. 167-169 9, 23, 41, 62 (avg. distance from earth to sun is 149,597,890 km, vt of earth is 107,300 km/h, mass of earth is 5.98 X 1024 kg) Chapter 4 Review: pp. 131-138 33, 41, 128 Copyright © 2010 Pearson Education, Inc.