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The back emf in a d.c motor
To understand this page properly
you will first need to check the
section on electromagnetic
induction.
C
 59V
 = 60V
B
> 60V
 = 5V
A
Figure 1
D
As soon as the coil in the motor starts rotating, a back e.m.f. will be induced in it due to the flux
that it cuts, and this will tend to reduce the current through it.
Let the supply e.m.f. be E, the back e.m.f. be , the resistance of the coil R and the current
through the coil I. Then
I = [E – ]/R since e is proportional to the angular speed () the greater  the smaller I.
For practical motors with E = 100 V, the back e.m.f. may be great as 95 V!
The resistance of the coil R is usually small (less than 1 ) and therefore when it is at rest a
large current may flow through it. When the coil speeds up this is reduced, since the back e.m.f.
is proportional to the rate of rotation of the coil. The starting current can be as large as 1000 A,
and a protective resistor must be incorporated in series with the coil during starting. This can be
removed when the motor is running. This is why a d.c. motor that is running should never be
stopped with the supply connected. If this is done the back e.m.f. will fall to zero, the current will
become very large and the coil may burn out.
The diagram shows an electric car run by a 60 V battery going over a hill. It should help to
explain what happens when the motor runs at different speeds. As the car climbs the hill AB on
the left the motor is running slowly, the back e.m.f. is therefore low (say 5 V) and this means
that a large current flows through the motor, giving a large torque. Chemical energy from the
battery is converted to potential energy of the car.
The car now goes up section BC. The slope is much shallower, the motor speeds up and so the
back e.m.f. rises to say 59 V. The current through the motor is therefore low.
The car now descends the section CD. The speed increases so that the back e.m.f. rises to 60
V, and energy is supplied to just overcome friction. Further down the hill, however, the car is
moving faster and the back e.m.f. is greater than 60 V and so the motor acts as a dynamo,
storing up energy in the battery. The current flowing produces a torque which tends to oppose
the motion and so acts as a brake.
As long as electromagnets are used for the field, a d.c. motor will run on a.c., although very
inefficiently owing to the large self-inductance of its coils.
Student investigation
The following experiment is designed to study the
effect of various loads on the speed of an electric
motor and hence on the back e.m.f. produced.
Set up the motor as shown in Figure 2, with a
variable tension friction brake around a wheel on the
motor axle.
Using a very small armature voltage (say 0.5 V, not
enough to rotate the motor) measure the resistance
of the armature coils.
Set the output of the power supply to a known value
(E) near the maximum required for the motor, and
then connect the motor to it. Measure the tension in
the friction brake, the voltage across the motor and
the current through it.
Hence calculate the back e.m.f. Measure the speed
of rotation of the motor with a stroboscope.
Vary the tension in the friction brake and record a
set of values for the above variables. Plot graphs of
both the current in the motor and the back e.rn.f
against the angular velocity and tension.
Spot for stroboscope
measurement
motor
Figure 2
friction brake
newton meter
2