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Transcript
5 ICP-A
1. A 65-kg merry-go-round worker stands on the ride’s platform 5.2-m from the center. If his speed as he goes
around the circle is 6.2-m/s, what must be the coefficient of friction between his feet and the platform be?
(start by finding Fc and FN).
Fc = Ff and Fg= Weight = m*g =Fn
0.75
2. Let us assume that the orbit of the earth around the sun is circular. If the radius of this orbit is 150,000,000km and has a period of 365.25 days;
a) Find the tangential velocity of the earth (in m/s).
Convert km to m and days to seconds
29,850-m/s
b) Find the centripetal acceleration of the earth towards the sun.
a = vt2/r
0.006-m/s2
c) If the mass of the earth is 5.97 × 1024 kilograms, find the magnitude of the gravitational force
keeping the earth going in the circle.
Don’t use Newton’s Law of Universal Gravitation
Fg = Fc = m*acx
3.55 1022 N
3. An 8-kg can of paint sits 0.5 meters
from the axis of rotation. To balance
the can of paint, what force must be
applied 1.65-m from the axis?
Force of the paint can is m*g
Set the two torques equal to one
another.
24-N
5 ICP-B
1. A 75-kg merry-go-round worker stands on the ride’s platform 4.8-m from the center. If his speed as he goes
around the circle is 6.2-m/s, what must be the coefficient of friction between his feet and the platform be?
(start by finding Fc and FN).
Fc = Ff and Fg= Weight = m*g =Fn
0.82
2. Let us assume that the orbit of the earth around the sun is circular. If the radius of this orbit is 150,000,000km and has a period of 365.25 days;
Convert km to m and days to seconds
29,850-m/s
b) Find the centripetal acceleration of the earth towards the sun.
a = vt2/r
0.006-m/s2
c) If the mass of the earth is 5.97 × 1024 kilograms, find the magnitude of the gravitational force
keeping the earth going in the circle.
Don’t use Newton’s Law of Universal Gravitation
Fg = Fc = m*acx
3.55 1022 N
3. A 12-kg can of paint sits 0.6 meters from the axis of rotation. To balance the can of paint, what force must
be applied 1.65-m from the axis?
Force of the paint can is m*g
Set the two torques equal to one
another.
42.8-N
5 ICP-C
1. A 85-kg merry-go-round worker stands on the ride’s platform 4.4-m from the center. If his speed as he goes
around the circle is 6.2-m/s, what must be the coefficient of friction between his feet and the platform be?
(start by finding Fc and FN).
Fc = Ff and Fg= Weight = m*g =Fn
0.89
2. Let us assume that the orbit of the earth around the sun is circular. If the radius of this orbit is 150,000,000km and has a period of 365.25 days;
Convert km to m and days to seconds
29,850-m/s
b) Find the centripetal acceleration of the earth towards the sun.
a = vt2/r
0.006-m/s2
c) If the mass of the earth is 5.97 × 1024 kilograms, find the magnitude of the gravitational force
keeping the earth going in the circle.
Don’t use Newton’s Law of Universal Gravitation
Fg = Fc = m*acx
3.55 1022 N
3. A 10-kg can of paint sits 0.7 meters from the axis of rotation. To balance the can of paint, what force must
be applied 1.65-m from the axis?
Force of the paint can is m*g
Set the two torques equal to one
another.
41.6-N
5 ICP-D
1. A 95-kg merry-go-round worker stands on the ride’s platform 4.2-m from the center. If his speed as he goes
around the circle is 6.2-m/s, what must be the coefficient of friction between his feet and the platform be?
(start by finding Fc and FN).
Fc = Ff and Fg= Weight = m*g =Fn
0.93
2. Let us assume that the orbit of the earth around the sun is circular. If the radius of this orbit is 150,000,000km and has a period of 365.25 days;
Convert km to m and days to seconds
29,850-m/s
b) Find the centripetal acceleration of the earth towards the sun.
a = vt2/r
0.006-m/s2
c) If the mass of the earth is 5.97 × 1024 kilograms, find the magnitude of the gravitational force
keeping the earth going in the circle.
Don’t use Newton’s Law of Universal Gravitation
Fg = Fc = m*acx
3.55 1022 N
3. An 11-kg can of paint sits 0.75
meters from the axis of rotation. To
balance the can of paint, what force
must be applied 1.65-m from the
axis?
Force of the paint can is m*g
Set the two torques equal to one another.
49-N