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Summer 2006 Conservation of Mechanical Energy (Projectile Gun) Name Section Theory In an isolated system subject only to a conservative force, it can be shown that the mechanical energy of the system remains constant. In other words, the sum of the kinetic energy K and potential energy U is constant for the system. K + U = E (constant ) (1) This force could be gravitational, elastic, or electromagnetic in nature. In any case, the total energy of the system will remain constant. As you can see from Equation 1, as one form of energy decreases, the other must increase by the same amount. In this experiment, we will examine the energy of a sphere projected vertically; i.e., subject only to the gravitational force. We define the potential energy at the release point to be 0 so that the sphere has only a kinetic energy dependent upon its initial velocity. As the sphere rises, its potential energy increases as its kinetic energy decreases. Apparatus Pasco Mini Launcher, Clamp, Steel sphere, Paper, Carbon paper, Tape, Plumb bob, Meterstick, Triple-beam balance. Procedure 1. Determine the initial velocity of the sphere. Clamp the gun apparatus to the side of the table and set the gun to shoot horizontally as shown in the figure. 2. Tape a sheet of paper on the floor under the gun so that the release point of the sphere (shown on the side of the gun) can be transferred to the floor. The plumb bob will help with this. 3. Fire a test shot from the gun at medium range and note where the sphere strikes the floor. Tape another sheet of paper at this location and place a sheet of carbon paper on top. 4. Fire 10 shots from the gun onto the target paper. 5. Remove the carbon paper and measure the horizontal distance x each of the shots traveled form the point you marked on the floor under the gun. Record these values in Table 1 and calculate the average distance and average deviation in distance. 6. Measure the vertical distance y the sphere (freely) falls from the gun to the floor. Use this distance to calculate how long the sphere is in the air. y= 1 2 gt 2 (2) 7. Each shot was in the air the same amount of time. Since the horizontal distance varied, this means that there was some variation in the initial velocity of the sphere. Calculate three initial velocities – one from the average distance, one from the minimum distance (average - deviation), and one from the maximum distance (average + deviation). There is no force on the sphere in the horizontal direction, so the horizontal velocity (also the initial velocity of the sphere since it was fired horizontally) is constant. 151 Page 1 of 5 Summer 2006 v= x t (3) Re-record these velocities as (average ± deviation). Finally, express this deviation as a percentage of the mean. 8. Measure the mass of the sphere with the triple-beam balance. Calculate the kinetic energy of the sphere as it leaves the gun (three values). K= 1 mv 2 2 (4) Re-record this kinetic energy as (average ± deviation), and express the deviation as a percentage of the mean. 9. Assuming that mechanical energy is conserved, calculate the expected vertical distance h the sphere will travel when shot vertically from the gun as shown in the figure (three values). U = mgh (5) You now have a range of vertical distances the sphere could travel, based on the uncertainty in the initial velocity. 10. These calculated distances are from the release point, but you need to know how high off the floor it will rise. Measure the distance from the release point to the floor and add this to your high and low distances. Mark the high and low expected vertical distances you determined on the 2m meterstick with some tape. 11. Hold the meterstick vertically next to the gun and fire the sphere straight up. Watch and see if the sphere ascends to within this range. 151 Page 2 of 5 Summer 2006 Table 1 Data and Calculations Horizontal Distances x (m) Average distance (m) ____________________ Average deviation (m) ____________________ Freefall distance y (m) ____________________ Freefall time t (s) ____________________ Mass of sphere (kg) ____________________ Minimum velocity (m/s) ____________________ Minimum kinetic energy (J) ____________________ Average velocity (m/s) ____________________ Average kinetic energy (J) ____________________ Maximum velocity (m/s) ____________________ Maximum kinetic energy (J) ____________________ Velocity Kinetic Energy ( _______________ ± __________ ) m/s ( _______________ ± __________ ) J Deviation as percentage of mean ____________ Deviation as percentage of mean ____________ Distance from release point to floor (m) ____________________ Minimum height from gun (m) ____________________ Maximum height from gun (m) ____________________ Minimum height from floor (m) ____________________ Maximum height from floor (m) ____________________ Did your vertical shot fall within the predicted range? _______________ 151 Page 3 of 5 Summer 2006 Questions 1. You calculated a deviation as a percentage of the mean for both initial velocity and kinetic energy. How do these percentages compare? Why do you think this is so? 2. Consider the gun – sphere system. In order to shoot the sphere, you cock the gun by compressing the spring inside. If mechanical energy is conserved for this system, what do you think the elastic potential energy is in the spring when the gun is set to shoot on medium range? Give a numerical value. 3. We defined the potential energy of the sphere at the point of release to be 0. Was this necessary? Could we have taken the point of 0 potential to be the floor under the gun? Would mechanical energy still be conserved in this case? 151 Page 4 of 5 Summer 2006 Pre-Lab: Conservation of Mechanical Energy (Projectile Gun) Name Section 1. What is the conservation of mechanical energy? 2. Calculate the average and average deviation in the following values. Express your answer in the form ( average ± deviation ) units Finally, express the deviation as a percentage of the mean (a single percentage value). Distance (cm) 68.9 72.1 72.3 68.3 70.5 71.0 69.4 71.9 69.3 70.7 151 Page 5 of 5