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Math 10
Absolute Value Worksheet - Answers
1. State the transformations, mapping rule and new table of values. State the vertex and
equation of the axis of symmetry and then, draw the graph.
a) y + 3 = |x – 1|
Transformations: VT = -3, HT = 1
Mapping Rule:
Vertex:
(x, y)  (x + 1, y – 3)
(1, -3)
Table of Values:
Axis: x = 1
x
-2
-1
0
1
2
3
4
y
0
-1
-2
-3
-2
-1
0
b) -(y – 1) = |x +3|
Transformations: VT = 1, HT = -3, Rx
Mapping Rule:
Vertex:
(x, y)  (x - 3, -y + 1)
(-3, 1)
Table of Values:
Axis: x = -3
x
-6
-5
-4
-3
-2
-1
0
y
-2
-1
0
1
0
-1
-2
c) 2(y + 1) = |x|
Transformations: VT = -1, VS = ½
Mapping Rule:
Vertex:
(x, y)  (x, ½y – 1)
(0, -1)
Table of Values:
Axis: x = 0
x
-3
-2
-1
0
1
2
3
y
½
0
-½
-1
-½
0
½
2. State the transformations applied to y = |x| based on the given mapping rule:
a) (x, y)  (x – 2, -3y)
b) (x, y)  (x, ½ y + 3)
HT = -2, Rx, VS = 3
VS = ½, VT = 3
c) (x, y)  (x + 5, -2y – 5)
HT = 5, Rx, VS = 2, VT = -5
3. State the equation given the following transformations (applied to y = |x|):
a) VT = -1, VS = 4, HT = 3
¼ (y + 1) = |x – 3|
b) Rx, VT = 3
c) Rx, HT = -4, VT = 2
-(y – 3) = |x|
-(y - 2) = |x + 4|
4. State the transformations and then the equation for:
A) Transformations: VT = 2, HT = 4
Equation: y – 2 = |x – 4|
B) Transformations: VT = -2, HT = - 1, VS = ½
Equation: 2(y + 2) = |x + 1|
C) Transformations: Rx, VT = -3, HT = 2
Equation: -(y + 3) = |x – 2|
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