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Math 1310 Test Free Response first practice 1. Thomas collects dimes and quarters in his change jar. If he has 6 more dimes than quarters, and the total amount of money in the jar is $34.55, find the number of each type of coin in the jar. a. b. c. d. Define a variable Write the equation Solve the equation State the answer to the question, in appropriate units. 2. Solve by completing the square on the function: 3. Write the following expression in the form: a + bi − − − = Solutions: Question 1 Solution 1: a. Let d = the number of dimes and d - 6 = the number of quarters b. Then 0.10d = the amount of money in dimes 0.25(d - 6) = the amount of quarters. c Equation: 0.10d + 0.25(d − 6) = 34.55 and d =103 Answer: There are 103 dimes and 97 quarters This was using decimals which without a calculator . You could change the answer to be in pennies like the next solution. Solution 2: a. Let x = the number of quarters and x+6= the number of dimes b. Then 25x = the amount in quarters and 10(x+6)= the amount In dimes c. 25x +10(x+6) = 3455 25x +10x+60=3455 35x+60=3455 35x=3395 x=3395/35 =97 quarters so x+ 6 = 103 dimes Question 2 − = − + − − − + − = + = + − = = − − − = = ±√ = ±√ ±√ Question 3 − = ∗ + + + = + + − − = − + − = +