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Math 110
Lecture #19
CH. 4.3-4.4 (PART I). Logarithmic Function. Logarithmic equations.
ƒ Change-of-Base Formula.
For any logarithmic bases a and b, and any
positive number M,
log b M =
log a M
log a b
Problem #1.
Use your calculator to find the following logarithms.
Show your work with Change-of-Base Formula.
a) log 2 10
b) log 1 9
c) log 7 11
3
ƒ Using the Change-of-Base Formula, we can graph
Logarithmic Functions with an arbitrary base.
Example:
ln x
ln 2
log x
log 2 x =
log 2
log 2 x =
y = log 2 x
1
Math 110
Lecture #19
CH. 4.3-4.4 (PART I). Logarithmic Function. Logarithmic equations.
ƒ Properties of Logarithms.
If b, M, and N are positive real numbers, b ≠ 1, p, x are real
numbers, then
1. log b MN = log b M + log b N product rule
2. log b
M
= log b M − log b N
N
3. log b M p = p log b M
⎧⎪log b b x = x
4. ⎨ log x
⎪⎩b b = x, x > 0
quotient rule
power rule
inverse property of logarithms
5. log b M = log b N if and only if M = N .
This property is the base for solving Logarithmic
Equations in form log b g ( x ) = log b h ( x ) .
Properties 1-3 may be used for Expanding and Condensing
Logarithmic expressions.
ƒ Expanding and Condensing Logarithmic expressions.
2
Math 110
Lecture #19
CH. 4.3-4.4 (PART I). Logarithmic Function. Logarithmic equations.
Problem #2.
Express each of the following expressions as a single
logarithm
whose coefficient is equal to 1.
a)
1
⎡3log ( x + 1) + 2log ( x − 3) − log 7 ⎤⎦
5⎣
b)
1
1
⎡⎣ln ( x + 1) + 2ln ( x − 1) ⎤⎦ + ln x
2
3
c)
1
1
ln ( x + 3) − ⎡⎣ln x + 3ln ( x + 1) ⎤⎦
2
5
d)
1
⎡⎣log ( x − 2 ) + 2log ( x + 2 ) − log 5⎤⎦
2
Problem #3.
Expand a much as possible each of the following.
x2 y
a) log 5
z
x3 y
b) ln
z3
4
ƒ Solving Logarithmic Equations.
3
Math 110
Lecture #19
CH. 4.3-4.4 (PART I). Logarithmic Function. Logarithmic equations.
1. Solving the Simplest Logarithmic Equation (SLE).
Given: log b x = a , b > 0 , b ≠ 1 , a is any real number.
According the definition of the logarithm this equation is
equivalent to x = b a .
2. According to properties of logarithms, if
log b M = logb N , then M = N .
Remember, check is part of solution for
Logarithmic Equations.
Problem #4. Solve the following Logarithmic Equations.
a) log 2 x = 5
b) log 3 ( x − 2 ) = 5
c) log ( x 2 − x ) = log 6
d) log 1 ( x + 4 ) = −3
2
4
Math 110
Lecture #19
CH. 4.3-4.4 (PART I). Logarithmic Function. Logarithmic equations.
e) log ( x − 15 ) = −2
f) ln ( x + 3) = 1
g) log ( 2 x − 1) = log ( x − 2 )
5