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UNIT 3 LESSON 5 RADICAL EQUATIONS AND SQUARE ROOT FUNCTION Solving Radical Equations A “radical” equation is when the variable is in the radicand. How to: Step 1: Isolate the radical Step 2: Raise each side to power equal to index Step 3: Solve the resulting equation Step 4: Check answers to avoid extraneous solutions (extraneous means that the solution does not work) Ex 4) Simplify Step 1: Is radical isolated? YES because there are no constants or variables in front or behind radical Step 2: The index = 2 so we will square both sides of the equation ( √𝑥 − 1) 2 = (2) 2 Step 3: Solve the equation x – 1= 4 x=5 Step 4: Check for extraneous solutions (plug x = 5 into original equation) 2 = 2 My solution checks good. x = 5 is the solution to the equation √5 − 1 = 2 √4 = 2 Ex 5) Simplify (x − 3) 2 = (√30 − 2𝑥) 2 X2 – 6x + 9 = 30 – 2x X2 – 4x -21 = 0 (x – 7) (x + 3) = 0 x =7 x = -3 x=7 is a solution to the equation, x = -3 is an extraneous solution Check: 7 − 3 = √30 − 2(7) −3 − 3 = √30 − 2(−3) 4 = √16 4 =4 -6 = √36 -6 = 6 Domain - solve for variable under radical to find domain We will graph the square root function using transformation rules. Example 1) Graph the function State the transformation and domain Using the graphing calculator, input the function. Notice the transformation from the original function (square root function) and the function given. Answer: Graph moves right 2 units. Domain = x ≥ 2 Example 2) Graph the function State the transformation and domain Using the graphing calculator, input the function. Notice the transformation from the original function (square root function) and the function given. Answer: Graph moves right 3 units, up 2 units, and reflection. Domain = x ≥ 3