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stellar evolution Simon Portegies Zwart Sterrewacht Leiden > from amuse.lab import * > bodies = Salpeter(N, Mmin, Mma > stellar = MESA() > stellar.add_particles(bodies) > stellar.evolve_model(t_end) >write_to_file(stellar, “stars.hdf5”) Initialize Evolve Store data The Sun – best studied example Stellar interiors not directly observable. Solar neutrinos emitted at core and detectable. Helioseismology - vibrations of solar surface can be used to probe density structure Must construct models of stellar interiors – predictions of these models are tested by comparison with observed properties of individual stars 3 Observable properties of stars Basic parameters to compare theory and observations: • Mass (M) • Luminosity (L) – The total energy radiated per second i.e. power (in W) ∞ L=∫0 L λ dλ • Radius (R) • Effective temperature (Te) – The temperature of a black body of the same radius as the star that would radiate the same amount of energy. Thus L= 4πR2 σ Te4 where σ is the Stefan-Boltzmann constant (5.67× 10-8 Wm-2K-4) ⇒ 3 independent quantities 4 What are the main physical processes which determine the structure of stars ? • Stars are held together by gravitation – attraction exerted on each part of the star by all other parts • Collapse is resisted by internal thermal pressure. • These two forces play the principal role in determining stellar structure – they must be (at least almost) in balance • Thermal properties of stars – continually radiating into space. If thermal properties are constant, continual energy source must exist • Theory must describe - origin of energy and transport to surface 5 Equation of hydrostatic support Balance between gravity and internal pressure is known as hydrostatic equilibrium Mass of element dm = ρ r dsdr where ρ(r)=density at r Consider forces acting in radial direction 1. Outward force: pressure exerted by stellar material on the lower face: P r ds 2. Inward force: pressure exerted by stellar material on the upper face, and gravitational attraction of all stellar material lying within r GM(r) P(r + dr)ds + dm 2 r GM(r) = P(r + dr)ds + r (r)dsdr 2 r ᅠ 6 In hydrostatic equilibrium: GM r P r ds=P r dr ds 2 ρ r dsdr r GM r ⇒ P r dr −P r =- 2 ρ r dr r If we consider an infinitesimal element, we write P(r + dr) - P(r) dP(r) = dr dr for δr→0 Hence rearranging above we get dP(r) GM(r)r (r) =dr r2 The equation of hydrostatic support 7 Equation of mass conservation Mass M(r) contained within a star of radius r is determined by the density of the gas ρ( r). Consider a thin shell inside the star with radius r and outer radius r+δr 2 dV =4 r dr 2 ⇒ dM=dVρr =4 r drρ r dM r 2 ⇒ =4 r ρ r dr In the limit where δr → 0 This the equation of mass conservation 8 Stellar energy production Cooling ● Contraction ● Chemical Reactions ● Nuclear Reactions ● 9 Solving the equations of stellar structure Hence we now have four differential equations, which govern the structure of stars (note – in the absence of convection). dM r =4 r 2 ρ r dr dP(r) GM(r)r (r) =dr r2 dL r =4 r 2 ρ r e r dr 3ρ r k R r dT r =L r 2 3 dr 64 r sT r We will consider the quantities: P = P (ρ, T, chemical composition) κkR = κR(ρ, T, chemical composition) ε = ε (ρ, T, chemical composition) Where r = radius P = pressure at r M = mass of material within r ρ = density at r L = luminosity at r (rate of energy flow across sphere of radius r) T = temperature at r kR = Rosseland mean opacity at r ε = energy release per unit mass per unit time The equation of state 10 Boundary conditions Two of the boundary conditions are fairly obvious, at the centre of the star M=0, L=0 at r=0 At the surface of the star its not so clear, but we use approximations to allow solution. There is no sharp edge to the star, but for the the Sun ρ(surface)~10-4 kg m-3. Much smaller than mean density ρ(mean)~1.4×103 kg m-3 (which we derived). We know the surface temperature (Teff=5780K) is much smaller than its minimum mean temperature (2×106 K). Thus we make two approximations for the surface boundary conditions: ρM=M, ρ = 0 kg/m3 and T = 0K at r=rs i.e. that the star does have a sharp boundary with the surrounding vacuum 11 Use of mass as the independent variable The above formulae would (in principle) allow theoretical models of stars with a given radius. However from a theoretical point of view it is the mass of the star which is chosen, the stellar structure equations solved, then the radius (and other parameters) are determined. We observe stellar radii to change by orders of magnitude during stellar evolution, whereas mass appears to remain constant. Hence it is much more useful to rewrite the equations in terms of M rather than r. If we divide the other three equations by the equation of mass conservation, and invert the latter: dr 1 = dM 4pr 2 r dP GM =dM 4pr 4 ᅠ dL =e dM With boundary conditions: r=0, L=0 at M=0 ρ=0, T=0 at M=Ms dT 3k R L =dM 64p 2 r 4 acT 3 We specify Ms and the chemical composition and now have a well defined set of relations ᅠ to solve. It is possible to do this analytically if simplifying assumptions are made, but in general these need to be solved numerically on a computer. 12 Example set of models Eggleton code 13 Geneva code 14 Theoretical isochrones from Geneva models 15 Examples of young and old clusters NGC6231 young cluster Age~ 6Myrs Pleiades young open cluster Age~ 100Myrs 16 47 Tuc : globular cluster. Age= 810Gyrs NGC188: old open cluster . Age= 7Gyrs 17