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```June 15 Math 2254 sec 001 Summer 2015
Section 7.2: Trigonometric Integrals
d
sin x = cos x,
dx
d
cos x = − sin x
dx
sin2 x + cos2 x = 1
Half Angle IDs
sin2 x =
1
(1 − cos 2x),
2
cos2 x =
sin x cos x =
()
1
(1 + cos 2x)
2
1
sin 2x
2
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Other Uses of Trig Identities
Recall:
d
tan x = sec2 x
dx
and
d
sec x = sec x tan x
dx
tan2 x+1 = sec2 x
Z
tan x dx = ln | sec x|+C
and
Z
sec x dx = ln | sec x+tan x|+C
()
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Other Uses of Trig Identities
Recall:
d
cot x = − csc2 x
dx
and
d
csc x = − csc x cot x
dx
cot2 x+1 = csc2 x
Z
cot x dx = − ln | csc x|+C = ln | sin x|+C
and
Z
csc x dx = − ln | csc x+cot x|+C
()
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Evaluate
Z
π/2
cot3 x csc4 x dx
π/4
()
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()
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()
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A summary note about tangents/cotangents and
secants/cosecants
I
The substitution u = tan x requires we have du = sec2 x dx with
an even number of sec x left to convert to tangents.
I
The substitution u = sec x requires we have du = sec x tan x dx
and an even number of tan x left to convert to secants.
I
The substitution u = cot x requires we have −du = csc2 x dx with
an even number of csc x left to convert to cotangents.
I
The substitution u = csc x requires we have −du = csc x cot x dx
and an even number of cot x left to convert to cosecants.
()
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Integration by Parts w/ Trigonometric ID
Evaluate
R
()
sec3 x dx beginning with integration by parts.
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()
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```
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