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Lesson #5 – Electric Potential I. Review of Concepts From Physics 1224 A. Key Concept – Force (Vector) In first semester physics, we showed that we could in theory solve ANY problem involving a system of particles moving at speeds less than 10% of the speed of light by determining the net external force acting upon the system and applying Newton’s Laws. However, we found that many problems were difficult to solve by this method because either the individual forces acting upon the system were unknown (collisions) or because of the vector nature of forces (energy problems). Thus, we solved many problems using the scalar concepts of energy, work, and potential energy instead of using the vector force methods directly!! B. Potential Energy – U The negative of the work done by a conservative force as an object is moved from point A to point B is defined to be the difference in the potential energy of the object due to that force between point A and point B. Because potential energy is defined in terms of an integral, only the difference in potential energy has physical meaning!!! Thus, when someone talks about the potential energy at some point or potential energy function, they actually mean the potential energy difference with respect to some implied zero potential reference point!!! C. Gravitational Potential Energy (near the surface of the Earth) – Ug Using the surface of the earth as the zero gravitational potential energy reference point, the gravitational potential energy of an object of mass M at a height of h above the Earth is given by Note: Gravitational potential energy is NOT a scalar field since its value depends on the mass of the object and not just the object’s location. This is true of all types of potential energy. Potential energy is a property of a system of objects. In this case, the gravitational potential energy belongs to system of masses composed of the Earth and the object at height h. C. Example of a Scalar Field We can create a scalar function that depends only upon the object’s location above the Earth dividing the gravitational potential energy function by the mass of the test object. This new function is a scalar gravitational potential field created by the Earth. With this new function, we can easily determine the potential energy stored as object of mass M is moved from the zero potential energy reference location to a point at a height of h above the Earth by multiplying our scalar gravitational potential energy field by the object’s mass. In other words, we can easily find out how much work we must do to move the object from the Earth’s surface to a height h. Although this process may seem unnecessary for the simple problem we are considering here, it is extremely helpful for problems involving more complicated geometry. Furthermore, we will see shortly that a special instrument called the voltmeter has been constructed to calculate the difference in the scalar electric potential between two points in space. II. Electric Potential Energy – UE A. For non-time varying electric fields, the electric force on a test charge q is a conservative force. B. Using the definition of potential energy from Physics 1224, we have that the change in electric potential energy for a test object of charge q as it is moved from point A to point B is given by the equation: Note: The electric potential energy is not a scalar field as it depends on the charge of the test object. The electrical potential energy is a property of a system of charges (those charges that set up the electric field and the test charge). III. Electric Potential Difference (Voltage) - V A. Definition – The electric potential difference between two points in space is defined as the change in the electric potential energy that a test object would experience as it was moved between the two points divided by the charge on the test object. B. Units – Volts C. Electric potential difference depends only on the points in space and not on the test object. Thus, it is a scalar field created by the charges that created the electric field. D. Electric Potential Difference: (Scalar) Electric Field : (Vector) Electric potential can be uniquely defined at a point in space only after defining a reference point of zero electric potential. For a point charge, we will choose r = as our reference point. IV. Calculating the Electric Potential Difference From the Electric Field A. If you know the electric field, you can calculate the electric potential difference between two points using the formula: PROOF: B. EXAMPLE: What is the electric potential difference between point B : (2,3) and N A : (0,0) for a constant electric field, E 100. iˆ C SOLN: Since the electric potential depends only on the starting and ending points, we can choose any path that we wish to evaluate the integral. In the diagram below, we split the path into two segments: 1) A to C and 2) C to B. y C A B x C. Although it is possible to calculate the electric potential given the electric field, this process is rarely done in practices as it defeats the advantage of avoiding the vector math associated with electric fields. Instead, we will follow the same process that we did in PHYS1224 when we calculated the work integral for a few special forces (gravity, spring, etc) to develop potential energy functions. We then used the potential energy functions when solving problems. V. Electric Potential For a Point Charge A. We already know that any problem involving a distribution of charge can be solved by breaking the charge distribution into a series of point charges and then either integrating or summing the individual point charge contributions. B. The electric potential due to a point charge of charge Q at a distance r from the point charge is given by where we have chosen r = as our zero electric potential reference point. PROOF: Consider the change in electric potential between a point at a distance r from a point charge Q and r = . Since the electric potential depends only upon the initial point ( r = ) and the final point ( r = r ) and not the path taken between the points, we can chose to evaluate the integral by moving along the radius. r= x Q V(r) V( ) Electric Field For A Point Charge : Displacement Vector : r VI. Electric Potential For Any Charge Distribution A. Discrete Set of Point Charges The total electric potential for N discrete point charges can be found using our result from part V. The result is B. Continuous Charge Distribution Using our result from part V and Calculus, we see that the total electric field due to a continuous charge distribution is C. Although the proceeding two results may look similar to our results involving electric fields, they are mathematically much easier to perform because they involve scalars and not vectors. (No breaking vectors into components or dealing with r̂ ) D. Another advantage of our approach is that we can experimentally perform these sums or integration’s using a voltmeter. The common (negative) lead is placed at the zero reference point (i.e. large r) and the positive lead gives the electric potential at any point in space where it is placed. EXAMPLE: Calculate the electric potential at point P : (0.00 m, -0.450 m) due to a 6.00 nC point charge at (0.00 m,0.150 m) and a –4.00 nC point charge at (-0.450 m, 0.00 m). y 6nC 0.15 m -4nC x 0.45 m 0.45 m P X Note: Compare this with the work required to determine the electric field at point P. Example 2: Calculate the electric potential at a distance d to the left of the end of a uniformly charged thin rod of length L that is lying along the x-axis as shown below: dq A x d r L VII. Calculating the Electric Field From the Electric Potential Difference If the electric potential is known for a charge distribution then you can find the electric field by the formula Where E is the electric field V is the electric potential difference is the gradient. In the Cartesian coordinate system, the gradient is given by ˆ ˆ ˆ i j k . x y z It is more complicated in other coordinate systems and you will either need to look it up in a math handbook or learn the general formula for the gradient for generalized coordinates whose metric is not one. (see Math Methods for Physicists and Engineers Web Page or look at the book of the same title by Arfkin) You should note that the gradient is an operator. Thus, the position of the electric potential and the gradient in the equation is IMPORTANT!! PROOF: In PHYS1224, we learned that in order for a force to be conservative, you must be able to write the force as the negative of the gradient of a scalar function (potential energy function). Thus, we have Dividing both sides by the charge on the test object, we have that Since q is a constant, we can bring it inside the gradient operator, thus we have Now using the definitions for the electric field and electric potential, we have that EXAMPLE: What is the electric field associated with the electric potential V = 3x2yz3? PROBLEM: Given a specified charge distribution, find the acceleration that a test charge would experience at a specific point in space. Flow Chart (Electric Field Method) Given: A charge distribution Calculate Electric Field Continuous Distribution No Yes Calculate the Electric Field E kdq r̂ 2 charges r Calculate Force on Test Charge FqE Calculate Force on Test Charge F a m N kQ E 2 i r̂i i 1 ri PROBLEM: Given a specified charge distribution, find the acceleration that a test charge would experience at a specific point in space. Flow Chart (Electric Potential Method) ** MORE STEPS but Easier Math ** Given: A charge distribution Calculate Electric Potential Continuous Distribution N No Yes Calculate the Electric Potential V kdq r charges Calculate Electric Field E V Calculate Force on Test Charge FqE Calculate Force on Test Charge F a m V i 1 kQ i ri VII. Equipotential Surfaces A. Definition – An equipotential surface is defined as a surface consisting of a continuous distribution of points having the same electric potential (voltage). D B C A VBA = VCA = VDA = B. From the definition of electric potential, we know that an equipotential surface is also a constant potential energy surface!!! Thus, in the same way we can walk on the third floor of a building without being hurt by gravity, we can place our hand on the Van de Graaff generator and become charged without being shocked!!! If we step out of a window on the third floor, then gravity will do work on our mass as we move between two surfaces of different gravitational potential energy. If we touch something or someone who is not at the same electric potential as the Van de Graaff then the electric field will do work on the electric charges in our body as they move between the two surfaces of different electric potential. (i.e. You get shocked!!) ** If you are having trouble following this discussion then review the material on the “work energy theorem” and the “conservation of mechanical energy requirement” from PHYS1224 ** Electrical Engineering Safety Tip – Electrical engineers and electronic technicians often work on devices that are capable of severely shocking or even killing a person. In order to reduce the possibility of this hazard, they often tie the common (negative) lead to a single reference point on the circuit called “ground.” The electric potential at any point in the circuit is then measured by touching the positive lead of the voltmeter to the desired point while keeping the other hand in your pocket or behind your back. This reduces the chance of you reaching across the circuit and accidentally touching with your hands two points that greatly differ in electric potential. Although the point chosen as the ground can theoretically be any convenient point in the circuit, it is usually specified in the schematics when one is troubleshooting. C. Electric field is perpindicular to an equipotential surface at every point on the surface. PROOF: Consider two neighboring points on an equipotential surface. The difference in electric potential between the two points must be zero so we have that D. Electric field lines point in the direction of DECREASING electric potential. EXAMPLE 1: Draw the electric field lines and equipotential surfaces for the positive point charge Q shown below: +Q EXAMPLE 2: Draw the electric field lines and equipotential surfaces for the charge distribution shown below: +3Q -Q LAB: We will experimentally determine equipotential surfaces and electric field lines for different charge distributions in lab. Remember to bring graph paper to lab!!! VIII. Conductors and Electric Potential A. All points on the surface of a conductor are at equipotential! We know from previous work that the electric field is perpendicular to the surface of a conductor. From our work in the previous section, it therefore follows that the conductor’s surface is an equipotential surface. B. All points INSIDE a conductor are at equipotential! Surface of Conductor B A Since the electric field inside a conductor is ______________, we have VBA = VB – VA = C. All points in an EMPTY CAVITY inside a conductor are at the SAME electric potential as the CONDUCTOR!! Outer Surface of Conductor B A Cavity VBA = VB – VA =