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Week 1 Handout MAT 1033C Professor Niraj Wagh J Section 2.1 Linear Equations in One Variable Linear Equations in One Variable A linear equation in one variable is an equation that can be written in the form: ax + b = c where a, b, and c are real numbers and a ≠ 0. For example, 3x = 15, 7 – y = 3y, 4n – 9n + 6 = 0 are all times of linear equations in one variable. When you SOLVE an equation you find the SOLUTION to the equation. That is you find a number that when substituted into the equation makes both the right hand side and left hand side of an equation equal. Let’s examine this… Our equation is: 3x + 4 = 7 -> ISOLATE the “X” term 3x + 4 = 7 −4 −4 -> All X’s on one side, everything else on the other! 3x = 3 -> Make the coefficient of “x” become 1 so divide 3 on both sides. -> Thus, the solution is x =1 -> Check by substituting the value into the original equation: N. Wagh 1 3x 3 = 3 3 3(1) + 4 = 7 7 = 7, YES! J Review on Fractions & Lowest Common Denominator (LCD) Suppose we are trying to add or subtract TWO fractions with DIFFERENT denominators, can we do this automatically? NO! L We must get both fractions to have the same denominator, we call this the lowest common denominator (LCD). Once they have the same denominator, we can add/subtract them! For example, I want to add: 1 3 + 2 5 We must find a number that 2 and 5 both go into because we want the denominator to be the same! If it’s not the same we can’t add the two fractions! What is the LCD? It is ____! Why? ___ is the least common multiple (LCM) that 2 and 5 both go into. ____ x ____ = 10 When doing this we multiply BOTH the top and bottom of the fraction: = , we are completely simplified! N. Wagh 2 2.1 Examples Solve each equation and check. 1. -2x = 18 2. 5y – 3 = 11 + 3y 3. 4x + 14 = 6x + 8 4. 2(4x + 3) = 7x + 5 x x 5 6. + = 2 5 4 7. 1 1 1 5. x +1 = x + 4 6 2 2 + h h −1 1 + = 9 3 3 That’s it for 2.1! W ork on MML 2.1. If you have ANY questions, please feel free to ask! Intermediate Algebra is a hard course and I would love to help you! J N. Wagh 3 Section 2.2 An Introduction to Problem Solving In this section we are going to talk about applications, i.e. story problems. Most students find these problems to be very difficult but I will do my best to make sure it’s as doable as possible. Throughout this course we are going to see a variety of applications both here and in your lab. General Steps to Solving Story Problems 1. Read the re-read problem. 2. State what you KNOW and what you want to FIND out. -> Sometimes it’s helpful to draw a sketch of what the problem is asking. 3. Translate the problem into a mathematical equation. 4. Solve the equation. 5. Explain what your solution means. 2.2 Examples Write the following as algebraic expressions. Then simplify. 1. The perimeter of a rectangle with length x and width x – 5. 2. The sum of three consecutive integers if the first is “z.” N. Wagh 4 Solve. 3. Daytona International Speedway in Florida has 37,000 more grandstand seats than twice the number of grandstand seats at the Darlington Motor Raceway in South Carolina. Together, these two race tracks seat 220,000 NASCAR fans. How many seats does each race track have? That’s it for 2.2! W ork on MML 2.2. If you have ANY questions, please feel free to ask! Intermediate Algebra is a hard course and I would love to help you! J N. Wagh 5 Section 2.3 Formulas & Problem Solving This section is pretty similar to section 2.1. In 2.1., we solved linear equations, and in this section we will be solving for particular variables of formulas. Some general formulas: I = PRT Interest = principal •rate •time A = lw Area of a rec tan gle = length • width d = rt Dis tan ce = rate •time C = 2π r Circumfrence of a circle = 2 • π •radius V = lwh Volume of a rec tan gular solid = length • width • height nt ! r$ A = P #1+ & Compound Interest Formula : P = principal amount, r = rate, " n% n = # of times compounded per year, t = time in years When you want to solve for a particular variable, the same general steps from 2.1 apply. Our goal is to isolate the variable that we want to solve for. 2.3 Examples Solve each equation for the specified variable 1. Solve I = PRT for R 2. Solve P = 2L + 2W for W N. Wagh 6 3. Solve A = Prt + P for P 4. Solve E = I(r + R) for r 5. Complete the table and find the balance A if $5000 is invested at an annual percentage rate of 6% for 15 years and compounded n times per year. n A 1 2 4 12 365 2.3 is complete! W ork on MML 2.3. If you have ANY questions, please feel free to ask! Intermediate Algebra is a hard course and I would love to help you! J N. Wagh 7