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Transcript
Solving Equations
Common Core Standard: Use variables to represent quantities in a real-world or mathematical problem, and construct
simple equations and inequalities to solve problems by reasoning about the quantities.
Common Core Standard: Solve word problems leading to equations of the form px + q = r and p(x + q) = r, where p, q,
and r are specific rational numbers. Solve equations of these forms fluently. Compare an algebraic solution to an arithmetic
solution, identifying the sequence of the operations used in each approach.

In 6th grade, students learned to solve one-step equations, now students will learn to solve 1 and 2 step equations

Example: The perimeter of a rectangle is 54 cm. Its length is 6 cm. What is its width?
o
o
To determine the perimeter of a rectangle there are two commonly used formulas

1: w + w + l + l, where w = width and l = length

2: 2w + 2 l
For this example, use the second formula (but you could also use the first one and would still get the same
answer)

2w + 2 l = P

Now, substitute the information known in for each variable

2w + 2(6cm) = 54 cm

2w + 12 cm = 54 cm

Combine like terms 12 cm and 54 cm are the constants and like terms

Subtract 12 cm from each side of the equation to keep the equation equal and because
subtraction is the inverse operation of addition

2w + 12 cm – 12 cm = 54 cm – 12 cm; Note: 12 cm – 12 cm = 0

2w = 42 cm

Now, divide both sides of the equation by 2, because the question asks for what the width equals,
right now, we know what 2 times the width equals


2w ÷ 2 = 42 cm ÷ 2

w = 24 cm
Real World Example:
o
Jalen spent $200 at the mall this weekend. He bought several items. He purchased three shirts, and he also
bought a pair of shoes for $120. How much were each shirt? Assume that all the shirts cost the same
amount.
o

Converting this to an equation can be tricky, take it step by step

We know that Jalen spent $200, so the equation will equal $200

We know that he spent $120 for one item

We also know that he bought 3 shirts for an undetermined amount of money.

What we don’t know is the variable, so the amount the shirts cost is the variable, x
Now, put this information together

3x- this represents the amount spent on shirts, since he bought 3 of them

3x + $120 = this represents the total spent, because he bought a pair of shoes and 3 shirts

3x + $120 = $200 is the equation
o
Combine like terms, which are $120 and $200
o
To move $120 with $200, subtract $120, since it is the inverse operation
o
3x + $120 – $120 = $200 - $120
o
3x = $80
o
Now, to determine what one shirt equals, we must change the 3 to a 1 to change a number to 1, divide that
number by itself

o
So, divide both sides of the equation by 3, so that the equation stays equal
o
3x ÷ 3 = $80 ÷ 3
o
x = approximately $26.67.
o
So each t-shirt costs about $26.67.
Distributive Property Example:
o
Solve: -2(n + 6) = 26
o
First, use the distributive property to multiply the terms inside the parenthesis by the -2
o

-2 ● n + -2 ● 6 = 26

-2n + -12 = 26
Now, combine like terms the -12 and 26
o
To move the -12 with the 26 add 12 to both sides, since -12 + 12 = 0

-2n + -12 + 12 = 26 + 12

-2n = 38
o
Now, to determine what just one variable equals, divide the -2n by -2, since this will equal 1
o
Also divide 38 by -2, so that the equation stays equal
o
-2n ÷ -2 = 38 ÷ -2
o
n = - 19
o
Prove it!
o
-2(n + 6) = 26, n = -19

Substitute the -19 in for n, since they are equal

-2(-19 + 6) = 26

-2(-13) = 26

-2 ● -13 = 26

26 = 26, it works!!! 