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Verbal Expressions An expression is a mathematical phrase (not a complete thought; no verb; no = sign). An equation is a mathematical sentence (complete thought; has verb; has = sign). Addition Verbal Terms Subtraction Multiplication *added to sum plus *more than add addend increased by *greater than1 total together Division left times divided by difference multiply divided into take away product divide *take from factpr each *less than multiplied by quotiend subtract groups of dividend minus scale factor split/group decreased by to the power of divisor *decreased from subtracted by *subtracted from deduct by *deduct from reduced by *reduced from 1 greater than is most often used as an inequality symbol *Flip/flop – from, than to Subtraction – flip flop is important because commutative property does not apply A number plus 9 would be represented by n+9 not 9+n 9 more than a number = n+9 not 9+n Ex) 3n+7 can be verbalized multiple ways: 3 times a number plus 7 7 greater than 3 times a number 3 multiplied by a number added to 7 The sum of a number times 3 plus 7 Ex) 6-3y=-15 6 minus 3 times a number is -15 6 less three times a number is -15 3 times a number less than 6 equals -15 4-1 Expressions, Equations, Inequalities Expressions - a mathematical phrase that can be simplified or evaluated –by order of operations 2 types of expression: Numerical expression – no variables, just numbers. Ex) 5+33+(4- -62)3 Variable expression – has variables (at least one variable) also known as an Algebraic expression. In this class the only time a variable expression would be simplified would be if we were given the value of the variable. Ex) m2+3t(m-6)3 Equations - a mathematical sentence that shows equality; made up of two equal expressions. Ex) n+3=7 (n+3 is one expression and seven is the other expression) Inequalities – a mathematical sentence where one expression is either greater than, less than, greater than or equal to, or less than or equal to (>, <, >, <) 4-2 Substitutions for Algebraic (Variable) Expressions “Simplify or evaluate” – order of operations problem (PEMDAS) Ex) simplify: b2+-c if b=7, c= 4 c3 numerator b + c (the opposite of c) 72+4 49+4 53 53 64 2 - Ex) simplify: 2a2+b2+(a-b)2 if a=3, b=-5 2(3)2+-52+(3- -5)2 2(3)2+-52+(3+5)2 2(3)2+-52+82 2(9)+25+64 18+25+64 43+64 107 Do not be satisfied with “close,” go for “exact.” 4-3 denominator c3 - 3 4 16x-4 64 Patterns and Sequences Arithmetic Sequences (addition (+) only) – each term is found by adding the same number to the previous term. They have a common difference between each term (the number you add to each term). Ex) 8, 11, 14, 17…*rule is add 3 or n+3 Ex) 20, 15, 10, 5…* rule is add -5. Common mistake – looks like subtraction between terms so it is not recognized as an arithmetic sequence when it actually is because it is adding a negative number. Ex) 5, 6, 8, 11, 15 … this is not an arithmetic sequence because the same number isn’t being added to the previous number. It is a sequence adding 1, 2, 3, 4… Common mistake - After finding the common difference, students may not identify the term requested by a question. For example: 1, 2, 3, 4… what is the 10 th term in the sequence? Students may just locate the next term in the sequence. Geometric Sequences Multiplication (x) only – each term is found by multiplying the previous number by the same number of times. They have a common ratio between each term. It changes each term by the same number of times. Ex) 1, 2, 4, 8, 16, 32… *rule is multiplying by 2 or 2n Ex) 40, 20, 10, 5, 2.5… * rule is multiplying by 1 2 or 1 n 2 Ex) 4, -8, 16, -32… *rule is multiplying by -2 or -2n This will most likely be what we see on the SOL. 4-4 Algebraic Equations One step algebraic equations Goals: Get the variable by itself – to undo what is being done to the variable, do the inverse operation. Keep the equation balanced – do operations to both sides *Do not change the sign or number, just the operation. Ex) 6n= -36 6n 36 = (could also be written 6n÷6 =-36÷6) 6 - 6 n= 6 Check your work: 6(-6)=-36 36=-36 *For organizational purposes, put the variable on the left. Ex) 16= p-3 p-3=16 p-3+3=16+3 p=19 Check your work: 16=19-3 16=16 *You want to have the variable first in the equation. Ex) 12=-3-n. First, get the variable on the left. Next, to get the variable first, change 3-n=12 the subtraction problem to an addition problem. Now because of the commutative property we can change the order of the addends to put 3+( n)=12 the variable first. Undo what is being done to the variable and do to n+( 3)=12 n+(-3)-(-3)=12-(-3) both sides. n=15 (“the opposite of n”=15) n=-15 Check your work: 12=-3-(-15) 12=12 4-5 Algebraic Equations Two step algebraic equations Goals are the same as one step equations. Ex) 3n-5=-10 3n-5+5=-10+5 3n=-5 If you have multiplication attached to a variable, undo (get rid of) the addition/subtraction first (unless the multiplication applies to both the variable and the other term) 3n - 5 = 3 3 -5 n= or -1.67 3 Check your work: -5 )-5=-10 3 - 15 -5=-10 3 3( - 5-5=-10 5+-5=-10 10=-10 With division attached to addition or subtraction, it depends if the division only applies to the variable or the variable and the other term. If the division only applies to the variable, undo the addition/subtraction first. If the division applies to both the variable and the other term, undo the division first. Ex) ÷ applies to variable and other term ÷ applies just to variable m5 = 10 3 3 m5 ( )= 10(3) 1 3 m-5=-30 m-5+5=-30+5 m=-25 Check your work: - 25 5 = 10 3 - 30 = 10 3 - 10=-10 n -6=3 5 n -6+6=3+6 5 n =9 5 5 n ( )=9(5) 1 5 n=45 Check your work: 45 -6=3 5 9-6=3 3=3 4-6 Inequalities An inequality is a mathematical sentence with unbalanced expressions using either greater than, less than, greater than or equal to, or less than or equal to signs (>, <, >, <). Always read signs left to right. If the big part of the symbol is on the left, it is greater than. > If the big part of the symbol in on the right, it is less than. < Goals: Get variable by itself Keep the inequality “unbalance” by the same amount it was initially. Ex) q+-6>4 q+-6-(-6)>4-(-6) q>10 Always check your work. In this example try any number greater than 10. Check: 12+-6>4 6>4 Graphing inequalities Whatever number you are graphing, put in the middle of the numberline. > or < exclude the number when graphing. Use “open dot” > or < include the number when graphing. Use “closed dot” The arrow on the graph will match the > or < symbol.(only when variable is on the left) Ex) x>-4 - 6 - - 5 - 4 - 3 2 n<5 3 4 5 6 7 p< -1 - y>7 4 3 5 - 6 - 2 7 1 0 8 1 9 10 Common mistake: students circle the wrong answer. i.e., n<9. Students circle 9 but n is less than 9. Just plug in answers to check. 4-7 Inequalities Any time you multiply or divide both sides of an inequality by a negative number, switch the inequality symbol. 3 p >4 -3 -3 p ( )<4(-3) *multiplying by a negative so the sign is switched -1 - 3 Ex) p<-12 Check your work: - 14 - 13 - 12 - 11 -10 - 15 >4 -3 5>4 4-8 Functions Relation – any set of ordered pairs. For each “x” member there may be many “y” members. Ex) {(5,2), (-7,3), (6,-4), (5,9), (1,2)} { } symbol means “set containing” All functions are relations but not all relations are function. A function is a relation in which there is one and only one “y” value for each “x.” There are no repeats in the ”x” values. The “x” value is referred to as input (domain) and the “y” value is the output (range). Functions can be graphed on a coordinate plane because input and output become ordered pairs. Linear functions are functions that create lines. Elementary function: Input X Rule Output Y When deciding what number to put in (input) remember that the ordered pair should be small enough to plot on a coordinate plane (usually -1, 0, 1) Ex) The rule is 3x+1 y=3x+1 If x = 1 y=3(-1)+1 0 y=3(0)+1 1 y=3(1)+1 y=-3+1 y=-2 y=3(0)+1 y=1 y=3+1 y=4 Ordered pairs x y 1 2 0 1 1 4 Ex) Are these relations also functions? 1) {(6,8), (-3,4), (5,2), (6,3)} – This is not a function because the “x” value of 6 has two “y” values (8 and 3). 2) {(3,4), (2,-4), (1,0), (-2,4)} – This is a function because there are not repeating “x” values (even though there are two “y” values that are the same). 4-9 One Step Algebraic Word Problems Step 1 – make a “let” statement (letting a variable represent the unknown amount in the question) Step 2 - do the elementary math. The algebraic method of solving is always the inverse of the elementary way. (step 4 helps with this if you are having trouble) Step 3 – create an algebraic equation (inverse of elementary). If you are having trouble with step 3, use step 4 to help (trial and error) Step 4 - write out a verbal sentence from the algebraic equation Step 5 – solve the algebraic equation and write a completion statement. The right side of any one step algebraic equation (when keeping the equation balanced) will be the elementary problem Ex) Jim’s 3 fish tanks contain an equal amount of fish. If Jim has a total of 27 fish, how many fish are in each tank? Steps: 1) let f= number of fish in each of the 3 tanks 2) 27 =9 3 3) 3f=27 4) Three fish tanks times the number of fish in each tank equals 27 fish 5) 3f=27 3 f 27 This is the same as the elementary problem in step 2. = 3 3 f=9 Jim has 9 fish in each of his 3 tanks. Ex) There were 7 apples. Fred ate 2 apples. How many apples were left” 1) Let a = number of apples left 2) 7-2=5 3) a+2=7 4) The number of apples left plus the 2 that were eaten equals 7 apples. 5) a+2=7 a+2-2=7-2 a=5 There are 5 apples left. 4-10 Two Step Algebraic Word Problems For two step problems, make sure you talk yourself through the elementary math as well as the algebraic equation. Circle the numbers you have “given” in the word problem from your elementary math. This will give you the numbers for your equation. From there you can use trial and error. Combine with the variable (from the let statement) to make your algebraic equation and check to see that it makes sense. Ex) It costs $12 to attend a golf clinic with a local pro. Buckets of balls for practice during the clinic cost $3 each. How many buckets can you buy at the clinic if you have $30 to spend? Steps: 1) let b= number of buckets of balls you can buy 2) 30-12=18 18 =6 3 3) 3b+12=30 4) Cost of one bucket (3) times the number of buckets you can buy (n) plus the cost of the class (12) equals total spent (30) 5) 3b+12-12=30-12 This is the same as the elementary problem in step 2. 3b=18 3b 18 = 3 3 This is the same as the elementary problem in step 2. b=6 You can buy 6 buckets of balls 4-11