Download Lesson 6: Why Call It Tangent?

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts
no text concepts found
Transcript
Lesson 6
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
ALGEBRA II
Lesson 6: Why Call It Tangent?
Classwork
Opening Exercise
Let 𝑃(π‘₯πœƒ , π‘¦πœƒ ) be the point where the terminal ray intersects the unit circle after rotation by πœƒ degrees, as shown in the
diagram below.
a.
Using triangle trigonometry, what are the values of π‘₯πœƒ and π‘¦πœƒ in terms of πœƒ?
b.
Using triangle trigonometry, what is the value of tan(πœƒ°) in terms of π‘₯πœƒ and π‘¦πœƒ ?
c.
What is the value of tan(πœƒ°) in terms of πœƒ?
Lesson 6:
Why Call It Tangent?
This work is derived from Eureka Math β„’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from ALG II-M2-TE-1.3.0-08.2015
S.38
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 6
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
ALGEBRA II
Discussion
A description of the tangent function is provided below. Be prepared to answer questions based on your understanding
of this function and to discuss your responses with others in your class.
Let πœƒ be any real number. In the Cartesian plane, rotate the nonnegative π‘₯-axis by πœƒ degrees about the origin.
Intersect the resulting terminal ray with the unit circle to get a point (π‘₯πœƒ , π‘¦πœƒ ). If π‘₯πœƒ β‰  0, then the value of tan(πœƒ°) is
π‘¦πœƒ
π‘₯πœƒ
. In terms of the sine and cosine functions, tan(πœƒ°) =
Lesson 6:
sin(πœƒ°)
for cos(πœƒ°) β‰  0.
cos⁑(πœƒ°)
Why Call It Tangent?
This work is derived from Eureka Math β„’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from ALG II-M2-TE-1.3.0-08.2015
S.39
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 6
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
ALGEBRA II
Exercise 1
1.
For each value of πœƒ in the table below, use the given values of sin(πœƒ°) and cos(πœƒ°) to approximate tan(πœƒ°) to two
decimal places.
𝜽⁑
(degrees)
𝐬𝐒𝐧(𝜽°)
𝐜𝐨𝐬(𝜽°)
βˆ’89.9
βˆ’0.999998
0.00175
βˆ’89
βˆ’0.9998
0.0175
βˆ’85
βˆ’0.996
0.087
βˆ’80
βˆ’0.98
0.17
βˆ’60
βˆ’0.87
0.50
βˆ’40
βˆ’0.64
0.77
βˆ’20
βˆ’0.34
0.94
0
0
1.00
20
0.34
0.94
40
0.64
0.77
60
0.87
0.50
80
0.98
0.17
85
0.996
0.087
89
0.9998
0.0175
89.9
0.999998
0.00175
a.
As πœƒβ‘ β†’ ⁑ βˆ’90° and πœƒ > βˆ’90°, what value does⁑sin(πœƒ°) approach?
b.
As πœƒβ‘ β†’ ⁑ βˆ’90° and πœƒ > βˆ’90°, what value does cos(πœƒ°) approach?
Lesson 6:
Why Call It Tangent?
This work is derived from Eureka Math β„’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from ALG II-M2-TE-1.3.0-08.2015
𝐭𝐚𝐧(𝜽°)
S.40
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 6
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
ALGEBRA II
c.
As πœƒβ‘ β†’ ⁑ βˆ’90° and πœƒ > βˆ’90°, how would you describe the value of tan(πœƒ°) =
d.
As πœƒβ‘ β†’ ⁑90°β‘ and πœƒ < 90°, what value does sin(πœƒ°) approach?
e.
As πœƒβ‘ β†’ ⁑90° and πœƒ < 90°, what value does cos(πœƒ°) approach?
f.
As πœƒβ‘ β†’ ⁑90° and πœƒ < 90°, how would you describe the behavior of tan(πœƒ°) =
g.
How can we describe the range of the tangent function?
sin(πœƒ°)
?
cos(πœƒ°)
sin(πœƒ°)
?
cos(πœƒ°)
Example 1
Suppose that point 𝑃 is the point on the unit circle obtained by rotating the initial ray through 30°. Find tan(30°).
Lesson 6:
Why Call It Tangent?
This work is derived from Eureka Math β„’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from ALG II-M2-TE-1.3.0-08.2015
S.41
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 6
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
ALGEBRA II
Exercises 2–6: Why Do We Call it Tangent?
2.
Let 𝑃 be the point on the unit circle with center 𝑂 that is the
intersection of the terminal ray after rotation by πœƒ degrees as
shown in the diagram. Let 𝑄 be the foot of the perpendicular line
from 𝑃 to the π‘₯-axis, and let the line β„“ be the line perpendicular
to the π‘₯-axis at 𝑆(1,0). Let 𝑅 be the point where the secant line
Μ…Μ…Μ…Μ….
𝑂𝑃 intersects the line β„“. Let π‘š be the length of 𝑅𝑆
a.
Show that π‘š = tan(πœƒ°).
b.
Using a segment in the figure, make a conjecture why mathematicians named the function 𝑓(πœƒ°) =
sin(πœƒ°)
the
cos(πœƒ°)
tangent function.
c.
Why can you use either triangle, β–³ 𝑃𝑂𝑄 or β–³ 𝑅𝑂𝑆, to calculate the length π‘š?
d.
Imagine that you are the mathematician who gets to name the function. (How cool would that be?) Based
upon what you know about the equations of lines, what might you have named the function instead?
Lesson 6:
Why Call It Tangent?
This work is derived from Eureka Math β„’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from ALG II-M2-TE-1.3.0-08.2015
S.42
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 6
M2
ALGEBRA II
3.
Draw four pictures similar to the diagram in Exercise 2 to illustrate what happens to the value of tan(πœƒ°) as the
rotation of the secant line through the terminal ray increases towards 90°. How does your diagram relate to the
work done in Exercise 1?
4.
When the terminal ray is vertical, what is the relationship between the secant line 𝑂𝑅⁑and the tangent line 𝑅𝑆?
Explain why you cannot determine the measure of π‘š in this instance. What is the value of tan(90°)?
5.
When the terminal ray is horizontal, what is the relationship between the secant line 𝑂𝑅⁑and the π‘₯-axis? Explain
what happens to the value of π‘š in this instance. What is the value of tan(0°)?
Lesson 6:
Why Call It Tangent?
This work is derived from Eureka Math β„’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from ALG II-M2-TE-1.3.0-08.2015
S.43
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 6
M2
ALGEBRA II
6.
When the terminal ray is rotated counterclockwise about the origin by 45°, what is the relationship between the
Μ…Μ…Μ…Μ…? What is the value of tan(45°)?
value of π‘š and the length of 𝑂𝑆
Exercises 7–8
7.
Rotate the initial ray about the origin the stated number of degrees. Draw a sketch and label the coordinates of
point 𝑃 where the terminal ray intersects the unit circle. What is the slope of the line containing this ray?
a.
30°
b.
45°
c.
60°
Lesson 6:
Why Call It Tangent?
This work is derived from Eureka Math β„’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from ALG II-M2-TE-1.3.0-08.2015
S.44
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 6
M2
ALGEBRA II
8.
d.
Use the definition of tangent to find tan⁑(30°), tan⁑(45°), and tan⁑(60°). How do your answers compare your
work in parts (a)–(c)?
e.
If the initial ray is rotated πœƒ degrees about the origin, show that the slope of the line containing the terminal
ray is equal to tan(πœƒ°). Explain your reasoning.
f.
Now that you have shown that the value of the tangent function is equal to the slope of the terminal ray,
would you prefer using the name tangent function or slope function? Why do you think we use tangent
instead of slope as the name of the tangent function?
Rotate the initial ray about the origin the stated number of degrees. Draw a sketch and label the coordinates of
point 𝑃 where the terminal ray intersects the unit circle. How does your diagram in this exercise relate to the
diagram in the corresponding part of Exercise 7? What is tan(πœƒ°)⁑for these values of πœƒ?
a.
210°
Lesson 6:
Why Call It Tangent?
This work is derived from Eureka Math β„’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from ALG II-M2-TE-1.3.0-08.2015
S.45
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 6
M2
ALGEBRA II
b.
225°
c.
240°
d.
What do the results of parts (a)–(c) suggest about the value of the tangent function after rotating an additional
180 degrees?
e.
What is the period of the tangent function? Discuss with a classmate and write your conclusions.
f.
Use the results of Exercise 7(e) to explain why tan(0°) = 0.
g.
Use the results of Exercise 7(e) to explain why tan(90°) is undefined.
Lesson 6:
Why Call It Tangent?
This work is derived from Eureka Math β„’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from ALG II-M2-TE-1.3.0-08.2015
S.46
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 6
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
ALGEBRA II
Lesson Summary
sin(πœƒ°)
, where cos(πœƒ°) β‰  0.
cos(πœƒ°)
ο‚§
A working definition of the tangent function is tan(πœƒ°) =
ο‚§
The value of tan(πœƒ°) is the length of the line segment on the tangent line to the unit circle centered at the
origin from the intersection with the unit circle and the intersection with the secant line created by the
π‘₯-axis rotated πœƒ degrees. (This is why we call it tangent.)
ο‚§
The value of tan(πœƒ°) is the slope of the line obtained by rotating the π‘₯-axis πœƒ degrees about the origin.
ο‚§
The domain of the tangent function is {πœƒ ∈ ℝ|πœƒ β‰  90 + 180π‘˜, for⁑all⁑integersβ‘π‘˜} which is equivalent to
{πœƒ ∈ ℝ| cos(πœƒ°) β‰  0}.
ο‚§
The range of the tangent function is all real numbers.
ο‚§
The period of the tangent function is 180°.
𝐭𝐚𝐧(𝟎°)
𝐭𝐚𝐧(πŸ‘πŸŽ°)
𝐭𝐚𝐧(πŸ’πŸ“°)
𝐭𝐚𝐧(πŸ”πŸŽ°)
𝐭𝐚𝐧(πŸ—πŸŽ°)
0
√3
3
1
√3
undefined
Problem Set
1.
Label the missing side lengths, and find the value of tan(πœƒ°) in the following right triangles.
a.
πœƒ = 30
1
30°
b.
πœƒ = 45
1
45°
Lesson 6:
Why Call It Tangent?
This work is derived from Eureka Math β„’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from ALG II-M2-TE-1.3.0-08.2015
S.47
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 6
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
ALGEBRA II
c.
πœƒ = 60
1
60°
2.
Let πœƒ be any real number. In the Cartesian plane, rotate the initial ray by πœƒ degrees about the origin. Intersect the
resulting terminal ray with the unit circle to get point 𝑃(π‘₯πœƒ , π‘¦πœƒ ).
a.
Complete the table by finding the slope of the line through the origin and the point 𝑃.
𝜽, in degrees
b.
Slope
𝜽, in degrees
0
180
30
210
45
225
60
240
90
270
120
300
135
315
150
330
Slope
Explain how these slopes are related to the tangent function.
Lesson 6:
Why Call It Tangent?
This work is derived from Eureka Math β„’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from ALG II-M2-TE-1.3.0-08.2015
S.48
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 6
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
ALGEBRA II
3.
Consider the following diagram of a circle of radius π‘Ÿ centered at the origin. The line β„“ is tangent to the circle at
𝑆(π‘Ÿ, 0), so β„“ is perpendicular to the π‘₯-axis.
a.
If π‘Ÿ = 1, then state the value of 𝑑 in terms of one of the trigonometric functions.
b.
If π‘Ÿ is any positive value, then state the value of 𝑑 in terms of one of the trigonometric functions.
For the given values of π‘Ÿ and πœƒ, find 𝑑.
c.
πœƒ = 30, π‘Ÿ = 2
d.
πœƒ = 45, π‘Ÿ = 2
e.
πœƒ = 60, π‘Ÿ = 2
f.
πœƒ = 45, π‘Ÿ = 4
g.
πœƒ = 30, π‘Ÿ = 3.5
h.
πœƒ = 0, π‘Ÿ = 9
i.
πœƒ = 90, π‘Ÿ = 5
j.
k.
πœƒ = 60, π‘Ÿ = √3
πœƒ = 30, π‘Ÿ = 2.1
l.
πœƒ = 𝐴, π‘Ÿ = 3
m. πœƒ = 30, π‘Ÿ = 𝑏
n.
4.
Knowing that tan(πœƒ°) =
sin(πœƒ°)
, for π‘Ÿ = 1, find the value of 𝑠 in terms of one of the trigonometric functions.
cos(πœƒ°)
Using what you know of the tangent function, show that βˆ’tan(πœƒ°) = tan(βˆ’πœƒ°) for πœƒ β‰  90 + 180π‘˜, for all
integers π‘˜.
Lesson 6:
Why Call It Tangent?
This work is derived from Eureka Math β„’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from ALG II-M2-TE-1.3.0-08.2015
S.49
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Related documents