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Lesson 2-3 Proving Theorems (page 43) Essential Question Can you justify the conclusion of a conditional statement? Proving Theorems What is a theorem? Statements that can be proved. Midpoint Theorem Theorem 2-1 If M is the midpoint of AB, ½ ½ then AM = ____ AB and MB = ____ AB. Given: M is the midpoint of AB 1 AB Prove: AM = 2 1 MB = AB 2 ⦁ A ⦁ M ⦁ B Given: M is the midpoint of AB Prove: AM = 1 AB 2 ⦁ A ⦁ M ⦁ B 1 MB = AB 2 Statements Reasons M is the midpoint of AB ___________________ ___________________ AM @ MB ___________________ AM = MB ___________________ AM + MB = AB Given Definition of Midpoint ___________________ ___________________ Def. of Segments Segment Add. Post. ___________________ 5. ______________________ AM + AM = AB Substitution Prop. ___________________ ___________________ Distributive Prop. ___________________ Division Prop. of = ___________________ Substitution Prop. 1. 2. 3. 4. 6. ___________________ 2 AM = AB 7. ___________________ AM = ½ AB 8. ___________________ MB = ½ AB Example: Given R is the midpoint of SQ . Give the reason that justifies each statement. S R P (a) Q SR @ RQ Definition of Midpoint _________________________________ Example: Given R is the midpoint of SQ . Give the reason that justifies each statement. S R P (b) Q 1 SR = SQ 2 Midpoint Theorem _________________________________ Example: Given R is the midpoint of SQ . Give the reason that justifies each statement. S R P (c) Q SR + RQ = SQ Segment Addition Post. _________________________________ Example: Given R is the midpoint of SQ . Give the reason that justifies each statement. S R P (d) Q PR bisects SQ Def. of Segment Bisector _________________________________ Theorem 2-2 If Angle Bisector Thm BX is the bisector of ∠ABC, ½ and m∠XBC = ____ ½ m∠ABC. then m∠ABX = ____ m∠ABC Given: BX is the bisector of ÐABC Prove: 1 mÐABX = mÐABC 2 1 mÐXBC = mÐABC 2 A ⦁ X ⦁ B ⦁ C Given: BX is the bisector of ÐABC Prove: mÐABX = 1 mÐABC 2 1 mÐXBC = mÐABC 2 Statements A ⦁ X ⦁ B Reasons ⦁ C 1. ___________________ ___________________ 2. ___________________ ___________________ See page 45 ___________________ ___________________ Classroom 3. ___________________ ___________________ Exercises 4. ______________________ ___________________ #10 for HELP! ___________________ ___________________ 5. ___________________ ___________________ 6. ___________________ ___________________ Given: BX is the bisector of ÐABC Prove: mÐABX = 1 mÐABC 2 1 mÐXBC = mÐABC 2 Statements A ⦁ X ⦁ B Reasons ⦁ C 1. BX ___________________ is the bisector of ÐABC 2. ___________________ ÐABX @ ÐXBC ___________________ (m∠ABX = m∠XBC) m∠ABX + m∠XBC = m∠ABC 3. ___________________ ___________________ Given Def. of Angle Bisector ___________________ ___________________ (Def. of Angles) Angle Add. Post. ___________________ 4. ______________________ m∠ABX + m∠ABX = m∠ABC Substitution Prop. ___________________ (Distributive Prop.) ___________________ ___________________ Division Prop. of = ___________________ Substitution Prop. (___________________ 2 m∠ABX = m∠ABC ) 5. ___________________ m∠ABX = ½ m∠ABC 6. ___________________ m∠XBC = ½ m∠ABC Example: Given FD bisects ∠CFE. Give the reason that justifies each statement. C D F (a) E m∠CFD = ½ m∠CFE Angle Bisector Theorem _________________________________ Example: Given FD bisects ∠CFE. Give the reason that justifies each statement. C D F (b) E m∠CFD = m∠DFE Def. of Angle Bisector _________________________________ Example: Given FD bisects ∠CFE. Give the reason that justifies each statement. C D F (c) E CD + DE = CE Segment Addition Post. _________________________________ Reason Used in Proofs 1. Given information 2. Definitions 3. Postulates (including properties from algebra) 4. Theorems - only ones that have already been proved! Deductive Reasoning: … proving statements by reasoning from accepted postulates, definitions, theorems, and given information. Example: 2-column proofs Note: Definitions can be written as biconditionals (combine conditional and converse), i.e. the conditional and converse are both true . Example of a Biconditional: • Conditional: If an angle is a right angle, then its measure is 90º. • Converse: If the measure of an angle is 90º, then the angle is a right angle. • Biconditional: An angle is a right angle if and only if its measure is 90º. Given: M is the midpt. of PQ N is the midpt. of RS PQ = RS Prove: PM = RN Statements ∙P ∙M ∙Q ∙R ∙N ∙S Reasons 1. ___________________ ___________________ Given M is the midpt. of PQ ___________________ N is the midpt. of RS ___________________ PQ = RS ½ PQ = ½ RS 2. ______________________ Multiplication Prop. ___________________ PM = ½ PQ 3. ______________________ Midpoint Theorem ___________________ Midpoint Theorem RN = ½ RS 4. ___________________ ___________________ 5. ___________________ ___________________ Substitution Prop. PM = RN Assignment Written Exercises on pages 46 & 47 RECOMMENDED: 9 to 12 ALL numbers, 19 & 20 REQUIRED: 1 to 8 ALL numbers, 13 & 14 Assignment Worksheet on Lesson 2-3 Prepare for a Quiz on Lessons 2-1 to 2-3: Using Deductive Reasoning Can you justify the conclusion of a conditional statement?