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What is the difference between atomic structure and crystal structure? Chapter 6 METAL STRUCTURE ENT 145 Materials Engineering Atomic structure relates to the number of protons and neutrons in the nucleus of an atom, as well as the number and probability distributions of the constituent electrons. Crystal structure pertains to the arrangement of atoms in the crystalline solid material. Chapter 3 - 1 Materials and Packing Metallic Crystal Structures Crystalline materials... • atoms are situated in a repeating/ periodic array. • typical of: -metals -many ceramics -some polymers Noncrystalline materials... • atoms have no periodic packing • occurs for: -complex structures -rapid cooling "Amorphous" = Noncrystalline Chapter 3 - 2 • Tend to be densely packed. • Reasons for dense packing: crystalline SiO2 Adapted from Fig. 3.23(a), Callister & Rethwisch 8e. Si Oxygen - Typically, only one element is present, so all atomic radii are the same. - Metallic bonding is not directional. - Nearest neighbor distances tend to be small in order to lower bond energy. - Electron cloud shields cores from each other • Have the simplest crystal structures. We will examine three such structures... noncrystalline SiO2 Adapted from Fig. 3.23(b), Callister & Rethwisch 8e. Chapter 3 - 3 Unit Cells Simple Cubic Structure (SC) • subdivide the structure into small repeat entities • represent the symmetry of crystal structures- all atom position In the crystal may be generated by translation of the unit cells along each of its edges • basic structural unit or building block Adapted from Fig. 3.2, Callister & Rethwisch 8e. Hard sphere model Aggregate of atoms Chapter 3 - 4 Chapter 3 - • Rare due to low packing density (only Po has this structure) • Close-packed directions are cube edges. • Coordination # = 6 (# nearest neighbors) Click once on image to start animation (Courtesy P.M. Anderson) Chapter 3 - 6 1 Atomic Packing Factor (APF) APF = Body Centered Cubic Structure (BCC) • Atoms touch each other along cube diagonals. Volume of atoms in unit cell* Volume of unit cell --Note: All atoms are identical; the center atom is shaded differently only for ease of viewing. *assume hard spheres ex: Cr, W, Fe (), Tantalum, Molybdenum • Coordination # = 8 • APF for a simple cubic structure = 0.52 atoms unit cell a R=0.5a 1 APF = 4 3 volume atom p (0.5a) 3 a3 close-packed directions contains 8 x 1/8 = 1 atom/unit cell volume unit cell (Courtesy P.M. Anderson) Adapted from Fig. 3.24, Callister & Rethwisch 8e. • APF for a body-centered cubic structure = 0.68 Chapter 3 - 8 Exercise 1. Show for the body-centered cubic (BCC) crystal structure that the unit cell edge length a and the atomic radius R are related through a =4R / √3 . 3a Using the triangle NOP (NP)2 = a2 + a2 = 2a2 And then for triangle NPQ, a (NQ) 2 = (QP) 2 + (NP) 2 But NQ = 4R, R being the atomic radius. Also, QP = a. Therefore, (4R)2 = a2 + 2a2 or a = 4R / √3 2a R Close-packed directions: length = 4R = 3 a a atoms volume 4 p ( 3a/4 ) 3 2 unit cell atom 3 APF = volume 3 a unit cell Chapter 3 - 9 Chapter 3 - 10 Face Centered Cubic Structure (FCC) • Atoms touch each other along face diagonals. --Note: All atoms are identical; the face-centered atoms are shaded differently only for ease of viewing. ex: Al, Cu, Au, Pb, Ni, Pt, Ag • Coordination # = 12 Atomic Packing Factor: FCC • APF for a face-centered cubic structure = 0.74 maximum achievable APF Close-packed directions: length = 4R = 2 a 2a a Adapted from Fig. 3.1(a), Callister & Rethwisch 8e. Adapted from Fig. 3.1, Callister & Rethwisch 8e. Click once on image to start animation (Courtesy P.M. Anderson) 2 atoms/unit cell: 1 center + 8 corners x 1/8 Chapter 3 - 7 Atomic Packing Factor: BCC Adapted from Fig. 3.2(a), Callister & Rethwisch 8e. Adapted from Fig. 3.2, Callister & Rethwisch 8e. Click once on image to start animation 4 atoms/unit cell: 6 face x 1/2 + 8 corners x 1/8 Chapter 3 - 11 Unit cell contains: 6 x 1/2 + 8 x 1/8 = 4 atoms/unit cell atoms volume 4 p ( 2a/4 ) 3 4 unit cell atom 3 APF = volume a3 unit cell Chapter 3 - 12 2 Theoretical Density, r Density = r = r = where Theoretical Density, r • Ex: Cr (BCC) A = 52.00 g/mol R = 0.125 nm n = 2 atoms/unit cell Mass of Atoms in Unit Cell Total Volume of Unit Cell nA VC NA n = number of atoms/unit cell A = atomic weight VC = Volume of unit cell = a3 for cubic NA = Avogadro’s number = 6.022 x 1023 atoms/mol Chapter 3 - 15 Adapted from Fig. 3.2(a), Callister & Rethwisch 8e. atoms unit cell r= volume unit cell R a 2 52.00 a3 6.022 x 1023 a = 4R/ 3 = 0.2887 nm g mol rtheoretical = 7.18 g/cm3 ractual atoms mol = 7.19 g/cm3 Chapter 3 - 16 Exercise 2. Iron has a BCC crystal structure, an atomic radius of 0.124 nm, and an atomic weight of 55.85 g/mol. Compute and compare its theoretical density with the experimental value found in the front section of the book. Chapter 3 - 17 Chapter 3 - 18 Exercise 3. Rhodium has an atomic radius of 0.1345 nm and a density of 12.41 g/cm3. Determine whether it has an FCC or BCC crystal structure. Chapter 3 - 19 Chapter 3 - 20 3 Polycrystalline Densities of Material Classes In general rmetals > rceramics > rpolymers 30 Why? Metals have... Ceramics have... • less dense packing • often lighter elements Polymers have... r (g/cm3 ) • close-packing (metallic bonding) • often large atomic masses • low packing density (often amorphous) • lighter elements (C,H,O) Composites have... • intermediate values Metals/ Alloys 20 Platinum Gold, W Tantalum 10 Silver, Mo Cu,Ni Steels Tin, Zinc 5 4 3 2 Graphite/ Ceramics/ Semicond Composites/ fibers Polymers B ased on data in Table B1, Callister *GFRE, CFRE, & AFRE are Glass, Carbon, & Aramid Fiber-Reinforced Epoxy composites (values based on 60% volume fraction of aligned fibers in an epoxy matrix). Adapted from Fig. K, color inset pages of Callister 5e. (Fig. K is courtesy of Paul E. Danielson, Teledyne Wah Chang Albany) Zirconia Titanium Aluminum Magnesium Al oxide Diamond Si nitride Glass -soda Concrete Silicon G raphite 1 1 mm PTFE Silicone PVC PET PC HDPE, PS PP, LDPE 0.5 0.4 0.3 Glass fibers GFRE* Carbon fibers CFRE* A ramid fibers AFRE * Wood Data from Table B.1, Callister & Rethwisch, 8e. Chapter 3 - 21 Various stages in the solidification of polycrystalline overall component properties are not directional. • Grain sizes typically range from 1 nm to 2 cm (i.e., from a few to millions of atomic layers). E (diagonal) = 273 GPa Data from Table 3.3, Callister & Rethwisch 8e. (Source of data is R.W. Hertzberg, Deformation and Fracture Mechanics of Engineering Materials, 3rd ed., John Wiley and Sons, 1989.) E (edge) = 125 GPa • Polycrystals -Properties may/may not vary with direction. -If grains are randomly oriented: isotropic. 200 mm (Epoly iron = 210 GPa) -If grains are textured, anisotropic. Upon completion of solidification, grains having irregular shapes have formed Chapter 3 - 22 Single vs Polycrystals -Properties vary with direction: anisotropic. -Example: the modulus of elasticity (E) in BCC iron: Growth of the crystallite Isotropic • Nb-Hf-W plate with an electron beam weld. • Each "grain" is a single crystal. • If grains are randomly oriented, • Single Crystals Small crystallite nuclei Anisotropic • Most engineering materials are polycrystalline. Adapted from Fig. 4.14(b), Callister & Rethwisch 8e. (Fig. 4.14(b) is courtesy of L.C. Smith and C. Brady, the National Bureau of Standards, Washington, DC [now the National Institute of Standards and Technology, Gaithersburg, MD].) Grain structure as it would appear under microscope Polymorphism Chapter 3 - 24 Crystal Systems • Two or more distinct crystal structures for the same material (allotropy/polymorphism) iron system titanium liquid , -Ti 1538ºC -Fe BCC carbon 1394ºC diamond, graphite -Fe FCC Unit cell: smallest repetitive volume which contains the complete lattice pattern of a crystal. 7 crystal systems 14 crystal lattices 912ºC BCC a, b, and c are the lattice constants -Fe Fig. 3.4, Callister & Rethwisch 8e. Chapter 3 - 25 Chapter 3 - 26 4 Point Coordinates z Point coordinates for unit cell center are 111 c a/2, b/2, c/2 000 a x ½½½ y b Point coordinates for unit cell corner are 111 z 2c b y Translation: integer multiple of lattice constants identical position in another unit cell b Chapter 3 - Point Coordinates Chapter 3 - 28 Point Coordinates tableun_03_p57 Crystallographic Directions Algorithm z y 1. Vector repositioned (if necessary) to pass through origin. 2. Read off projections in terms of unit cell dimensions a, b, and c 3. Adjust to smallest integer values 4. Enclose in square brackets, no commas [uvw] x ex: 1, 0, ½ => 2, 0, 1 => [ 201 ] -1, 1, 1 => [ 111 ] where overbar represents a negative index families of directions <uvw> Chapter 3 - 31 figun_03_p58 5 Crystallographic Planes Crystallographic Planes • Miller Indices: Reciprocals of the (three) axial intercepts for a plane, cleared of fractions & common multiples. All parallel planes have same Miller indices. • Algorithm 1. If the plane passes through selected origin, either another parallel plane must be constructed within the unit cell or new origin must be construct. 2. Read off intercepts of plane with axes in terms of a, b, c 3. Take reciprocals of intercepts 4. Reduce to smallest integer values 5. Enclose in parentheses, no commas i.e., (hkl) Adapted from Fig. 3.10, Callister & Rethwisch 8e. Chapter 3 - 33 Chapter 3 - 34 Crystallographic Planes Crystallographic Planes z example 1. Intercepts 2. Reciprocals 3. Reduction a 1 1/1 1 1 4. Miller Indices (110) example 1. Intercepts 2. Reciprocals 3. Reduction a 1/2 1/½ 2 2 4. Miller Indices (100) b 1 1/1 1 1 c 1/ 0 0 y c 1/ 0 0 example 1. Intercepts 2. Reciprocals b a x b 1/ 0 0 z c z 3. Reduction 4. Miller Indices a 1/2 1/½ 2 6 b 1 1/1 1 3 (634) c c 3/4 1/¾ 4/3 4 a x y b c y a Family of Planes {hkl} b Ex: {100} = (100), (010), (001), (100), (010), (001) x Chapter 3 - 35 X-Ray Diffraction Chapter 3 - 36 X-Rays to Determine Crystal Structure • Incoming X-rays diffract from crystal planes. extra distance travelled by wave “2” q q Chapter 3 - 37 Adapted from Fig. 3.20, Callister & Rethwisch 8e. spacing dhkl between planes Braggs Law • Diffraction gratings must have spacings comparable to the wavelength of diffracted radiation. • Can’t resolve spacings • Spacing is the distance between parallel planes of atoms. reflections must be in phase for a detectable signal dhkl = dhkl = n 2 sin q a √h2 + k2 + l2 = wavelength dhkl = Interplanar spacing a= lattice parameter n = order of reflection Chapter 3 - 38 6 Exercise 3. Using the data for molybdenum in Table 3.1, compute the interplanar spacing for the (111) set of planes X-Ray Diffraction Pattern z z Intensity (relative) c a x z c b y (110) a x c b y a x (211) b y (200) Diffraction angle 2q Diffraction pattern for polycrystalline -iron (BCC) Adapted from Fig. 3.22, Callister 8e. Chapter 3 - 39 Chapter 3 - 40 Exercise 4. Determine the expected diffraction angle for the firstorder reflection from the (113) set of planes for FCC platinum when monochromatic radiation of wavelength 0.154 nm is used. Chapter 3 - 41 Chapter 3 - 42 SUMMARY • Atoms may assemble into crystalline or amorphous structures. • Common metallic crystal structures are FCC, BCC, and HCP. Coordination number and atomic packing factor are the same for both FCC and HCP crystal structures. • We can predict the density of a material, provided we know the atomic weight, atomic radius, and crystal geometry (e.g., FCC, BCC, HCP). • Crystallographic points, directions and planes are specified in terms of indexing schemes. Crystallographic directions and planes are related to atomic linear densities and planar densities. Chapter 3 - 43 Chapter 3 - 44 7 SUMMARY ANNOUNCEMENTS • Materials can be single crystals or polycrystalline. Material properties generally vary with single crystal orientation (i.e., they are anisotropic), but are generally non-directional (i.e., they are isotropic) in polycrystals with randomly oriented grains. • Some materials can have more than one crystal structure. This is referred to as polymorphism (or allotropy). Reading: Core Problems: Self-help Problems: • X-ray diffraction is used for crystal structure and interplanar spacing determinations. Chapter 3 - 45 Chapter 3 - 46 8