Download Solving Systems by Elimination – Section 4.08

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Solving Systems by Elimination – Section 4.08 – Guided Notes This method works because you can add and subtract equations if you line them up along the equal sign. Example 1: Solve the system using elimination. Steps −4𝑥 + 6𝑦 = 3
−4𝑥 − 2𝑦 = −1
1. 2. 3. 4. 5. 1 Math 1: Algebra, Geometry and Statistics
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Sometimes, you have to multiply both equations by a constant before one variable can be eliminated. Example 2: Solve the systems using elimination. 5𝑦 − 2𝑥 = −15
12𝑦 + 3𝑥 = 3
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Practice: Solve each system of equations using elimination. 4𝑥 − 5𝑦 = 15
4𝑥 + 2𝑦 = −6
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6𝑥 − 12𝑦 = 24
−𝑥 − 6𝑦 = 4
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Math 1: Algebra, Geometry and Statistics
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5𝑥 + 𝑦 = 30
3𝑥 − 4𝑦 = 41
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5𝑥 − 2𝑦 = 30
9𝑥 − 2𝑦 = 54
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