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2-7 Solving Absolute-Value Inequalities Connection: Connecting Absolute-Value and Compound Inequalities Essential question: How does solving absolute-value inequalities relate to solving compound inequalities? Standards for Mathematical Content • How would the solution and graph have been different if the inequality had been |x| + 2 ≤ 5? The solution would have been all real numbers that are less than or equal to 3 units from 0. The graph would have been the same except that the circles would have been solid. A-REI.2.3 Solve linear inequalities…in one variable… Vocabulary absolute value 2 Math Background EXplore To solve an absolute-value inequality, properties of inequality can be used to isolate the absolutevalue expression on one side of the inequality. Then the inequality can be rewritten and solved as a compound inequality that does not involve absolute value. When an absolute-value inequality involves < or ≤, the compound inequality uses AND. When an absolute-value inequality involves > or ≥, the compound inequality uses OR. Questioning Strategies • Why is 3 added to each side of the inequality? To INTR O D U C E Essential Question How does solving absolute-value inequalities relate to solving compound inequalities? isolate the absolute-value expression on one side. • How can the graph be used to write a compound inequality? The graph shows the solutions are either less than -5 or greater than 5. This is the solution to the inequality x < -5 OR x > 5. CLOSE You can solve an absolute-value inequality by isolating the absolute-value expression, writing a description of the solution, graphing the solution on a number line, and writing a compound inequality that describes the graph. You can also solve an absolute-value inequality by isolating the absolute-value expression, writing a compound inequality, and solving the compound inequality. When the absolute-value inequality involves < or ≤, the compound inequality involves AND. When the absolute-value inequality involves > or ≥, the compound inequality involves OR. TEAC H 1 explore Questioning Strategies • Why is 2 subtracted from each side of the inequality? To isolate the absolute-value Summarize Have students write a journal entry in which they describe how to solve an absolute-value inequality that involves < or ≤ and one that involves > or ≥. Ask them to explain how they know whether the solution of each is an AND or an OR compound inequality. expression on one side. • How can the graph be used to write a compound inequality? The graph shows that the solutions are both greater than -3 and less than 3. This is the solution to the inequality x > -3 AND x < 3. Chapter 2 103 Lesson 7 © Houghton Mifflin Harcourt Publishing Company Review absolute value with students, reminding them that the absolute value of a number is its distance from 0. Demonstrate by sketching the solution of |x| = 4 on a number line. By looking at the number line, ask students to name some solutions of |x| > 4 and some solutions of |x| < 4. Name Class Notes 2-7 Date Solving Absolute-Value Inequalities Connection: Connecting Absolute-Value and Compound Inequalities Essential question: How does solving absolute-value inequalities relate to solving compound inequalities? The absolute value of a number is its distance from 0 on a number line. To solve an absolute-value inequality, you rewrite the inequality as a compound inequality. A-REI.2.3 1 EXPLORE Solving Absolute-Value Inequalities with < Solve the inequality ⎪x⎥ + 2 < 5. A Use the Subtraction Property of Inequality to isolate the absolute-value expression. ⎪x⎥ + 2 < 5 ⎪x⎥ + 2 - 2 <5- ⎪x⎥ < 2 3 B Write a description of the solution of the inequality. C Draw the graph of the solution on the number line. less All real numbers that are © Houghton Mifflin Harcourt Publishing Company -7 -6 -5 -4 -3 -2 -1 D 0 1 2 3 than 3 4 5 units from 0 6 Use the graph to rewrite ⎪x⎥ < 3 as a compound inequality. AND x > -3 3 , or -3 < x < x< 3 REFLECT 1a. How did you decide whether to use AND or OR in the compound inequality? The graph is a segment with open circles, so the solutions are between these two values. This is the graph of a compound inequality involving AND. 1b. Solve ⎪x + 2⎥ ≤ 5 by rewriting it as a compound inequality. Show your work. ⎪x + 2⎥ ≤ 5 x + 2 ≥ -5 AND x + 2 ≤ 5 x + 2 - 2 ≥ - 5 - 2 AND x + 2 - 2 ≤ 5 - 2 (Subtraction Property of Inequality) x ≥ - 7 AND x ≤ 3 Chapter 2 Lesson 7 103 A-REI.2.3 2 EXPLORE Solving Absolute-Value Inequalities with > Solve the inequality ⎪x⎥ - 3 > 2. A Use the Addition Property of Inequality to isolate the absolute value expression. 3 >2+ ⎪ x⎥ > B 3 5 Write a description of the solution of the inequality. All real numbers greater than 5 units from 0. C Draw the graph of the solution on the number line. D Use the graph to rewrite ⎪x⎥ > 5 as a compound inequality. -7 -6 -5 -4 -3 -2 -1 x < -5 OR 0 1 x> 2 3 4 5 6 5 REFLECT 2a. How did you decide whether to use AND or OR in the compound inequality? The graph is two rays pointing in opposite directions, so the solution is not between these two values. This is the graph of an OR compound inequality. 2b. Solve ⎪x - 3⎥ ≥ 2 by rewriting it as a compound inequality. Show your work. ⎪x - 3⎥ ≥ 2 x - 3 ≤ -2 OR x - 3 ≥ 2 x - 3 + 3 ≤ -2 + 3 OR x - 3 + 3 ≥ 2 + 3 (Addition Property of Inequality) x ≤ 1 OR x ≥ 5 2c. Write a generalization for absolute-value inequalities that relate the inequality symbol to the type of compound inequality that represents a solution. When the absolute-value inequality has a < or ≤ symbol, the solution will be a compound inequality involving AND. When the absolute-value inequality has a > © Houghton Mifflin Harcourt Publishing Company © Houghton Mifflin Harcourt Publishing Company ⎪x⎥ - 3 > 2 ⎪x⎥ - 3 + or ≥ symbol, the solution will be a compound inequality involving OR. Chapter 2 Chapter 2 104 Lesson 7 104 Lesson 7 Problem Solving ADD I T I O NA L P R AC TI C E AND PRO BL E M S O LV I N G 1. |x - 2| ≤ 0.05; 1.95 ≤ x ≤ 2.05 2. |x - 134| ≤ 8; 126 ≤ x ≤ 142 Assign these pages to help your students practice and apply important lesson concepts. For additional exercises, see the Student Edition. 3. |x - 50| > 11 4. |x - 15.3| ≤ 0.4 Answers 5. B Additional Practice 6. G 7. A 1. x ≥ -5 AND x ≤ 5 2. x > -3 AND x < 1 3. x ≥ 3 AND x ≤ 9 4. x > -7 AND x < 1 5. x < -3 OR x > 3 6. x < 2 OR x > 10 © Houghton Mifflin Harcourt Publishing Company 7. x ≤ -9 OR x ≥ -1 8. x ≤ 0.5 OR x ≥ 3.5 9. |x -350| ≤ 35; 315 ≤ x ≤ 385 10. |x - 88| ≤ 7.5; 80.5 ≤ x ≤ 95.5 Chapter 2 105 Lesson 7 Name Class Notes 2-7 Date Additional Practice © Houghton Mifflin Harcourt Publishing Company )1).-.*+,*(*.!$%-) *).$!).!,)!.%.!*""!,-1!-%.! $*-.%)#"*, +!,(*).$1%.$ -.,./+"!!%.!*""!,- 1!-%.!$*-.%)#"*,+!,(*).$1%.$)*-.,./+"!!*,$*1 ()3(*).$-1*/' ))!! .*&!!+.$!1!-%.!"*,%.!.*!'!-- !2+!)-%0!.$)%.! *,1$.0'/!-*"%-.$!,!*".$!,!.)#'!#,!.!,.$) .$!+!,%(!.!, Chapter 2 Lesson 7 105 Problem Solving (&64*28*6(987'3&6)78-&8&6*1*8*67 032,8.7&((*48&'0*+368-*0*2,8-83 ).++*6+6318-.7:&09*'=&81378 1*8*67$6.8*&2)730:*&2 &'73098*:&09*.2*59&0.8=83+.2)8-* 6&2,*3+&((*48&'0*0*2,8-7 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% &.8-.2/73+&7*(6*8291'*6!-*7&=7 8-&8-*67*(6*8291'*6.7136*8-&2 92.87&;&=+631$6.8*&2&'73098* :&09*.2*59&0.8=8-&8,.:*78-*4377.'0* :&09*73+&.7291'*6 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% 96.2,&;36/398#.2(*86.*783/**4-.7 -*&686&8*&8 '*&874*61.298*.7 &(89&0-*&686&8*:&6.*7+6318-.7:&09*'= &719(-&7'*&874*61.298*$6.8* &2)730:*&2&'73098*:&09*.2*59&0.8=83 +.2)#.2(*76&2,*3+-*&686&8*7 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% 3<*73+(*6*&0&6*794437*)83;*.,- 392(*7*&(-59&0.8=(328630 1&2&,*6+.2)78-&88-*'3<*7&6*23 136*8-&2392(*7&;&=+6318-.7 ;*.,-8$6.8*&2&'73098*:&09* .2*59&0.8=8-&8,.:*78-*6&2,*3+4377.'0* ;*.,-873+8-*'3<*7 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% !#! " $-.(-&'73098*:&09*.2*59&0.8=,.:*7 $-.(-1&11&0-&7&0.+*74&28-&8(&2 8-*291'*63+=*&67&,3&81&=0.:* '*6*46*7*28*)'=8-*&'73098*:&09* .2*59&0.8= 28*034* 88*6 3&0& "-*.2*59&0.8=?,.:*78-* 291'*63+=*&67&4&2)&1&=0.:* $-&8.78-*:&09*3+ $30+ # # 28*034* 83 3&8 83 3&0& 83 88*6 83 &2)& 83 $30+ 83 !396(* © Houghton Mifflin Harcourt Publishing Company © Houghton Mifflin Harcourt Publishing Company " -884;;;7&2).*,3>3336,&2.1&0'=8*7&1&11&0-810 Chapter 2 Chapter 2 106 Lesson 7 106 Lesson 7