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Exponential Functions MATH 160, Precalculus J. Robert Buchanan Department of Mathematics Fall 2011 J. Robert Buchanan Exponential Functions Objectives In this lesson we will learn to: recognize and evaluate exponential functions with base a, graph exponential functions and use the One-to-One Property, recognize and evaluate exponential functions with base e, use exponential functions to model and solve real-world problems. J. Robert Buchanan Exponential Functions Exponential Functions Definition The exponential function f with base a is denoted by f (x) = ax where a > 0, a 6= 1, and x is any real number. J. Robert Buchanan Exponential Functions Exponential Functions Definition The exponential function f with base a is denoted by f (x) = ax where a > 0, a 6= 1, and x is any real number. Example Use a calculator if necessary to evaluate each of the following expressions. 31.2 = 1.23 = 2−2.7 = 0.80.2 = 1.0112.7 = J. Robert Buchanan Exponential Functions Exponential Functions Definition The exponential function f with base a is denoted by f (x) = ax where a > 0, a 6= 1, and x is any real number. Example Use a calculator if necessary to evaluate each of the following expressions. 31.2 = 3.73719 1.23 = 2−2.7 = 0.80.2 = 1.0112.7 = J. Robert Buchanan Exponential Functions Exponential Functions Definition The exponential function f with base a is denoted by f (x) = ax where a > 0, a 6= 1, and x is any real number. Example Use a calculator if necessary to evaluate each of the following expressions. 31.2 = 3.73719 1.23 = 1.728 2−2.7 = 0.153893 0.80.2 = 0.956352 1.0112.7 = 1.1347 J. Robert Buchanan Exponential Functions Graphs, a > 1 When a > 1 the graph of an exponential function resembles the following. x −4 −3 −2 −1 0 1 2 3 4 2x y 1 16 1 8 1 4 1 2 1 2 4 8 16 15 10 5 -4 J. Robert Buchanan -2 Exponential Functions 2 4 x Effect of the Base If we increase the value of the base a, the graph becomes steeper. y 30 25 20 15 10 5 -4 -2 J. Robert Buchanan 0 2 Exponential Functions 4 x Graphs, 0 < a < 1 When 0 < a < 1 the graph of an exponential function resembles the following. x 1 y x 3 35 −4 81 30 27 −3 25 9 −2 20 −1 3 15 0 1 1 10 1 3 1 5 2 9 1 3 27 -4 -2 2 1 4 81 J. Robert Buchanan Exponential Functions 4 x Asymptote Regardless of the base a, the function f (x) = ax approaches, but never touches the line y = 0 (the x-axis). In situations like this we may say, y = 0 is an asymptote of the graph of f (x) = ax , or y = 0 is a horizontal asymptote of the graph of f (x) = ax , or the graph of f (x) = ax approaches the line y = 0 asymptotically. J. Robert Buchanan Exponential Functions General Concepts of Exponential Functions For a > 1: For 0 < a < 1: ax > 0 ax > 0 ax increases on (−∞, ∞) and is called an exponential growth function. ax decreases on (−∞, ∞) and is called an exponential decay function. a0 = 1, so the point (0, 1) is on the graph. a0 = 1, so the point (0, 1) is on the graph. ax approaches the x-axis for negative values of x (The x-axis is a horizontal asymptote). ax approaches the x-axis for positive values of x (The x-axis is a horizontal asymptote). J. Robert Buchanan Exponential Functions One-to-One Property Since exponential functions are either always increasing or always decreasing, they all pass the Horizontal Line Test and are therefore one-to-one functions. One-to-One Property For a > 0 and a 6= 1, ax = ay if and only if x = y . J. Robert Buchanan Exponential Functions One-to-One Property Since exponential functions are either always increasing or always decreasing, they all pass the Horizontal Line Test and are therefore one-to-one functions. One-to-One Property For a > 0 and a 6= 1, ax = ay if and only if x = y . Example Use the One-to-One Property to solve the following equation. 2x−3 = 16 J. Robert Buchanan Exponential Functions One-to-One Property Since exponential functions are either always increasing or always decreasing, they all pass the Horizontal Line Test and are therefore one-to-one functions. One-to-One Property For a > 0 and a 6= 1, ax = ay if and only if x = y . Example Use the One-to-One Property to solve the following equation. 2x−3 = 16 2x−3 = 24 J. Robert Buchanan Exponential Functions One-to-One Property Since exponential functions are either always increasing or always decreasing, they all pass the Horizontal Line Test and are therefore one-to-one functions. One-to-One Property For a > 0 and a 6= 1, ax = ay if and only if x = y . Example Use the One-to-One Property to solve the following equation. 2x−3 = 16 2x−3 = 24 x −3 = 4 x J. Robert Buchanan = 7 Exponential Functions Natural Base e In many applications (particularly to the physical and social sciences) we will prefer to use the base e ≈ 2.718281828 . . . . This is called the natural base and the function f (x) = ex is called the natural exponential function. J. Robert Buchanan Exponential Functions Natural Base e In many applications (particularly to the physical and social sciences) we will prefer to use the base e ≈ 2.718281828 . . . . This is called the natural base and the function f (x) = ex is called the natural exponential function. Example Use a calculator if necessary to evaluate each of the following expressions. e1.2 = e3 = e−2.7 = e0.2 = eπ = J. Robert Buchanan Exponential Functions Natural Base e In many applications (particularly to the physical and social sciences) we will prefer to use the base e ≈ 2.718281828 . . . . This is called the natural base and the function f (x) = ex is called the natural exponential function. Example Use a calculator if necessary to evaluate each of the following expressions. e1.2 = 3.32012 e3 = e−2.7 = e0.2 = eπ = J. Robert Buchanan Exponential Functions Natural Base e In many applications (particularly to the physical and social sciences) we will prefer to use the base e ≈ 2.718281828 . . . . This is called the natural base and the function f (x) = ex is called the natural exponential function. Example Use a calculator if necessary to evaluate each of the following expressions. e1.2 = 3.32012 e3 = 20.0855 e−2.7 = 0.0672055 e0.2 = 1.2214 eπ = 23.1407 J. Robert Buchanan Exponential Functions Application: Compound Interest Definition After t years, the balance A in an account with principal P and annual interest rate r (expressed as a decimal) is given by the following formulas. r n t 1 For n compounding periods per year: A = P 1 + n rt 2 For continuous compounding: A = Pe J. Robert Buchanan Exponential Functions Example Determine the balance A at the end of 20 years if $1500 is invested at 6.5% interest and the interest is compounded quarterly monthly weekly continuously J. Robert Buchanan Exponential Functions Example Determine the balance A at the end of 20 years if $1500 is invested at 6.5% interest and the interest is compounded quarterly 0.065 (4)(20) ≈ 5446.73 A = 1500 1 + 4 monthly weekly continuously J. Robert Buchanan Exponential Functions Example Determine the balance A at the end of 20 years if $1500 is invested at 6.5% interest and the interest is compounded quarterly 0.065 (4)(20) ≈ 5446.73 A = 1500 1 + 4 monthly 0.065 (12)(20) A = 1500 1 + ≈ 5484.67 12 weekly continuously J. Robert Buchanan Exponential Functions Example Determine the balance A at the end of 20 years if $1500 is invested at 6.5% interest and the interest is compounded quarterly 0.065 (4)(20) ≈ 5446.73 A = 1500 1 + 4 monthly 0.065 (12)(20) A = 1500 1 + ≈ 5484.67 12 weekly 0.065 (52)(20) A = 1500 1 + ≈ 5499.48 52 continuously J. Robert Buchanan Exponential Functions Example Determine the balance A at the end of 20 years if $1500 is invested at 6.5% interest and the interest is compounded quarterly 0.065 (4)(20) ≈ 5446.73 A = 1500 1 + 4 monthly 0.065 (12)(20) A = 1500 1 + ≈ 5484.67 12 weekly 0.065 (52)(20) A = 1500 1 + ≈ 5499.48 52 continuously A = 1500e(0.065)(20) ≈ 5503.93 J. Robert Buchanan Exponential Functions Application: Exponential Growth The number of fruit flies in an experimental population after t hours is given by Q(t) = 20e0.03t for t ≥ 0. 1 Find the initial number of fruit flies in the population. 2 How large is the population of fruit flies after 72 hours? J. Robert Buchanan Exponential Functions Application: Exponential Growth The number of fruit flies in an experimental population after t hours is given by Q(t) = 20e0.03t for t ≥ 0. 1 Find the initial number of fruit flies in the population. Q(0) = 20e(0.03)(0) = 20 2 How large is the population of fruit flies after 72 hours? J. Robert Buchanan Exponential Functions Application: Exponential Growth The number of fruit flies in an experimental population after t hours is given by Q(t) = 20e0.03t for t ≥ 0. 1 Find the initial number of fruit flies in the population. Q(0) = 20e(0.03)(0) = 20 2 How large is the population of fruit flies after 72 hours? Q(72) = 20e(0.03)(72) ≈ 173 J. Robert Buchanan Exponential Functions Application: Radioactive Decay Let Q represent the mass of carbon-14 (14 C) in grams. The quantity of carbon-14 present after t years is given by t/5715 1 Q(t) = 10 2 1 Find the initial quantity of carbon-14 present. 2 Determine the quantity present after 2500 years. J. Robert Buchanan Exponential Functions Application: Radioactive Decay Let Q represent the mass of carbon-14 (14 C) in grams. The quantity of carbon-14 present after t years is given by t/5715 1 Q(t) = 10 2 1 Find the initial quantity of carbon-14 present. 0/5715 1 = 10 Q(0) = 10 2 2 grams Determine the quantity present after 2500 years. J. Robert Buchanan Exponential Functions Application: Radioactive Decay Let Q represent the mass of carbon-14 (14 C) in grams. The quantity of carbon-14 present after t years is given by t/5715 1 Q(t) = 10 2 1 Find the initial quantity of carbon-14 present. 0/5715 1 = 10 Q(0) = 10 2 2 grams Determine the quantity present after 2500 years. 2500/5715 1 Q(2500) = 10 ≈ 7.38441 2 J. Robert Buchanan Exponential Functions grams Half-Life QHtL 10 8 6 4 2 0 2000 4000 6000 8000 t/5715 1 Q(t) = 10 2 J. Robert Buchanan Exponential Functions 10 000 t Homework Read Section 3.1. Exercises: 1, 5, 9, 13, . . . , 69, 73 J. Robert Buchanan Exponential Functions