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Transcript
6-4 Elimination Using Multiplication
Use elimination to solve each system of equations.
9. x + 5y = 17
−4x + 3y = 24
SOLUTION: Notice that if you multiply the first equation by 4, the coefficients of the x–terms are additive inverses.
Now, substitute 4 for y in either equation to find x.
The solution is (–3, 4).
12. 3x − 3y = −6
−5x + 6y = 12
SOLUTION: Notice that if you multiply the first equation by 2, the coefficients of the y–terms are additive inverses.
Now, substitute 0 for x in either equation to find y.
The solution is (0, 2).
15. 8x + 3y = −7
7x + 2y = −3
SOLUTION: Page 1
Notice that if you multiply the first equation by –2 and the second equation by 3, the coefficients of the y–terms are
additive inverses.
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6-4 Elimination
Using Multiplication
The solution is (0, 2).
15. 8x + 3y = −7
7x + 2y = −3
SOLUTION: Notice that if you multiply the first equation by –2 and the second equation by 3, the coefficients of the y–terms are
additive inverses.
Now, substitute 1 for x in either equation to find y.
The solution is (1, –5).
18. −4x + 2y = 0
10x + 3y = 8
SOLUTION: Notice that if you multiply the first equation by –3 and multiply the second equation by 2, the coefficients of the y–
terms are additive inverses.
Now, substitute
for x in either equation to find y.
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Page 2
6-4 Elimination
Using Multiplication
The solution is (1, –5).
18. −4x + 2y = 0
10x + 3y = 8
SOLUTION: Notice that if you multiply the first equation by –3 and multiply the second equation by 2, the coefficients of the y–
terms are additive inverses.
Now, substitute
for x in either equation to find y.
The solution is
.
Use elimination to solve each system of equations.
21. 2.2x + 3y = 15.25
4.6x + 2.1y = 18.325
SOLUTION: Notice that if you multiply the first equation by –2.1 and the second equation by 3, the coefficients of the y–terms are
additive inverses.
Now, substitute 2.5 for x in either equation to find y.
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6-4 Elimination
Using Multiplication
The solution is
.
Use elimination to solve each system of equations.
21. 2.2x + 3y = 15.25
4.6x + 2.1y = 18.325
SOLUTION: Notice that if you multiply the first equation by –2.1 and the second equation by 3, the coefficients of the y–terms are
additive inverses.
Now, substitute 2.5 for x in either equation to find y.
So, the solution is (2.5, 3.25).
24. SOLUTION: Notice that if you multiply the second equation by –12, the coefficients of the y–terms are additive inverses.
Now, substitute
for x in either equation to find y.
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6-4 Elimination
Using
Multiplication
So, the solution
is (2.5,
3.25).
24. SOLUTION: Notice that if you multiply the second equation by –12, the coefficients of the y–terms are additive inverses.
Now, substitute
for x in either equation to find y.
So, the solution is
.
27. ENTERTAINMENT At an entertainment center, two groups of people bought batting tokens and miniature golf
games, as shown in the table.
a. Define the variables, and write a system of linear equations from this situation.
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b. Solve the system of equations, and explain what the solution represents.
SOLUTION: Page 5
6-4 Elimination Using Multiplication
So, the solution is
.
27. ENTERTAINMENT At an entertainment center, two groups of people bought batting tokens and miniature golf
games, as shown in the table.
a. Define the variables, and write a system of linear equations from this situation.
b. Solve the system of equations, and explain what the solution represents.
SOLUTION: a. Let x = the cost of a batting token and let y = the cost of a miniature golf game; 16x + 3y = 30 and 22x + 5y = 43.
b. Notice that if you multiply the first equation by –5 and the multiply the second equation by 3, the coefficients of
the y–terms are additive inverses.
Now, substitute 1.5 for x in either equation to find y.
The solution is (1.5, 2). A batting token costs $1.50 and a game of miniature golf costs $2.00.
30. ERROR ANALYSIS Jason and Daniela are solving a system of equations. Is either of them correct? Explain your
reasoning.
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6-4 Elimination
Using Multiplication
The solution is (1.5, 2). A batting token costs $1.50 and a game of miniature golf costs $2.00.
30. ERROR ANALYSIS Jason and Daniela are solving a system of equations. Is either of them correct? Explain your
reasoning.
SOLUTION: Jason is correct. In order to eliminate the r–terms, you must multiply the second equation by 2 and then subtract, or
multiply the equation by −2 and then add. When Daniela subtracted the equations, she should have gotten r + 16t =
18, instead of r = 18. The t-term should not be eliminated. She needs to find multiples of the equations that have the
same coefficient or opposite coefficients for either r or t before adding or subtracting the equations.
33. WRITING IN MATH Why is substitution sometimes more helpful than elimination, and vice versa?
SOLUTION: Sample answer: It is more helpful to use substitution when one of the variables has a coefficient of 1 or if
a coefficient can be reduced to 1 without turning other coefficients into fractions. Otherwise, elimination is more
helpful because
it will avoid the use of fractions when solving the system.
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