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Last Night's Homework: pg. 281 #1860 Every 3rd Problem 18. 21. 24. 27. 30. 33. 36. 39. 42. 16o 45' 286o 52' 48" 23.242o 173.410o 1080o 2700o 1440o 133o + 360ko; 473o; 247o 305o + 360ko; 55o; 665o 45. 48. 51. 54. 57. 60. 40o; I 339o; IV III 23o 35o 90k where k is an integer 1 2 Today's Objectives: Find the values of the six trigonometric ratios for acute angles of right triangles. Find the value of a trigonometric ratio given its cofunction. Tomorrow: Quiz 51 52 opposite side hypotenuse θ legs adjacent side 3 Trigonometric Ratios: sine θ sinθ sinθ = opp/hyp cosine θ cosθ cosθ = adj/hyp tangent θ tanθ tanθ = opp/adj e us Definition ten Symbols po hy Words opposite defined by the ratios of the sides of the right triangles θ adjacent Reciprocal Trigonometric Ratios Words Symbols Definition cosecant θ csc θ csc θ = 1/sin θ = hyp/opp secant θ sec θ sec θ = 1/cos θ = hyp/adj cotangent θ cot θ cot θ = 1/tan θ = adj/opp 4 Find the values of the six trig ratios for C B. 15 cm B 8 cm A NOTE: If you do this with your calculator, be sure you are in DEGREE mode. Cofunctions sin θ = cos(90o - θ) tan θ = cot(90o - θ) sec θ = csc(90o - θ) cos θ = sin(90o - θ) cot θ = tan(90o - θ) csc θ = sec(90o - θ) 5 Homework: pg. 288 #1031 Every 3rd 6