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Staple L A S T N A M E , , F I R S T N A M E 2016-2017 Spring Semester MATH 3050 Section 101 (Barsamian) Homework 2, Due Fri Jan 20, 2017 Problem: 1 2 3 4 5 6 7 8 9 10 Total Rescaled Your Score: Possible: 10 10 10 10 10 10 10 10 10 10 100 20 [1] (Similar to suggested problem 2.3 #41) A set of premises and a conclusion are given at right. Use the valid argument forms listed in table 2.3.1 to deduce the conclusion from the premises, giving a reason for each step as in example 2.3.8. Assume all variables are statement variables. premise 1: premise 2: premise 3: premise 4: premise 5: conclusion: πβ¨π πβπ πβ§π βπ ~π ~π β π β§ π π [2] Let x and y be variables with domain the set R of real numbers. Let π(π₯, π¦) be the predicate βIf π₯ < π¦ then π₯ 2 < π¦ 2.β (a) Explain why π(π₯, π¦) is false for (π₯, π¦) = (β3,2). (b) Give (π₯, π¦) values different from those in part (a) for which π(π₯, π¦) is false. (c) Explain why π(π₯, π¦) is true for (π₯, π¦) = (2,3). (d) Explain why π(π₯, π¦) is true for (π₯, π¦) = (2, β3). (e) Give values different from those in parts (c) and (d) for which π(π₯, π¦) is true. [3] Find the truth set of each predicate. (a) The domain of the variable π is the set Z. The predicate π(π) is the sentence β6/π is an integer.β (b) The domain of the variable π is the set Z+. The predicate π(π) is the sentence β6/π is an integer.β (c) The domain of the variable π₯ is the set R. The predicate π(π₯) is the sentence β1 β€ π₯ 2 β€ 4.β (d) The domain of the variable π₯ is the set Z. The predicate π(π₯) is the sentence β1 β€ π₯ 2 β€ 4.β [4] The statement βThe square of any rational number is rationalβ can be written formally in at least two ways: 1. βFor all rational numbers π₯, π₯ 2 is rational.β 2. βFor all real numbers π₯, if π₯ is rational, then π₯ 2 is rational.β Notice that in the first version, the domain (the set of rational numbers) is small, and the predicate (βπ₯ 2 is rationalβ) is just a simple statement about the numbers in the domain. And notice that in the second version, the domain is larger, and so the predicate needs to be in the form of a conditional statement, with the hypothsis (βπ₯ is rationalβ) serving to further narrow down the numbers being talked about. The conclusion of the second version (βπ₯ 2 is rationalβ) is the simple statement that was the entire predicate of the first version. The two versions presented above could be generalized to the following two general forms: 1. For all items in some small domain, BLAH. 2. For all items in some larger domain, if the item is in the smaller subset then BLAH. By this notation, I mean that the statement BLAH that is the predicate in the first form is the same as the statement BLAH that is the conclusion of the conditional statement in the predicate of the second form. Rewrite each of the following statements in the two general forms described above. (a) The derivative of any polynomial function is a polynomial function. (b) The negative of any irrational number is irrational. (c) The product of any two rational numbers is rational. The assignment continues on back. ο¨ [5] (Based on suggested problem 3.1 #30) Let π be a variable with domain the set Z of integers. Let πππ(π) be the statement βπ is oddβ. Let πππππ(π) be the statement βπ is primeβ. Let πππ’πππ(π) be the statement βπ is a perfect squareβ. (An integer π is said to be a perfect square if it equals the square of some integer. For example, 9 is a perfect square because 9 = 32 .) Consider the following two statements statement A: βπ such that πππππ(π) β§ ~πππ(π)β. statement B: βπ such that πππ(π) β§ πππ’πππ(π)β. Rewrite each statement without using quantifiers or variables. Determine whether the statements are true or false, and justify your answers as best as you can. [6] (Based on suggested problem 3.1 #30) Let π’, π£, π₯, π¦ be variables with domain the set R of real numbers. Consider the following two statements statement A: π₯π¦ = 0 β π₯ = 0 β¨ π¦ = 0. statement B: π’ < π₯ β§ π£ < π¦ β π’π£ < π₯π¦. Are the statements true or false? Give counterexamples for the statements that are false. [7] (Similar to suggested problem 3.2 #5) Consider the following two statements statement A: Some exercises have answers. statement B: Every rational number is a real number. Write a formal and informal negation for each statement. (Hint: start by rewriting the original statements formally, using variables and quantifiers. Then find the formal negation of the formal original, then finally find the rewrite the formal negation as an informal negation. [8] (Similar to suggested problem 3.2 #19) Write a negation of statement A. statement A: β integers π, if 12/π is an integer, then π = 4. [9] (Similar to suggested problems 3.2 #29) Write the contrapositive, converse, and inverse of statement A from the previous exercise. [10] Consider the five statements π΄, ~π΄, ππππ‘πππππ ππ‘π£π(π΄), ππππ£πππ π(π΄), πππ£πππ π(π΄) from problems [8],[9]. Which of those five statements is true? Explain.