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Copyright © 2005 Pearson Education, Inc. SEVENTH EDITION and EXPANDED SEVENTH EDITION Slide 9-1 Chapter 9 Geometry Copyright © 2005 Pearson Education, Inc. 9.1 Points, Lines, Planes, and Angles Copyright © 2005 Pearson Education, Inc. Basic Terms A line segment is part of a line between two points, including the endpoints. Description Diagram Line AB Ray AB A Copyright © 2005 Pearson Education, Inc. B B A Ray BA Line segment AB Symbol B A A B suur AB uuur AB uuur BA AB Slide 9-4 Plane Any three points that are not on the same line (noncollinear points) determine a unique plane. A line in a plane divides the plane into three parts, the line and two half planes. Any line and a point not on the line determine a unique plane. The intersection of two planes is a line. Copyright © 2005 Pearson Education, Inc. Slide 9-5 Angles The measure of an angle is the amount of rotation from its initial to its terminal side. Angles can be measured in degrees, radians, or, gradients. Angles are classified by their degree measurement. Right Angle is 90° Acute Angle is less than 90° Obtuse Angles is greater than 90° but less than 180 ° Straight Angle is 180° Copyright © 2005 Pearson Education, Inc. Slide 9-6 Types of Angles Adjacent Angles-angles that have a common vertex and a common side but no common interior points. Complementary Angles-two angles whose sum is 90 degrees. Supplementary Angles-two angles whose sum is 180 degrees. Copyright © 2005 Pearson Education, Inc. Slide 9-7 Example If ABC and ABD are supplementary and the measure of ABC is 6 times larger than CBD, determine the measure of each angle. C m ABC + m CBD = 180o 6 x + x = 180 o 7 x = 180 o x = 25.7o Copyright © 2005 Pearson Education, Inc. A B D m ABC = 154.2o m ABD = 25.7o Slide 9-8 More definitions Vertical angles have the same measure. A line that intersects two different lines, at two different points is called a transversal. Special angles are given to the angles formed by a transversal crossing two parallel lines. Copyright © 2005 Pearson Education, Inc. Slide 9-9 Special Names Alternate interior angles Alternate exterior angles Corresponding angles Interior angles on the opposite side of the transversal—have the same measure Exterior angles on the opposite sides of the transversal—have the same measure One interior and one exterior angles on the same side of the transversal-have the same measure Copyright © 2005 Pearson Education, Inc. 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8 Slide 9-10 9.2 Polygons Copyright © 2005 Pearson Education, Inc. Polygons Polygons are names according to their number of sides. Number of Sides Name Number of Sides Name 3 Triangle 8 Octagon 4 Quadrilateral 9 Nonagon 5 Pentagon 10 Decagon 6 Hexagon 12 Dodecagon 7 Heptagon 20 Icosagon Copyright © 2005 Pearson Education, Inc. Slide 9-12 Triangles The sum of the measures of the interior angles of an n-sided polygon is (n − 2)180°. Example: A certain brick paver is in the shape of a regular octagon. Determine the measure of an interior angle and the measure of one exterior angle. Copyright © 2005 Pearson Education, Inc. Slide 9-13 Triangles continued Determine the sum of the interior angles. S = (n − 2)180o = (8 − 2)(180o ) = 6(180o ) = 1080o Copyright © 2005 Pearson Education, Inc. The measure of one interior angle is 1080o o = 135 8 The exterior angle is supplementary to the interior angle, so 180° − 135° = 45° Slide 9-14 Types of Triangles Copyright © 2005 Pearson Education, Inc. Slide 9-15 Similar Figures Two polygons are similar if their corresponding angles have the same measure and their corresponding sides are in proportion. 9 6 4 4 3 Copyright © 2005 Pearson Education, Inc. 6 6 4.5 Slide 9-16 Example Catherine Johnson wants to measure the height of a lighthouse. Catherine is 5 feet tall and determines that when her shadow is 12 feet long, the shadow of the lighthouse is 75 feet long. How tall is the lighthouse? x 5 75 Copyright © 2005 Pearson Education, Inc. 12 Slide 9-17 Example continued ht. lighthouse lighthouse's shadow = ht. Catherine Catherine's shadow x 75 = 5 12 12 x = 375 x = 31.25 x 5 75 12 Therefore, the lighthouse is 31.25 feet tall. Copyright © 2005 Pearson Education, Inc. Slide 9-18 Congruent Figures If corresponding sides of two similar figures are the same length, the figures are congruent. Corresponding angles of congruent figures have the same measure. Copyright © 2005 Pearson Education, Inc. Slide 9-19 Quadrilaterals Quadrilaterals are four-sided polygons, the sum of whose interior angles is 360°. Quadrilaterals may be classified according to their characteristics. Copyright © 2005 Pearson Education, Inc. Slide 9-20 Classifications Trapezoid Two sides are parallel. Copyright © 2005 Pearson Education, Inc. Parallelogram Both pairs of opposite sides are parallel. Both pairs of opposite sides are equal in length. Slide 9-21 Classifications continued Rhombus Rectangle Both pairs of opposite sides are parallel. The four sides are equal in length. Both pairs of opposite sides are parallel. Both pairs of opposite sides are equal in length. The angles are right angles. Copyright © 2005 Pearson Education, Inc. Slide 9-22 Classifications continued Square Both pairs of opposite sides are parallel. The four sides are equal in length. The angles are right angles. Copyright © 2005 Pearson Education, Inc. Slide 9-23 9.3 Perimeter and Area Copyright © 2005 Pearson Education, Inc. Formulas Figure Rectangle Square Parallelogram Triangle Trapezoid Copyright © 2005 Pearson Education, Inc. Perimeter Area P = 2l + 2w A = lw P = 4s A = s2 P = 2b + 2w A = bh P = s1 + s2 + s3 A = 21 bh P = s1 + s2 + b1 + b2 A = 21 h(b1 + b2 ) Slide 9-25 Example Marcus Sanderson needs to put a new roof on his barn. One square of roofing covers 100 ft2 and costs $32.00 per square. If one side of the barn roof measures 50 feet by 30 feet, determine a) the area of the entire roof. b) how many squares of roofing he needs. c) the cost of putting on the roof. Copyright © 2005 Pearson Education, Inc. Slide 9-26 Example continued a) The area of the roof is A = lw A = 30(50) A = 1500 ft2 1500(2 both sides of the roof) = 3000 ft2 b) Determine the number of squares area of roof 3000 = = 30 area of one square 100 Copyright © 2005 Pearson Education, Inc. Slide 9-27 Example continued c) Determine the cost 30 squares × $32 per square $960 It will cost a total of $960 to roof the barn. Copyright © 2005 Pearson Education, Inc. Slide 9-28 Pythagorean Theorem Copyright © 2005 Pearson Education, Inc. Slide 9-29 Example Tomas is bringing his boat into a dock that is 12 feet above the water level. If a 38 foot rope is attached to the dock on one side and to the boat on the other side, determine the horizontal distance from the dock to the boat. 12 ft Copyright © 2005 Pearson Education, Inc. 38 ft rope Slide 9-30 Example continued a2 + b2 = c 2 122 + b 2 = 383 144 + b 2 = 1444 b 2 = 1300 b = 1300 b ≈ 36.06 2 The distance is approximately 36.06 feet. Copyright © 2005 Pearson Education, Inc. Slide 9-31 Circles A circle is a set of points equidistant from a fixed point called the center. A radius, r, of a circle is a line segment from the center of the circle to any point on the circle. A diameter, d, of a circle is a line segment through the center of the circle with both end points on the circle. Copyright © 2005 Pearson Education, Inc. Slide 9-32 Example Terri is installing a new circular swimming pool in her backyard. The pool has a diameter of 27 feet. How much area will the pool take up in her yard? A = πr 2 A = π (13.5)2 A = 572.54 Copyright © 2005 Pearson Education, Inc. The radius of the pool is 13.5 feet. The pool will take up about 573 square feet. Slide 9-33 9.4 Volume Copyright © 2005 Pearson Education, Inc. Volume Volume is the measure of the capacity of a figure. Copyright © 2005 Pearson Education, Inc. Slide 9-35 Formulas Figure Formula Rectangular Solid V = lwh Cube V = s3 Cylinder V = πr2h Cone V = 31 π r 2 h Sphere V = 34 π r 3 Copyright © 2005 Pearson Education, Inc. Diagram Slide 9-36 Example Mr. Stoller needs to order potting soil for his horticulture class. The class is going to plant seeds in rectangular planters that are 12 inches long, 8 inches wide and 3 inches deep. If the class is going to fill 500 planters, how many cubic inches of soil are needed? Copyright © 2005 Pearson Education, Inc. Slide 9-37 Example continued We need to find the volume of one planter. V = lwh V = 12(8)(3) V = 288 in.3 Soil for 500 planters would be 500(288) = 144,000 cubic inches 144,000 = 83.33 ft 3 1728 Copyright © 2005 Pearson Education, Inc. Slide 9-38 Polyhedron A polyhedron is a closed surface formed by the union of polygonal regions. Copyright © 2005 Pearson Education, Inc. Slide 9-39 Euler’s Polyhedron Formula Number of vertices − number of edges + number of faces = 2 Example: A certain polyhedron has 12 edges and 6 faces. Determine the number of vertices on this polyhedron. Number of vertices − number of edges + number of faces = 2 x − 12 + 6 = 2 There are 8 vertices. Copyright © 2005 Pearson Education, Inc. x −6 = 2 x =8 Slide 9-40 Volume of a Prism V = Bh, where B is the area of the base and h is the height. Example: Find the volume of the figure. Area of one triangle. Find the volume. A = 21 bh A = 21 (6)(4) V = Bh V = 12(8) 4m A = 12 m2 8m V = 96 m3 6m Copyright © 2005 Pearson Education, Inc. Slide 9-41 Volume of a Pyramid V = 31 Bh where B is the area of the base and h is the height. Example: Find the volume of the pyramid. Base area = 122 = 144 V = 31 Bh V = 31 (144)(18) 18 m V = 864 m3 12 m 12 m Copyright © 2005 Pearson Education, Inc. Slide 9-42 9.5 Transformational Geometry, Symmetry, and Tessellations Copyright © 2005 Pearson Education, Inc. Definitions The act of moving a geometric figure from some starting position to some ending position without altering its shape or size is called a rigid motion (or transformation). Copyright © 2005 Pearson Education, Inc. Slide 9-44 Reflection A reflection is a rigid motion that moves a a geometric figure to a new position such that the figure in the new position is a mirror image of the figure starting position. In two dimensions the figure and its mirror image are equidistant from a line called the reflection line or the axis of reflection. Copyright © 2005 Pearson Education, Inc. Slide 9-45 Construct the reflection of triangle ABC about the line l. A C A C B l 2 units B 2 units B’ l C’ A’ Copyright © 2005 Pearson Education, Inc. Slide 9-46 Translation A translation (or glide) is a rigid motion that moves a geometric figure by sliding it along a straight line segment in the plane. The direction and length of the line segment completely determine the translation. Copyright © 2005 Pearson Education, Inc. Slide 9-47 Example Copyright © 2005 Pearson Education, Inc. Slide 9-48 Example continued Copyright © 2005 Pearson Education, Inc. Slide 9-49 Rotation A rotation is a rigid motion performed by rotating a geometric figure in the plane about a specific point, called the rotation point or the center of rotation. The angle through which the object is rotated is called the angle of rotation. Copyright © 2005 Pearson Education, Inc. Slide 9-50 Example Copyright © 2005 Pearson Education, Inc. Slide 9-51 Example continued Copyright © 2005 Pearson Education, Inc. Slide 9-52 Glide Reflection A glide reflection is a rigid motion formed by performing a translation (or glide) followed by a reflection. Copyright © 2005 Pearson Education, Inc. Slide 9-53 Example Copyright © 2005 Pearson Education, Inc. Slide 9-54 Symmetry A symmetry of a geometric figure is a rigid motion that moves a figure back onto itself. That is, the beginning position and ending position of the figure must be identical. Copyright © 2005 Pearson Education, Inc. Slide 9-55 Example Copyright © 2005 Pearson Education, Inc. Slide 9-56 Tessellations A tessellation (or tiling) is a pattern of the repeated use of the same geometric figures to entirely cover a plane, leaving no gaps. The geometric figures use are called the tessellating shapes of the tessellation. Copyright © 2005 Pearson Education, Inc. Slide 9-57 Example The simplest tessellations use one single regular polygon. Copyright © 2005 Pearson Education, Inc. Slide 9-58 Example continued Copyright © 2005 Pearson Education, Inc. Slide 9-59