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Physics 125 Solar System Astronomy James Buckley [email protected] Lecture 3 The Big Picture from the Big Bang to Our Solar System (Part II) Reading Quiz 2 Circular acceleration • Answer BOTH questions -True or False: The Stars, unlike the sun, tend to rise in the West and set in the East -Ancient peoples built stone or wood structures to mark •the seasons, e.g., on the summer solstice, the sun ∆⃗vthe line of site of two appears on the Horizon along ⃗a = ∆t or two, describe why stone monoliths. In a sentence this alignment only occurs two times a year. Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Angles Circular acceleration Arclength s = D ✓ D ✓/2 ✓ a/2 = D sin(✓/2) a/2 s For small angles sin ⇡ a/2 ⇡ D (✓/2) a ⇡ D✓ • To make the following formulas work, we need to measure angules in radians, not degrees. Recall: there are 2⇡ radians in 360 ∆⃗ v ⃗a = ∆t • The separation of two stars, or two sides of a planet appear to us as an angle (that’s what cameras and eyes really see). Angles map into positions on the film, or retina - we don’t really measure size. Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Back-Yard Astronomy Tip #1 Circular acceleration Measuring Angles • ∆⃗v ⃗a = ∆t • Measuring angles Physics 312 - Lecture 4 – p.3/?? Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Star Formation Circular acceleration • ∆⃗v ⃗a = ∆t • Iconic Hubble image of the “pillars of creation’’ in the Eagle Nebula where molecular clouds (H2, CO, even organic molecules) are collapsing under self gravity to form new stars. Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Jean’s acceleration Instability Circular Molecule with KE>PE • Molecule with KE<PE ∆⃗v ⃗a = ∆t get collapse • If pressure not sufficient to hold off gravity, • Another way of looking at this is that there is some radius (and enclosed mass) for which molecules (at a given Temperature) do not have enough kinetic energy to escape gravity. This radius is called the Jean’s radius and the enclosed ass called the Jean’s mass. Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Star Formation Circular acceleration Pleiades • ∆⃗v ⃗a = Orion Nebula ∆t • You can find star formation regions in Orion, or see young stars in the Pleiades (the blue glow is due to ionization of the surrounding gas by UV light from the young stars) Trapezium Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Collapse Circular acceleration Pressure Gravity • Gravitational attraction makes cloud collapse and heat-up, emitting black-body radiation (protostar) • The heat of collapse results in an increase in random motion of the gas atoms, increasing temperature and pressure • • Eventually random thermal velocities are high enough and densities high enough that Hydrogen atoms can overcome their repulsion and fuse ∆⃗v to form Helium, liberating mass as ⃗aenergy = ∆t • A star is born! Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Pressure Circular acceleration • ∆⃗v ⃗a = ∆t • Gravity compresses gas, like a piston making particles speed up and density and pressures increase Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Sustained Fusion in Stars Circular acceleration • As velocity (kinetic energy) and density increases, the probability of two hydrogen nuclei hitting each other really hard increases. • If they hit hard enough, they can overcome the electric repulsion (like charges repel), and strong nuclear forces take over, making them stick together in a different nucleus ⌫ 1 H• e+ 2 1 H Step 1 e 2 H 1 H H 3 3 ∆⃗v He ⃗a = Step 2 He ∆t 4 3 He He + 1 + H 1 H Step 3 Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Hydrogen Bomb Circular acceleration • ∆⃗v ⃗a = ∆t • Hydrogen bombs are the most energetic man-made terestrial events, with typical energy release equal to 1Mton of TNT (4.2 Giga-Joules) Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Fusion Energy Circular acceleration Fusion: H-Bomb: • Solar luminosity is 3.826x1026 Watts • • 1 megaton of TNT (typical H-bomb) releases 4x1015 Joules. So sun’s ∆⃗v 26 output in “H-bomb” units is (3.8 x10 / ⃗a = 4.0 x1015) J or about 100 billion ∆t H-bombs a second! • More than just an arbitrary unit, the sun really is 100 billion H-bombs worth of Hydrogen fusion a second, with all the associated radiation! Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Fusion Power Math Time! Circular acceleration E = m c2 Mass of a hydrogen atom, mH = 1.673 ⇥ 10 Mass of a helium atom, mHe = 6.645 ⇥ 10 27 27 kg kg Speed of light, c = 2.998 ⇥ 108 m/s m = (4 ⇥ mH ) E = m c2 = 4.7 ⇥ 10 = = •6⇥10 26 mHe = 4.7 ⇥ 10 29 4.22 ⇥ 10 4.22 ⇥ 10 29 kg kg ⇥ (2.998 ⇥ 108 m/s)2 12 kg m2 /s2 12 J hydrogen atoms in a kg 1 Joule = 1 W sec (1 hr /3600 sec)(1 kW ∆⃗ /v 1000 W) ⃗a = ✓ ◆✓ ◆ 26 ∆t 1 kW hr 6 ⇥ 10 H atoms Energy per kg = 4.22 ⇥ 10 12 J/reaction 3.6 ⇥ 106 J 4 H atoms/reaction = 1.8 ⇥ 108 kW hr An average American household uses about 1000 kW hr per month, so on kg of Hydrogen fuel could power a small city (200 thousand) households for one month. Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Fusionacceleration Enery on Earth Circular • ∆⃗v ⃗a = ∆t • Promise of fusion energy, the ultimate clean infinite source of energy, still remains far out of reach. Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Discussion question: Circular acceleration • ∆⃗v ⃗a = ∆tSocrative, check ALL correct • Discuss the answers, and using answers (there could be more than one or zero!) Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 How do you know? Circular acceleration • If you were an ancient Greek, with no modern technology (no telescopes, internet, GPS, electronic clocks, computers or modern transportation how would you know: - The earth is round? - How big the moon and sun are? How far away? - That we orbit the sun, and not (what we observe) that the sun orbits us? the earth is spinning? - That • ∆⃗v suns? other - That the points of light in the sky⃗aare = ∆t - How far away those stars are? Are they other suns? - And yet, the ancient greeks DID know these things! Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Library of Alexandria Circular acceleration • ∆⃗v ⃗a = ∆t • World’s first Research institute, established by Aristotle, tutor of Alexander the Great under his patronage. Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Library of Alexandria Circular acceleration • The library of Alexandria thrived between the 4th century BC and Roman and continued until about 400 AD (surviving several fires) until it was finally destroyed (probably in one great fire). • The library contained as many as a million scrolls with writings of great astronomers and mathematicians like Euclid, Archimedes, Erastothenes, Hipparchus, Aristarchus of Samos. • The details remain unclear, but is likely that the library was destroyed near the beginning of the 5th century AD. The destruction may have occurred near the time that Hypatia, a leading (female) philosopher of the Greek Alexandrian tradition was brutally murdered (dragged behind a carriage) by a•Christian mob, perhaps upset by a dispute between the prefect Orestes ∆⃗v and Hypatia, or about their and Bishop over the “pagan” beliefs⃗aof=Orestes ∆t support of the Jewish population • The great intellectual achievements of Hypatia, and the story of her brutal murder (even as Christian writers of the time admired her intellect inspired the name of the Feminist journal “Hypatia: A Journal of Feminist Philosophy) Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Aristotle and Plato Circular acceleration Plato (424-348 BCE) Aristotle (384-322 BCE) • establishing a school of • Aristotle (and Plato) was a brilliant philosopher, ∆⃗v ⃗a =century. thought that persisted through the 15th ∆t • Made important contributions to Philosophy, but not so much for the Physical sciences (and Astronomy). In fact they did some harm - so we will skip them and get to the story of the Ancient Greeks that actually matter for Astronomy! Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Aristarchus of Samos Circular acceleration • Aristarchus lived on the Greek island of Samos (310-230 BC) • Postulated that planets orbited sun not Earth. • Devised methods to measure Samos size of the Earth, size and distance of the Moon and Sun. • Deduced that stars are other suns but at enormous distances “Aristarchus has brought out a book consisting of certain hypotheses, wherein • it appears, as a consequence of the assumptions made, that the universe is ∆⃗ v hypotheses are that many times greater than the ‘universe’ just mentioned. His ⃗a = ∆t revolves about the the fixed stars and the sun remain unmoved, that the earth sun on the circumference of a circle, the sun lying in the middle of the orbit, Contributed by Vae Isakhanian, EYAD, G and others and that the sphere of fixed stars, situated about©2014 theGoogle same· center as the sun, is Basarsoft, ORION-ME, TerraMetrics · Terms of Use 100 km so great that the circle in which he supposes the earth to revolve bears such a proportion to the distance of the fixed stars as the centre of the sphere bears to its surface.” - Archimedes (287-212 BC) Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Distance to Moon and Sun Circular acceleration 3 deg 87 deg • • Aristarchus argued that angle between the moon and sun when the moon was exactly half full ∆⃗v estimated the angle at ~ 87 deg so could be used to compute ratio of distances. Aristarchus ⃗a = the ratio of distances was sin(3 deg). Trig was not invented ∆t yet, so he used an inequality 1/18>sin(3)>1/20 (based on right triangles). • He deduced sun was 18 to 20 times as far away as the moon. Actually, the angle between the half moon and sun is 89.83 deg and sun is about 400 times as far as the moon - but the method was sound (Aristarchus also estimate the radius of the Sun from the angular size) Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Relative Size of Earth and Moon Circular acceleration • ∆⃗v ⃗a = ∆t a lunar eclipse gives a • Curvature of shadow of Earth during rough estimate of the relative radius of the earth and moon. • Angular size of moon is about 0.5 deg??? Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Aristarchus, continued Circular acceleration 10th century copy of Aristarchus’ calculations of the relative sizes of the sun earth and moon. • ∆⃗v ⃗a = ∆t • Knowing the ratio of distances from the Earth to the Sun and moon, Aristarchus used the size of the shadow relative to the moon at a Lunar Eclipse, an the fact that the Earth and Sun have about the same angular size (0.5 deg) at eclipse to measure the relative radii of the Sun, Earth and Moon and the relative distances Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Radiusacceleration of Earth Circular • Erastothenes of Cyrene (modern day Libya) (276-194 BC) was a Greek mathematician, astronomer, Librarian of Alexandria, friend of Archimedes. • Sun visible at bottom of well, vertical sticks cast no shadow in Syene on summer solstice at local noon. In Alexandria on same day, a stick cast a measurable shadow. • From measurements of shadows in Alexandria, the zenith angle of the sun corresponded to 1/50 •circle of 7.2 deg south of zenith> Sun’s Rays 7.2 deg Alexandria ∆⃗v • Assuming Alexandria due north of Syene, ⃗a = ∆t distance to Syene must be 1/50 circumference of the Earth. With a distance of 5000 stadia => 700 stadia per deg, a circumf of 252,000 stadia. 1 stadium ~ 185m giving a circumference of 46620 km, only 16.3% too large! Syene Radius of t 7.2 deg Diamete • Erastothenes of Cyrene (modern day Libya Greek mathematician, astronomer, Librari friend of Archimedes. • Sun visible at bottom of a well, vertical sti in Syene on the summer solstice at local n on the same day, a stick cast a measurable • From measurements of shadows in Alexan elevation of the Sun corresponded to 1/50 south of the zenith at the same time. Physics 125, J. Buckley Alexandria was due north of Sy • Assuming Physics 312 - Lecture 1 – p. 25/27 Hyparchus’ Lunar Distance Circular acceleration ✓ Alexandria Earth ✓ Syene Moon visible Blocked from Sun view (Alexandria) • Hyparchus (190-120 BC) used the different appearance of a solar eclipse from Syene (total) and Alexandria (partial) to determine the distance from the Earth to•Moon. ∆⃗v = in Alexandria saw 1/5 of the sun. • During the total eclipse in Syene, an⃗aobserver ∆t • Angular size of the sun is ⇡ 0.5 , so ✓ ⇡ 1/10 • He derived that the distance to the moon Dm was related to the distance between the two cities D, by D = Dm ✓ Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Geocentric Universe Circular acceleration Figure from a 16th century Portugese Cartographer showing the Ptolemeic geocentric system • But • Hipparchus rejected the ideas of Aristarchus and others, and adopted a Heliocentric model (as introduced by Plato ∆⃗v(424-348 BC) and Aristotle (384-322) ⃗a =by Ptolemy (384-322 BC) in the 4th century BC), and formalized ∆t • The Planets (or Wanderers) were star-like objects that seemed to move with respect to background stars. • In the time of Hipparchus, and later formalized by Ptolemy Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Planetsacceleration and Epicycles... Circular • ∆⃗v ⃗a = ∆t Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Summary Circular acceleration • Sun and moon have about the same angular size (0.5 deg) • Aristarchus derived a number of geometric methods for determining the relative size and distances of the Sun, Earth, Moon system and postulated a Heliocentric solar system, and even that stars were other suns. His numbers were off, only due to his limited ability to measure the angle between half moon and sun. • Erastothenes devised an accurate method for deriving the radius of the earth. • Hipparchus repeated and improved on Aristarchus’ methods and came up with pretty • accurate estimates for the size of the solar system - but he believed in a Geocentric system ∆⃗v ⃗a = to the destruction of many important • The burning of the library of Alexandria led∆t documents. Some Muslim scholars had translated some works (Aristotles, in particular) into Arabic. These were later translated into Latin after most of the original Greek copies were destroyed (referred to as the Recovery of Aristotle in the middle ages) Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Parallax Distance Parallax Circular acceleration 1 AU d= tan p d 1 AU p 1 pc p” • By definition, a star at a distance of one parsec (1 pc) will have a parallax angle of one arcsec (1”) • 1 pc = 3.08568025 x 1018 cm • 1 pc = 3.26163626 ly •∆⃗ v ⃗a = Nearest star, Proxima Centauri, •∆t has a parallax angle of 0.77” and a distance of 1.3 pc or 4.2 ly Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Distance to Planets Parallax distance S un E arth M ercu ry ! Venus transit, APOD July 20, 2004 Relative scales of the solar system Planet Period (years) Approx. Radius (a.u.) Earth 1.0 1.0 Mercury 0.241 0.39 Venus 0.615 0.72 Mars 1.881 1.5 Jupiter 11.86 5.2 Physics 312 - Lecture 3 – p.9/12 Venus transit, Crow Observatory, June 5, 2012 Mercury Transit Circular acceleration • ∆⃗v ⃗a = ∆t • Mercury transits occur more often, but Mercury is closer to the sun and it is hard to measure the parallax Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 3 Future and past 4 See also 5 References 6 External links Nearest Stars Nearestacceleration Stars Circular List Designation # 1 System Star Solar System Sun Alpha Centauri (Rigil Kentaurus; Toliman) Additional references 180° 0.000015 has 8 planets variable: the Sun travels along the ecliptic 14h 29m 43.0s !62° 40! 46" 0.768 87(0 29)"[5][6] 4.2421(16) # Centauri A (HD 128620) 2 G2V [2] 0.01[2] 14h 39m 36.5s !60° 50! 02" # Centauri B (HD 128621) 2 K1V [2] 1.34[2] 5.71[2] 14h 39m 35.1s !60° 50! 14" 4 M4.0Ve 9.53[2] 13.22[2] 17h 57m 48.5s +04° 41! 36" 0.546 98(1 00)"[5][6] 5.9630(109) 5 M6.0V[2] 13.44[2] 16.55[2] 10h 56m 29.2s +07° 00! 53" 0.419 10(2 10)"[5] 6 M2.0V[2] 11h 03m 20.2s +35° 58! 12" 0.393 42(0 70)"[5][6] 8.2905(148) 06h 45m 08.9s !16° 42! 58" 0.380 02(1 28)"[5][6] 8.5828(289) 01h 39m 01.3s !17° 57! 01" 0.373 70(2 70)"[5] 4 Lalande 21185 (BD+36°2147) • Declination [2] Distance[4] Light-years (±err) 11.09[2] 15.53[2] Wolf 359 (CN Leonis) Luyten 726-8 Right ascension[2] Parallax[2][3] Arcseconds(±err) M5.5Ve 3 6 G2V [2] !26.74 [2] 4.85[2] Epoch J2000.0 1 Barnard's Star (BD+04°3561a) Sirius (# Canis Majoris) Apparent Absolute magnitude magnitude (m V ) (M V ) Proxima Centauri (V645 Centauri) 2 5 Star # Stellar class 4.38[2] 0.747 23(1 17)"[5][8] 4.3650(68) 7.47[2] 10.44[2] Sirius A 7 A1V [2] !1.46 [2] 1.42[2] Sirius B 7 DA2 [2] 8.44[2] 11.34[2] Luyten 726-8 A (BL Ceti) 9 M5.5Ve 12.54[2] 15.40[2] Luyten 726-8 B (UV Ceti) [7] 10 M6.0Ve 12.99[2] 7.7825(390) 8.7280(631) 15.85[2] ∆⃗v a =23 41 54.7 14.79⃗ ∆t 7 Ross 154 (V1216 Sagittarii) 11 M3.5Ve 10.43[2] 13.07[2] 8 Ross 248 (HH Andromedae) 12 M5.5Ve 12.29[2] 9 Epsilon Eridani (BD!09°697) 13 K2V [2] 3.73[2] 6.19[2] 03h 32m 55.8s has two !09° 27! 30" 0.309 99(0 79)"[5][6] 10.522(27) proposed planets 10 Lacaille 9352 (CD!36°15693) 14 M1.5Ve 7.34[2] 9.75[2] 23h 05m 52.0s !35° 51! 11" 0.303 64(0 87)"[5][6] 10.742(31) 11 Ross 128 (FI Virginis) 15 M4.0Vn 11.13[2] 13.51[2] 11h 47m 44.4s +00° 48! 16" 0.298 72(1 35)"[5][6] 10.919(49) 16 M5.0Ve 13.33[2] 15.64[2] 12 EZ Aquarii (GJ 866, Luyten 789-6) • EZ Aquarii A [2] 18h 49m 49.4s h m s !23° 50! 10" 0.336 90(1 78)"[5][6] 9.6813(512) +44° 10! 30" 0.316 00(1 10)"[5] [2] 15.58 [2] M? !15°encyclopedia 18! 07" 0.289 50(4 40)"[5] 13.27 22h 38m the 33.4s free List 16 of nearest stars - Wikipedia, EZ Aquarii B List of nearest and14.03 parallax [2] 16.34[2] (from Wikipedia) EZ Aquarii C stars 16 M? Procyon 13 (# Canis Minoris) Procyon A 19 F5VIV[2] 0.38[2] 2.66[2] 07h 39m 18.1s 10.322(36) 11.266(171) Physics 125, J. Buckley +05° 13! 30" 0.286 05(0 81)"[5][6] 11.402(32) Physics 312 - Lecture 1 – p. 25/27 Local (Horizon) Coordinates Circular acceleration • ∆⃗v ⃗a = ∆t • Zenith is the point directly over head, the Meridian is the line going through points due south and due north, passing through the zenith. Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Path ofacceleration Sun Throughout Year Circular • ∆⃗v ⃗a = but during the course of the year, it • The Sun rises in the East, Sets in the West, ∆t appears to get higher in the sky (during summer) and cross the Horizon at different Points. • Ancient structures marked times of year, by aligning objects with the position that the Sun crossed the Horizon in different seasons. Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Summary Circular acceleration • The Universe started with the big bang! • There are 100 billion stars in the galaxy, and 100 billion galaxies in the visible universe. • Dark matter is the main gravitational mass, responsible for galaxy formation. • Stars are powered by nuclear fusion, ignited by very high temperatures and pressures from gravitational collapse. ••Our solar system is composed of inner, terrestrial planets and outer ∆⃗v gas giants, but is mostly empty space! ⃗a = ∆t • Going back to ancient time, we have come up with many ingenious ways to measure our Universe, without ever leaving our planet (or surfing the web). • Reading assignment: Sections 2.1, 2.2, 3.1 and 3.2 Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27 Planetsacceleration in the Night Sky Circular • Compared with stars, planets: - Are often quite bright - Twinkle less than stars becaues they are “extended” Mars • ⃗a = - Move relative to stars over ∆⃗v the course of nights, years ∆t • Greeks called planets “Wanderers” • Venus, Mars, Jupiter and Saturn all clear to the naked eye. Physics 125, J. Buckley Physics 312 - Lecture 1 – p. 25/27