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A differential equation is used to find the rate at which something is changing at a certain point. It is used to find an unknown function based on the dy/dx equation that is given as well as a certain x and y value. Steps 1. 2. 3. 4. Separate Variables Integrate both sides (don’t forget the “+C”) Substitute and solve for “C” Plug in “C” and solve for y Example 1 Find y=f(x) when dy/dx=x2y2, and x=1 when y=1 Step 1 1 dy =x2dx or y-2dy=x2dx 2 y Step 2 ∫y-2dy=∫x2dx Step 3 (1,1) -(1)-1=⅓ (1)3+C -1=⅓+C C=-4/3 Step 4 -y-1=⅓x3-4/3 y-1=-⅓x3+4/3 y=(-⅓x3+4/3)-1 -y-1=⅓x3+C Example 2 Find y=f(x) when dy/dx=-x/y, with the point (0,5) Step 1 ydy=xdx Step 2 ∫ydy=∫xdx Step 3 (0,5) ½(5)2=½ (0)2+C ½(25)=0+C 12.5=C Step 4 ½y2=½x2+12.5 y2=x2+25 y=√x2+25 ½y2=½x2+C Practice Problems Non-Calculator Multiple Choice 1) What is the particular solution of the equation dy/dx=xy with y(2)=4 A. √x2+6 B. -√x2+12 C. √x2+12 D. -√x2+6 E. x+√12 Short Answer Consider the curve given by x2+3y2=1+3xy. 1) Show that dy/dx=3y-2x/6y-3x Consider the differential equation dy/dx=x2(2y+1) 2) Find the particular solution y=f(x) to the given differential equation with the initial condition f(0)=5. Answer Key Multiple Choice: Choice C Short Answer 1) 2x+6ydy/dx=0+3xdydx+3y 6ydy/dx-3xdy/dx=3y-2x dy/dx(6y-3x)=3y-2x dy/dx=37-2x/6y-3x 2) dy/dx=x2(2y+1) dy=x2(2y+1)dx (1/(2y+1))dy=x2dx ln(2y+1)=⅓x3+C ln(2(5)+1)= ⅓(0)3+C ln(11)=C ln(2y+1)= ⅓x3+ln(11) 2y+1=e^(x3/3)*11 2y=11e^(x3/3)-1 y=½(11e^(x3/3)-1)