Download Chapter 15 Review - Blue Valley Schools

Chapter 15 Review
1
Based on the results of this cross, you determine that
A
B
C
D
E
2
The results of the following cross indicate that the
A
B
C
D
E
3
the allele for round eyes is linked to the allele for no tooth.
round eyes are dominant to vertical eyes, and the absence of a tooth is
dominant to the presence of a tooth.
round eyes are dominant to vertical eyes, and the presence of a tooth is
dominant to the absence of a tooth.
vertical eyes are dominant to round eyes, and the absence of a tooth is
dominant to the presence of a tooth.
vertical eyes are dominant to round eyes, and the presence of a tooth is
dominant to the absence of a tooth.
two genes are linked.
MendAlien species is polyploid.
two genes assort independently.
absence of a tooth is dominant to vertical eyes.
absence of a tooth is dominant to the presence of a tooth.
An F1 individual can produce _____ different gametes when both eye and tooth genes are
considered.
A
B
C
D
E
1
2
3
4
5
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Page 1
Chapter 15 Review
4
Page 2
Given these chromosomes, which of the choices represents the possible recombinant
gametes?
A
B
C
D
E
5
The results of a F1 testcross are: 250 bald head, four ears : 247 hairy head, six ears : 21
bald head, six ears : 19 hairy head, four ears. How many map units apart are the head and
ear genes?
A
B
C
D
E
3.5
3.9
7.5
50.5
92.6
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Chapter 15 Review
6
Which of the individuals is homozygous recessive for both of the gene pairs?
A
B
C
D
E
7
The results of the following cross indicates that the
A
B
C
D
E
8
two genes are linked.
MendAlien species is polyploid.
two genes assort independently.
absence of a tooth is dominant to vertical eyes.
absence of a tooth is dominant to the presence of a tooth.
The recombination frequency between gene A and gene B is 8.4%, the recombination
frequency between gene A and gene C is 6.8%, and the recombination frequency between
gene B and gene C is 15.2%. Which of these is the correct arrangement of these genes?
A
B
C
D
E
9
the male parent
the F1 generation
the female parent
both the male and female parents
both the male parent and the F1 generation
ABC
ACB
BCA
CAB
CBA
A color-blind woman mates with a male with normal color vision. Which of these results
would indicate that color blindness is caused by an X-linked recessive allele?
A
B
C
D
E
Half of the sons and half of the daughters are color-blind.
All of the daughters, and none of the sons, are color-blind.
All of the sons, and none of the daughters, are color-blind.
The offspring occur in a ratio of 3 color-blind : 1 normal vision.
The offspring occur in a ratio of 9 normal vision males : 3 color-blind vision
males : 3 normal vision females : 1 color-blind female.
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Page 3
Chapter 15 Review
10
Color blindness is an X-linked recessive trait. A color-blind man has a daughter with normal
color vision. What is the genotype of the daughter?
A
B
C
D
E
11
All the offspring have normal color vision.
3 normal vision female : 1 color-blind male
1 normal vision female : 1 color-blind male
2 normal vision females : 1 normal vision male : 1 color-blind male
1 normal vision female : 1 color-blind female : 1 normal vision male : 1
color-blind male
Color blindness is an X-linked recessive trait. A color-blind man has a daughter with normal
color vision. She mates with a color-blind male. What is the expected phenotypic ratio of
their offspring?
A
B
C
D
E
13
XcY
XCY
XcXc
XCXC
XCXc
Color blindness is an X-linked recessive trait. A color-blind man has a daughter with normal
color vision. She mates with a male who has normal color vision. What is the expected
phenotypic ratio of their offspring?
A
B
C
D
E
12
Page 4
All the offspring have normal color vision.
3 normal vision female : 1 color-blind male
1 normal vision female : 1 color-blind male
2 normal vision females : 1 normal vision male : 1 color-blind male
1 normal vision female : 1 color-blind female : 1 normal male : 1 color-blind
male
Color blindness is an X-linked recessive trait. A woman who is homozygous for normal color
vision mates with a color-blind male. What is the expected phenotypic ratio of their
offspring?
A
B
C
D
E
All the offspring have normal color vision.
1 normal vision female : 1 color-blind male
3 normal vision female : 1 color-blind male
2 normal vision females : 1 normal vision male : 1 color-blind male
1 normal vision female : 1 color-blind female : 1 normal male : 1 color-blind
male
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Chapter 15 Review
14
Color blindness is an X-linked recessive trait. A color-blind woman mates with a male with
normal color vision. What is the expected phenotypic ratio of their offspring?
A
B
C
D
E
15
He can't.
His mate is color-blind.
His father is color-blind.
His mother is color-blind.
He is heterozygous for color vision.
Hypophosphatemia (vitamin D-resistant rickets) is inherited as an X-linked dominant. An
unaffected woman mates with a male with hypophosphatemia. What is the expected
phenotypic ratio of their offspring?
A
B
C
D
E
17
All the offspring have normal color vision.
3 normal vision female : 1 color-blind male
1 normal vision daughter : 1 color-blind son
2 normal vision females : 1 normal-vision male : 1 color-blind male
1 normal vision female : 1 color-blind female : 1 normal male : 1 color-blind
male
Color blindness is an X-linked recessive trait. Under what conditions can an unaffected male
have a color-blind daughter?
A
B
C
D
E
16
Page 5
3 normal female : 1 male with hypophosphatemia
1 daughter with hypophosphatemia : 1 normal son
1 normal daughter : 1 son with hypophosphatemia
2 normal females : 1 normal male : 1 male with hypophosphatemia
1 normal female : 1 female with hypophosphatemia : 1 normal male : 1
male with hypophosphatemia
Hypophosphatemia (vitamin D-resistant rickets) is inherited as an X-linked dominant. A
woman without hypophosphatemia and a man with hypophosphatemia have a daughter.
The daughter mates with a male without hypophosphatemia. What is the expected
phenotypic ratio of their offspring?
A
B
C
D
E
1 unaffected daughter : 1 son with hypophosphatemia
1 daughter with hypophosphatemia : 1 unaffected son
3 unaffected females : 1 male with hypophosphatemia
2 unaffected females : 1 unaffected male : 1 male with hypophosphatemia
1 unaffected female : 1 female with hypophosphatemia : 1 unaffected male :
1 male with hypophosphatemia
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Chapter 15 Review
18
Suppose that having three nostrils is a dominant Y-linked character. A woman with two
nostrils mates with a man with three nostrils. What is the expected phenotypic ratio of their
offspring?
A
B
C
D
E
19
12
23
36
45
92
_____ is the process by which haploid gametes form a diploid zygote.
A
B
C
D
E
22
1
2
3
4
5
Humans are diploid and have 46 chromosomes. How many chromosomes are found in each
human gamete?
A
B
C
D
E
21
1 daughter with two nostrils : 1 son with three nostrils
2 daughters with two nostrils: 1 son with two nostrils: 1 son with three
nostrils
2 daughters with three nostrils: 1 son with two nostrils: 1 son with three
nostrils
2 sons with two nostrils: 1 daughter with two nostrils: 1 daughter with three
nostrils
1 daughter with two nostrils: 1 daughter with three nostrils: 1 son with two
nostrils : 1 son with three nostrils
Humans are diploid and have 46 chromosomes (or two sets). How many sets of
chromosomes are found in each human gamete?
A
B
C
D
E
20
Page 6
Mitosis
Meiosis
Fertilization
Gastrulation
Embryogenesis
A particular diploid plant species has 48 chromosomes, or two sets. A mutation occurs and
gametes with 48 chromosomes are produced. If self-fertilization occurs, the gametes will
have _____ set(s) of chromosomes.
A
B
C
D
E
1
2
3
4
5
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Chapter 15 Review
23
Which of these terms applies to an organism with extra sets of chromosomes?
A
B
C
D
E
24
Mutant tetraploid plants
A
B
C
D
E
25
diploid
haploid
trisomy
polyploid
monosomy
are usually sickly.
are unable to self-fertilize.
have an odd number of chromosomes.
are able to interbreed with their parents.
are unable to interbreed with a diploid plant.
Most polyploid plants arise as a result of
A
B
C
D
E
mitosis.
meiosis.
hybridization.
self-fertilization.
a mutation of gamete formation.
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Chapter 15 Review
Page 8
Answer Key : Chapter 15 Review
Question:
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Answer
B
C
D
D
C
C
A
D
C
E
E
E
A
C
A
B
E
A
A
B
C
D
D
E
C