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Theorems About Roots of Polynomial Equations 5-5 Vocabulary Review 1. Write L if the polynomial is linear, Q if it is quadratic, or C if it is cubic. 3x 1 x2 2x3 2 7x2 1 x 14 2 x Vocabulary Builder root (noun) root Related Words: factor, solution, zero, x-intercept Main Idea: A root is a solution of an equation. It is an x-intercept of the related function, which is why it can be called a zero. If (x 2 a) is a factor of a polynomial, then a is a root of that polynomial. Use Your Vocabulary Write T for true or F for false. 2. 1 and 21 are roots of the equation x2 5 1. 3. The equation x2 2 4x 1 4 5 0 has roots 4 and 24. Write the number of roots each polynomial has. 4. 3x4 2 2x2 1 17x 2 4 Theorem 5. 12x5 1 x7 2 8 1 4x2 6. 15 1 6x Rational Root Theorem Let P(x) 5 anxn 1 an21xn21 1 c 1 a1x 1 a0 be a polynomial with integer coefficients. Then there are a limited number of possible roots of P(x) 5 0. Integer roots must be factors of a0 . p Rational roots must have a reduced form q , where p is an integer factor of a0 and q is an integer factor of an . Chapter 5 134 Copyright © by Pearson Education, Inc. or its affiliates. All Rights Reserved. Definition: A root of an equation is a value that, when substituted for the unknown quantity, satisfies the equation. What are the possible rational roots of 15x4 2 3x 1 8? 7. Identify a0 and an . a0 5 an 5 9. List the factors of the leading coefficient, an . 8. List the factors of the constant, a0 . 4 ,4 ,4 ,4 4 , ,4 ,4 ,4 , 10. Circle the possible rational roots. 5 4 2 5 215 2 3 Problem 2 Using the Rational Root Theorem Got It? What are the rational roots of 2x3 1 x2 2 7x 2 6 5 0? Underline the correct number(s) to complete each sentence. 11. The leading coefficient is 0 / 2 / 1 / 7 / 26 . 12. The constant is 0 / 2 / 1 / 7 / 26 . 13. The factors of the leading coefficient are 0 / 21 / 1 / 22 / 2 / 23 / 3 / 26 / 6 . 14. The factors of the constant are 0 / 21 / 1 / 22 / 2 / 23 / 3 / 26 / 6 . Copyright © by Pearson Education, Inc. or its affiliates. All Rights Reserved. 15. Cross out the numbers that are NOT possible rational roots. 1 3 21 0 1 2 16. Try the easiest possible roots. P(1) 5 P(21) 5 17. Since 1 / 21 is a root, x 1 1 / x 2 1 is a factor of 2x3 1 x2 2 7x 2 6 5 0. 18. Use synthetic division to find another factor. 21 2 1 27 19. The quotient is . 26 2 20. Use the quadratic formula to find the remaining factors. 2b 4 "b2 2 4ac 5 2a 5 4 4 " 2 4Q 5 RQ R 5 4 " 2 or 21. The rational roots of 2x3 1 x2 2 7x 2 6 5 0 are 135 , , and . Lesson 5-5 Theorem Conjugate Root Theorem If P(x) is a polynomial with rational coefficients, then the irrational roots of P(x) 5 0 occur in conjugate pairs. That is, if a 1 !b is an irrational root with a and b rational, then a 2 !b is also a root. If P(x) is a polynomial with real coefficients, then the complex roots of P(x) 5 0 occur in conjugate pairs. That is, if a 1 bi is a complex root with a and b real, then a 2 bi is also a root. 22. Write the conjugate of each root. 1 1 3i Problem 3 4 2 !7 22 2 9i 15 1 !10 Using the Conjugate Root Theorem to Identify Roots Got It? A cubic polynomial P(x)has real coefficients. If 3 2 2i and 52 are two roots of P(x) 5 0, what is one additional root? 23. Place a ✓ if the Conjugate Root Theorem could be applied to the following types of roots. Place an ✗ if it could not be. Rational Irrational Complex 24. Write R if the root is rational, I if it is irrational, or C if it is complex. 25. By the Conjugate Root Theorem, Problem 4 is an additional root. Using Conjugates to Construct a Polynomial Got It? What is a quartic polynomial function with rational coefficients for the roots 2 2 3i, 8, 2? Underline the correct word or number to complete each sentence. 26. A quartic polynomial has 1 / 2 / 3 / 4 roots. 27. Since 2 2 3i is a root, is also a root. 28. Write P(x) as the product of four binomials. P(x) 5 Q x (2 2 3i) RQ x 8 RQ x 2 RQ x R 29. Circle the simplified form of the polynomial. x 4 2 14x3 1 37x2 2 66x 2 208 x 4 2 14x3 1 69x2 2 194x 1 208 213x3 1 37x2 2 194x 1 208 Chapter 5 136 Copyright © by Pearson Education, Inc. or its affiliates. All Rights Reserved. 5 2 3 2 2i Theorem Descartes’s Rule of Signs Let P(x) be a polynomial with real coefficients written in standard form. The number of positive real roots of P(x) 5 0 is either equal to the number of sign changes between consecutive coefficients of P(x) or less than that by an even number. The number of negative real roots of P(x) 5 0 is either equal to the number of sign changes between consecutive coefficients of P(2x) or less than that by an even number. 30. A possible number of positive real roots for x4 2 x3 1 x2 2 x 1 1 is 1 / 2 / 3 / 5 . Problem 5 Using Descartes’s Rule of Signs Got It? What does Descartes’s Rule of Signs tell you about the real roots of 2x4 2 x3 1 3x2 2 1 5 0? 31. The number of sign changes is 3, and the number of positive real roots is 4 32. P(2x) 5 2 Q R 2 3 . 2 1 3Q The number of sign changes is or R 21 5 , and the number of negative real roots is . Lesson Check • Do you UNDERSTAND? Copyright © by Pearson Education, Inc. or its affiliates. All Rights Reserved. Reasoning In the statement below, r and s represent integers. Is the statement sometimes, always, or never true? Explain. A root of the equation 3x3 1 rx2 1 sx 1 8 5 0 could be 5. 33. Write the factors of 8. 34. Write the factors of 3. 35. Because there are / are no factors of 5, the statement is always / sometimes / never true. Math Success Check off the vocabulary words that you understand. Rational Root Theorem Conjugate Root Theorem Descartes’s Rule of Signs Rate how well you can solve polynomial equations. Need to review 0 2 4 6 8 10 Now I get it! 137 Lesson 5-5