Download 2016-3-2 elimination day 2.notebook

2016­3­2 elimination day 2.notebook
March 02, 2016
Today is Wed.
3/2
Do Now:
-Take out homework
-Copy down homework
-Take calculator
Warm up: Do in your notebook
Describe and correct the error:
+
-5x + 5y = -5
5x + 3y = -3
2y = -8
2
2
y = -4
2016­3­2 elimination day 2.notebook
March 02, 2016
HW Answers
1)
- 2y = -12
{ -4x
4x + 8y = -24
6y = -36
6
6
y = -6
Solution: (
2)
,-6)
x - y = 11
{ 2x + y = 19
3x = 30
3
3
x = 10
Solution: (
, -1)
Solve the following system by graphing
y=
=
-x
1
{ y = -x - 1
y
y = 3x - 5 b = -5
3x
-5
m=3
m = -1
b = -1
(1, -2)
Solution:_______
2016­3­2 elimination day 2.notebook
March 02, 2016
Lesson 6: Solving systems by elimination (part 2)
Student outcomes:
-Students will solve a system using elimination where
they will have to multiply by a constant to get
opposites
What would be the first step to solving this
system if we wanted to use ELIMINATION?
2x + 7y = 1
2x - 4y = 12
2016­3­2 elimination day 2.notebook
March 02, 2016
Steps to solving systems by elimination (part 2)
Step 1: Multiply one equation by a constant
that results in an opposite term
Step 2: Add the two equations together
Step 3: Solve for the remaining variable
Step 4: Substitute to find the other variable
Step 5: Write the solution as an
ordered pair
Solve the following system of linear equations using elimination
{
3x + 6y = 9
3x + 5y = 8
2016­3­2 elimination day 2.notebook
March 02, 2016
Solve the following system of linear equations using elimination
{
x + 4y = 1
3x + 5y = 10
CHALLENGE
Solve the following system of linear equations using elimination
{
-2x + 3y = 7
5x + 8y = -2
2016­3­2 elimination day 2.notebook
March 02, 2016