Survey
* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project
Final Exam 2001 KEY 1 1. Draw a sawhorse representation of the most stable conformation of the C2 – C3 bond of (3R)-2,3,5-trimethylhexane. Why is it so stable? H3 C The hydrogen on C2 is gauche to the large groups on C3, minimizing gauche interactions. CH2 CH(CH 3 )2 H3 C H H CH3 2. Indicate, on the lines beside each arrow, the hybridization of the carbon atoms indicated in the molecule below: sp3 sp2 C OH sp sp3 3. Draw the compound below in its most stable conformation Cl CH3 Cl Final Exam 2001 KEY 2 4. Give each compound shown below its IUPAC (systematic) name. Cl Cl A. (3E, 5Z, 7R)-1,7-dichloro-2-methyl-3,5-nonadiene B. HO (1R, 3R, 5’E)-3-(5-methyl-5-octenyl)cyclopentanol C. OH (S)-3-methyl-2,4-cyclohexadienol OH D. (R)-1-(4-cycloheptenyl)-2-propanol E. NH 2 NH 2 (2E, 4R)-2-hexene-1,4-diamine Final Exam 2001 KEY 3 5. Draw the major products of the following: A. Propene + HBr/ROOR Br B. cis-2-butene + Br2/THF + mirror Br Br Br C. + HBr (+ FeSO 4) D. + CH3 Br HBr (+ ROOR) HO E. (1) Hg(OAc)2/H2O + (2) NaBH4 + mirror Final Exam 2001 KEY 4 6. What is the relationship between the following pairs of molecules? CH3 H H A. Cl H CH3 Cl CH3 CH2 H Cl Cl H Cl CH2 CH3 CH3 CH3 DIASTEREOMERS CH3 H OH H B. CH3 SAME H OH Cl CH2 CH3 CH3 C. OH H CH3 CH3 H OH ENANTIOMERS Final Exam 2001 KEY 5 7. Show how to accomplish the following transformations. (That means draw the starting material, then show the reagents and the order in which they are added, finally draw the product). A. Convert 3,3-dimethyl-1-butene to 3,3-dimethyl-1-butanol (1 pt for separate additions, (1) & (2) (1) BH3 / THF (1 pt) OH - (1 pt) (2) H2 O2 , OH , H2 O (1 pt) (1 pt) B. Convert 3,3-dimethyl-1-butene to 2,3-dimethyl-2-butanol + H 3 O / H2 O (3 pts) OH (1 pt) (1 pt) C. Convert 3,3-dimethyl-1-butene to 3,3-dimethyl-2-butanol 1 pt for separate additions OH (1) Hg(OAc) / H2 O (1 pts) (2) NaBH4 (1 pt) (1 pt) (1 pt) Final Exam 2001 KEY 6 Show how to prepare the following target molecules completely from 1butyne: (You do NOT have to repeat a synthesis, so if you use a compound later that you prepared earlier, you only have to write the compound and "see 8 C" or the like as the second synthesis) 8. A. butanal (an aldehyde) 1 pt for separate additions (1) (siamyl)2 BH, THF (2 pts) - (2) OH , H2 O2 , H2 O (1 pt) B. 2-butanone (a ketone) 2 pts O 2 pts H2 SO 4 , H2 O, HgSO4 O C. (Z)-3-octene H (2 pt) Na, NH3 (liq) or Lindlar's/H2 (2 pts) HBr (2 pts) NaNH 2 Br ROOR TARGET Retrosynthetic arrows are OK too: (2 pts) mix (2 pts) Lindlar's/H2 means "can be made from") D. racemic (3R,4S)- and (3S,4R)-3,4-dibromooctane (3 pts) Na, NH3 (liq) (from 8c) (2 pts) (2 pts) Br2 Final Exam 2001 KEY 7 9. Name the following molecule, then suggest the reactants that could have formed it in a Diels-Alder reaction: Cl Cl A. Name: (1S,2R,3R,4R,5S,6R)-3,4-dichlorotricyclo[4.2.1.02,5]non-7-ene B. Reactants: Cl + Cl 10. Put the following nucleophiles in order of INCREASING nucleophilicity in water (weakest first): Acetate anion, ethyl alcohol, ethyl thiolate anion, water, phenolate anion Water, ethyl alcohol , Acetate anion, phenolate anion, ethyl thiolate anion 11. How, with a 2° alkyl bromide, could you maximize the chances of the reaction with a nucleophile going through the SN2 route? Low polarity solvent, high concentration of nucleophile Final Exam 2001 KEY 8 12. Why does iodide ion make both a good leaving group and a good nucleophile in water? It’s a good leaving group because it’s a very weak acid (pKa of HI is –10). It’s a good nucleophile in water because it is not solvated much. 13. When (R)-3-methyl-3-bromohexane is treated with iodide ion in a relatively non-polar solvent, the product is only partially racemized. Explain first what one should expect here, and then suggest a reason for this observation. One would expect complete racemization since the carbocation formed is planar. The bromide ion must not have left the carbocation completely, but must be hanging around in an intimate ion pair or a solvent-separated ion pair with the carbocation. Final Exam 2001 KEY 9 14. How does one assure monobromination in the radical substitution reaction? Use a vast excess of the alkane substrate 15. Draw the major product of each below and suggest the route taken (i.e., SN1, SN2, etc.). Assume high concentrations of reagents listed. A) (R)-2-bromobutane + CH3COO– (water/methanol) ROUTE: SN2 O O B) (R)-2-bromobutane + OH– (aq) ROUTE: SN2 OH C) 2-methyl-2-bromobutane + potassium t-butoxide D) 2-methyl-2-bromobutane + sodium ethoxide E) 1-bromopropane + sodium methoxide ROUTE: ROUTE: ROUTE: E2 E2 SN2 O F) (R)-2-bromopentane + a 50-50 mixture of NaF and NaCl in DMSO. ROUTE: SN2 F Final Exam 2001 KEY 10 16. Suggest ways to synthesize the following compounds from butane: A. C N Br Br2 - t BuO - HBr ∆ ROOR O B. - Br OCH 3 # from A. C. racemic O - Br from A OCH 3 or solvolysis in CH3 OH Br CN - #