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Factoring Polynomials Greatest Common Factor and Factoring by Grouping Finding GCF (Greatest Common Factor) the largest natural number that divides all given numbers evenly Find the GCF of 24 and 60 List Factors Prime Factorization 24 2 Factors of 24: 12 4 3 2 1 2 3 4 6 8 12 24 2 24=2*2*2*3 60 Factors of 60: 2 1 2 3 4 5 6 10 12 15 20 30 60 30 10 2 3 5 60=2*2*3*5 GCF = 12 GCF = 2*2*3 = 12 Finding GCF Of Variables Find the GCF of x2y3z and x3z Consider each variable that exists in each Monomial X x2 and x3 GCF of x2 and x3 is x2 y y3 and y0 GCF of y3 and y0 is y0=1 z z and z GCF of z and z is z Therefore, GCF of x2y3z and x3z is x2*1*z = x2z 1 The simplest method of factoring a polynomial is to factor out the greatest common factor (GCF) of each term. Example: Factor 18x3 + 60x. GCF of 18 and 60 = 6 GCF x3 Determine GCF of the coefficients of each term. and x = x Determine GCF of the variables in each term. The GCF of the polynomial is the product of the GCF’s found above. GCF = 6x 18x3 + 60x = 6x 18x3 + 60x 6x 3x2 Factored form GCF * orig. polynomial GCF 10 18x3 + 60x = 6x 18x3 + 60x Rewrite and Simplify within the 6x 6x parentheses. 18x3 + 60x = 6x (3x2 + 10) Check the answer by multiplication. 6x(3x2 + 10) = 6x(3x2) + 6x(10) = 18x3 + 60x The simplest method of factoring a polynomial is to factor out the greatest common factor (GCF) of each term. Example: Factor 24x2y + 60x3. GCF of 24 and 60 = 12 Determine GCF of the coefficients of each term. GCF x2y and x3 = x2 Determine GCF of the variables in each term. The GCF of the polynomial is the product of the GCF’s found above. GCF = 12x2 24x2y + 60x3 = 12x2 24x2y + 60x3 Factored form 12x2 2y GCF * orig. polynomial GCF 5x 24x2y + 60x3 = 12x2 24x2y + 60x3 Rewrite and Simplify within the 12x2 12x2 parentheses. 24x2y + 60x3 = 12x2(2y + 5x) Check the answer by multiplication. 12x2(2y + 5x) = 12x2 (2y) + 12x2 (5x) = 24x2y + 60x3 The simplest method of factoring a polynomial is to factor out the greatest common factor (GCF) of each term. Example: Factor 4x2 -12x+ 20. GCF of 4, 12 and 20 = 4 Determine GCF of the coefficients of each term. GCF x2, x , 0 = N/A Determine GCF of the variables in each term. The GCF of the polynomial is the product of the GCF’s found above. GCF = 4 4x2 4x2 -12x +20 = 4 4x2 -12x +20 4 -12x +20 = 4 x2 4x2 4 3x Factored form GCF * orig. polynomial GCF 5 -12x +20 4 4 Simplify. 4x2 -12x +20 = 4(x2 -3x +5) Check the answer by multiplication. 4(x2 – 3x + 5) = 4x2 – 12x + 20 2 A common binomial factor can be factored out of certain expressions. Example: Factor the expression 5(x + 1) – y(x + 1). 5(x + 1) – y(x + 1) = (5 – y)(x + 1) (5 – y)(x + 1) = 5(x + 1) – y(x + 1) Check. Some polynomials can be factored by grouping terms to produce a common binomial factor. Examples: 1. Factor xy + 2y + 7x + 14. xy + 2y + 7x + 14. = (xy + 2y) + (7x + 14). Group terms. = y(x + 2) + 7(x + 2) Factor each pair of terms. = (x + 2)( y + 7) Factor out the common binomial. 2. Factor 6x3 - 8x2 + 3xy - 4y. 6x3 - 8x2 + 3xy - 4y. = (6x3 - 8x2)+ (3xy - 4y). = 2x2(3x – 4) + y(3x – 4) Group terms. Factor. = (2x2 + y)(3x – 4) Some polynomials can be factored by grouping terms to produce a common binomial factor. Examples: 3. Factor 2xy + 3y – 4x – 6. 2xy + 3y – 4x – 6 = (2xy + 3y) – (4x + 6) Group terms. = (2x + 3)y – (2x + 3)2 Factor each pair of terms. = (2x + 3)( y – 2) Factor out the common binomial. 4. Factor 2a2 + 3bc – 2ab – 3ac. 2a2 + 3bc – 2ab – 3ac = 2a2 – 2ab – 3ac + 3abc Rearrange terms. = (2a2 – 2ab) – (3ac + 3bc) Group terms. Factor. = 2a(a – b) – 3c(a – b) = 2a(a – b) – 3c(a – b) = (2a – 3c)(a – b) Factor. 3