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Example 1 Evaluate Trigonometric Functions Find the values of the six trigonometric functions for angle X. leg opposite X: YZ = 3, leg adjacent X: XY = 2, and hypotenuse: XZ = 13 sin X = csc X = opp hyp hyp opp = = 3 13 13 3 13 or 13 cos X = sec X = 3 adj hyp hyp adj = = 2 13 13 or 2 13 13 tan X = cot X = 2 opp adj adj opp 3 = 2 2 = 3 Example 2 Find Trigonometric Ratios 7 . Find the value of tan B. 12 Draw a right triangle and label one acute angle B. Since cos 7 adj B B= = , label the adjacent side 7 and the hypotenuse 12 hyp 12. In a right triangle, B is acute and cos B = Step 1 7 12 Step 2 b Use the Pythagorean Theorem to find a. a2 + b2 = c2 72 + b2 = 122 49 + b2 = 144 b2 = 95 b = ± 95 b= Step 3 C 95 Find tan B. opp tan B = adj = 95 7 A Pythagorean Theorem a = 7 and c = 12 Simplify. Subtract 49 from each side. Take the square root of each side. Length cannot be negative. Tangent function Replace opp with 95 and adj with 7. Example 3 Find a Missing Side Length Use a trigonometric function to find the value of x. Round to the nearest tenth if necessary. The measure of the side opposite the angle is 25, the given angle measures 45˚, and the missing length is the hypotenuse of the triangle. The trigonometric function relating the opposite side of a right triangle and the hypotenuse is the sine function. sin = sin 45˚ = 2 2 = opp x 45 25 sine ratio hyp 25 Replace with 45˚, opp with 25, and hyp with x. x 25 2 2 Find the cross products. sin 45˚ = x x 2 = 50 x= 50 Divide each side by 2 x = 25 2 2. Simplify. The value of x is 25 2 or about 35.4. Example 4 Find a Missing Side Length The Great Pyramid of Khufu in Egypt is one of the Seven Wonders of the World. Its original height was 481 feet. The angle that the sides make with the square base is about 52˚. What is the length of one side of the base? Make a drawing of the situation. The base will be twice the length of a shown in the diagram. Write an equation using a trigonometric function that involves the ratio of the length a and 481. tan 52˚ = a= 481 a 481 tan = 481 ft opp adj Solve for a. tan 52 a ≈ 375.8 Use a calculator. To find the length of a side of the base, find 2a. 2a = 2(375.8) = 751.6 The length of one side of the base of the pyramid is about 752 feet. 52 a Example 5 Find A Missing Angle Measure Solve ∆RST. Round measures of sides to the nearest tenth and measures of angles to the nearest degree. 20 T You know the measures of the sides. You need to find S and R. Find S. 20 2 5 opp sin S = or sin S = 5 10 5 hyp 10 5 S Use a calculator and the sin–1 function to find the angle whose sine is KEYSTROKES: ` [SIN–1] 2 * ` [ ] 5 )/5 ) To the nearest degree, S ≈ 63˚. Find R. 63˚ + R = 90˚ R = 27˚ Angles R and S are complementary. Solve for R. Therefore, S ≈ 63˚ and R ≈ 27˚. R 2 5 5 e 63.43494882 . Example 6 Use Angles of Elevation and Depression a. The world’s highest waterfall is Angel Falls in Venezuela. It is 3212 feet tall. If a tourist estimates the angle of elevation to the top of the falls to be 35˚, what is the tourist’s distance from the base of the falls? Make a drawing of the situation. Let d be the tourist’s distance from the base of the falls. Write an equation using a trigonometric function that involves the ratio of d and 3212. tan 35˚ = d= 3212 tan = d 3212 opp adj Solve for d. tan 35 d ≈ 4587.2 Use a calculator. The tourist’s distance from the base of the waterfall is about 4587 feet. b. A golfer is standing at the tee, looking up to the green on a hill. If the tee is 28 yards lower than the green and the angle of elevation from the tee to the hole is 18, find the distance from the tee to the hole. x yd 18 28 yd Write an equation using a trigonometric function that involves the ratio of the vertical rise (side opposite the 18 angle) and the distance from the tee to the hole (hypotenuse). sin 18 = 28 x x sin 18= 28 x= 28 sin18 opp sin θ = hyp Multiply each side by x. Divide each side by sin 18. x 58.25 Use a calculator. So, the distance from the tee to the hole is about 58.3 yards.