Survey
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Download Evaluating Mendelian and Non
Document related concepts
Transcript
Biology HS/Science Unit: 08 Lesson: 02 Evaluating Mendelian and Non-Mendelian Crosses PI KEY Use the following key to complete problems 1–5. Show all work using Punnett squares, AND summarize your answers below that work. Key This key provides you with information about certain genetic traits in monsters. T – No tail t – Tail present B – Blue fur b – Yellow fur H – Small head h – Large head **The blue fur allele is not completely dominant over yellow fur. Because of this, heterozygotes have green fur. G – Green tongue R – Red tongue O – Orange tongue **The green and red tongue color alleles are codominant. This means that monsters that have both the green tongue allele and red tongue allele, have tongues with green and red spots. The allele for orange color is recessive. XA – Ability to see in the dark Xa – Cannot see in the dark **The alleles for eye sight are sex-linked because they are found only on the X chromosome. 1. A cross is made between two monsters in the F1 generation. The parents of the F1 generation were homozygous small headed and homozygous large headed. H h ©2012, TESCCC H Hh Hh 05/14/13 page 1 of 4 Biology HS/Science Unit: 08 Lesson: 02 Hh h Hh What are the phenotypic and genotypic ratios of the F2 generation? 4:4 are all smallheaded (100%). 4:4 are Hh (100%) heterozygous. If these F1 monsters had 100 offspring in the F2 generation, predict how many would have the same phenotype as their parents. Approximately 100 of the offspring would have the same phenotype as one parent (small-headed). 2. A dihybrid cross is made between two heterozygote monsters with small heads and no tails. What are the phenotypic and genotypic ratios of the F1 generation? Phenotypic ratios: 9 small-headed and no tail: 3 small-headed and tail: 3 large-headed and no tail: 1 large-headed and tail Genotypic ratios: 1 HHTT: 2 HHTt: 2 HhTT: 4 HhTt: 1 HHtt: 2 Hhtt: 1 hhTT: 2 hhTt: 1 hhtt What percentage of F1 offspring do you predict have the same genotype as their parents? Approximately 56.25% (9/16) will have the same genotype as their parents (small heads and no tails). HT HT Ht hT ht HHTT HHTt HhTT HhTt HHTt HHtt HhTt Hhtt HhTT HhTt hhTT hhTt HhTt Hhtt hhTt hhtt Ht hT ht ©2012, TESCCC 05/14/13 page 2 of 4 Biology HS/Science Unit: 08 Lesson: 02 3. A female monster that cannot see in the dark is crossed with a male monster that can. What are the phenotypic and genotypic ratios of the F1 generation? Phenotypic ratios: 1 XAXa: 1 XaY Genotypic ratios: 1 female can see in the dark: 1 male can’t see in the dark What percentage of F1 offspring will be females that can see in the dark? 50% of the F1 offspring will be females that can see in the dark. Xa XA Y Xa XAXa XaY XAXa XaY 4. A cross is made between a monster with an orange tongue and a monster with a red and green spotted tongue. What are the phenotypic and genotypic ratios of the F1 generation? Phenotypic ratio: 1 green tongue: 1 red tongue Genotypic ratio: 1 GO: 1 RO What percentage of the offspring will have a different looking tongue from their parents? 100% of the offspring will have a different looking tongue from their parents. The offspring will have either green or red tongue, no orange and no green and red spotted. O ©2012, TESCCC O 05/14/13 page 3 of 4 Biology HS/Science Unit: 08 Lesson: 02 G R GO GO RO RO 5. Two monsters with green fur are crossed. What are the phenotypic and genotypic ratios of the F1 generation? Phenotypic ratio: 1 blue: 2 green: 1 yellow Genotypic ratio: 1BB: 2Bb: 1bb What percentage of the offspring will have a different phenotype than their parents? 50% of the offspring will have a phenotype different than their parents, 25% blue and 25% yellow. B B b ©2012, TESCCC b BB Bb Bb bb 05/14/13 page 4 of 4
