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Name ________________________________________ Date __________________ Class__________________
LESSON
10-3
Practice B
Angles of Elevation and Depression
Marco breeds and trains homing pigeons on the roof
of his building. Classify each angle as an angle of
elevation or an angle of depression.
1. ‘1 _____________________
2. ‘2 _____________________
3. ‘3 _____________________
4. ‘4 _____________________
To attract customers to his car dealership, Frank tethers a large red balloon
to the ground. In Exercises 5–7, give answers in feet and inches to the
nearest inch. (Note: Assume the cord that attaches to the balloon makes
a straight segment.)
5. The sun is directly overhead. The shadow of the balloon falls
14 feet 6 inches from the tether. Frank sights an angle of elevation
______________________
of 67q. Find the height of the balloon.
6. Find the length of the cord that tethers the balloon.
______________________
7. The wind picks up and the angle of elevation changes to 59q.
Find the height of the balloon.
______________________
Lindsey shouts down to Pete from her third-story window.
8. Lindsey is 9.2 meters up, and the angle of depression from
Lindsey to Pete is 79q. Find the distance from Pete to the base
of the building to the nearest tenth of a meter.
______________________
9. To see Lindsey better, Pete walks out into the street so he is
4.3 meters from the base of the building. Find the angle of
depression from Lindsey to Pete to the nearest degree.
______________________
10. Mr. Shea lives in Lindsey’s building. While Pete is still out in
the street, Mr. Shea leans out his window to tell Lindsey and
Pete to stop all the shouting. The angle of elevation from Pete
to Mr. Shea is 72°. Tell whether Mr. Shea lives above or below
Lindsey.
_________________________________________________________________________________________
© Houghton Mifflin Harcourt Publishing Company
290
Holt McDougal Analytic Geometry
MN 6; PN | 8.49; m‘M 90q; m‘P
45°; m‘N 45°
13. MP
7. 28 feet
9. 11.9 meters
14. KL 7; LJ 3; JK | 7.62; m‘L 90°; m‘J |
67°; m‘K | 23°
10. 1.9 meters
Practice B
1. angle of elevation
Challenge
3
1.
5
2. angle of depression
4
2.
3
3. angle of depression
4. angle of elevation
3. 53.1°
4. sin E
5
; cos E
5
2 5
; m‘E | 26.6°
5
5. sin M
1
; tan M
2
3
; m‘M
3
2
; tan R
2
1; m‘R
45°
7. sin K
3
; cos K
2
1
; m‘K
2
60°
2. 22° to 27°
3. 64°
4. 34.9 ft
5. A
6. G
7. D
8. F
8. 1.8 m
1. 82 ft 10 in.
2. 5 ft 10 in.
3. 128 ft 8 in.
4. Possible answer: m‘C 38° and
m‘ADB 52°. These angles are
complementary. So UABD a UACB.
Lamar can use similarity ratios to find the
AC AB
AB 2
.
or AC
distance AC:
AB AD
AD
Subtracting AD from AC leaves CD, the
width of the river.
5. 7.5 m
6. 95.2 m
7. 9° or N 81° E; 17.9 km/h
1. finding the measures of all unknown
sides and angles of the triangle
§9·
2. m‘B tan1 ¨© 4 ¸¹
AB
7. 31 ft 10 in.
Practice C
Reading Strategies
4
6. 37 ft 1 in.
10. Mr. Shea lives above Lindsey.
Problem Solving
1. 16°
5. 34 ft 2 in.
9. 65°
30°
6. cos R
3. sin 24°
8. 35 feet
Reteach
4. 67°; 23°; 12
1. elevation
2. depression
3. depression
4. elevation
5. elevation
6. depression
7. depression
8. elevation
9. 11.5 m
10-3 ANGLES OF ELEVATION AND
10. 23 ft
11. 18 ft
DEPRESSION
12. 35 ft
Challenge
Practice A
1.
1. horizontal; above
2. depression; below
3. angle of depression
4. angle of elevation
5. angle of depression
2. tan
6. angle of elevation
T
21.4
31.4
3. 34.3q
© Houghton Mifflin Harcourt Publishing Company
A57
Holt McDougal Analytic Geometry