Download Review work answer Key

l)
tt)
in pet
piir-r,ts, Ciie ¿;'1.'':;r'pcd gene
(i;)
is dsni̡ar'i
\1,./-^-
t-
ar¡:Ìî ùe,v-âjii)-'\'i-!í'ri g+ra (¿)
the Punnett squale below to show
,l¿ Twq pea plants with greeu pods, Gg x GG, were crossed' Complete
' the rãsulti of this cross. [I]
as
[a Wn"t p"r""niãg,5äf *e'tffsp-rüg
ls}
4Lo* th" g"oeti"
q
[I]
pods?
produced by thls cross will rnost likeþ have green
v,
all have yellowpods'
makeup of two parent pea plants whose offspriug would
[l]
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o^^
your answeis to questions
wo t"ll p"" pl"átr (rt x
Base
t'l).
€
3
through@on the Punaett square below, which shows a cross between
-
3
TaII Male Plant
Tt
Kty
Tall Female Pla¡t
3.
fuhat
c-
= tall gene (dominant)
t
= short geûe (recessive)
tall? r.r
hl
----.:'--^.-.r^rrÐ
will grow
percentage of the offspring
(""ordtg
.g
T
ao
á/
(la¿
( "'/
vÇ 7o
tall genes?
ihe Punaett square, what is the probability of ar: oßpriog bleriting two"/
(Express your answer as a hactioû or percentage')
[r]
{-. ó/
) Ò 1o
I
¿^"
/-
W
/ /-
(
J) ''
+
-- ¡-- L^¡-L are not exactly
same [i]
^-^^¡I., tJre
É*pUi" *ny U"tn parent plants are taÌl, even though their gen es for heíght
\l
''f-("i) úfu.b ,\
tu4
Ui[l A _ <rg"xÐ_ _ø]t=rw, _W-**I4
ifàe Por*,eit
sqr.:ai= ieii,;=", s.ho:i,s
a¡
?i_ä
¡.¡a
.nr
Èi"¿at
crcssed-wiLl aa ÌÈ- pea pian...
K"y
.R =
firll
mund pod sàaþe (dominant)
r = wri¡Hed
---'r
.þ,
€
pod sLape (recessive)
l{ãat
percentage of tåe otrspring
will have a firll, rouad pod shape?
ftl / 6 Ò
o"
7,
6
Complete the Pr:laet squere provided
bely
to show the erossing of two fir pareuts.
F--r
+
A
rì:.
(
-\_
{-
$@ tr roo oerrp'iog were produced from the crossing shown
how many would have a wrinlded pod shape?
hl
in.þ
Rgnett
S-O
square. b9row, approximately
ZO ñ /;
'
KeE
.R =
r
ßB = chesl+nøl
L
Cro55
',1
{)
UJ
t
brown)
x
tùt4-J
LrJk)
fidl
rot-nd pod shape (dominant)
= wri¡Ided pod sh¡fè (recessive)
=
u:hìk- 3¡) = Dú,[o¡ninÒ
frtendi"
cøss 3ø x Br^-r
' fa L,) )flr 9'o'"
1lt
ß
¿ii
f;i v z
X'JG*r'r@dt
lo)
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U.9, Nãt¡c.n,rl Librérf
Cell cycle/Mitosis
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I'fÈdicir'È
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?dds{ù{eË
@ @-I
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@@ @@*.
Word bank for cell cycle/mitosis:
.l¡tle+phase, M€tephase,-D'4+tosît
Bøenær€ph€i€rRep¡eates,-Teloplræ€-
skin after a cut. They also go through ¡t as
cells go through mitosis when you need
Meiosis
Meiosis is similar to
both processes involve a cell dividing. Not all body cells go
cells (sperm and eggs). Sex cells are also called
through
gametes.
only have half as
much DNA as
n^u.
only
t4Ç
have
cell. Your regular body cells
\2
L9 &
but your gametes
Word bank for
crossrng over,
,
8añeteT
se¡(cperm,
chromosomes. This is because
),bell plus an egg cell make a baby. lf you want your baby to have one set of
i
chromosomes like you do, you need the sperm to give half a set of DNA and the egg to give half
a set of DNA l% + y, = 1 set of chromosomes). To end up w¡th cells that have half a set of
chromosomes instead of a full set, you need a special process. That's where meiosis comes in!
Meiosis is different from mitos¡s because it t
"r@h/^l
cell divisions instead of just one
b 5\.-v' . and this mixes up your DNA.
when the cells divide and ..t7ã* *tlraoï*o *llrã alike because they each have
.hrorororn"r. rhis
is
carle¿
C?)
Cr'ðSS
t
different genes on them (see picture below)!
w
,@
@
w-@ @ <ffi
-@
No irvo rex cells arc alikc, ilue
to c¡rssi¡iE ol,e¡'!
Codominance Worksheet (Blood types)
Human blood t)?es are determined by genes that lollow the CODOMINANCE p
There are two dõminant aìleles (IA and IB) and one recessive allele (i).
Genotype
o
Can donate blood to:
Can receive blood aom:
A,B,AB and O
o
ll
lnnìversal donor'l
AB
IAIB
B
l
A,B,AB and O
(universal receiver)
IoIo
or Ioi
AB, A
O,A
I"Iu
o,
#
AB,B
o,B
Wdte the genotFe for each person based on the des_cription:
a.
b.
c.
d.
e.
f.
g.
2.
O, AB
#.r¿
+-*L
Homozygous for the "n" allele
Heterozygous for the "4" allele
Type O
Type
Type
"4" and had a t,?e "O"
"AB"
parent
Blood can be donated to a.rìybody
Can only get blood fiom a type "O''
Iß L "¿ÚL9
rÞrß
donor
TW
_-#<
L' )- ø
Pretend that Brad Pitt is homozygous for the type B allele, and Angelina Jolie is þpe
are all the possible blood types
oftheir
lo,% bC
baby?
;ffi
"O." What
W
Draw a Punnett square showing all the possible blood types for the Jffspring produced by
"o"motherandanarlpe*AB"father
-Vr
,1ffi
,,ffi
) Iï.4
EÒ
- - --1"'-"
a
type
^,
ts
*
I
Two parents think their baby was switched at the hospital. Its 1968, so DNA fingerprinting
technology does not exist yet, The mother has blood type "Q,-:the father has blood type "48,"
and the baby has blood type "¡-l
a. Mother's genotype: CO
b. Falher's genotype: /A J\
At
Baby's genotyp":
t+
d. Punnetl square showiirg,^all possible genotypes fór childlen produced by this couple
c.
'gn o,
"
hD
'
Òr[]
,ìT1
e. wasthebabvs*,"*0,
NbÞ-
Ao,
c\ \,r" b
Nù\
¿
cr"h
/
,'lL*¡
¿L^lL
Co,, 7u0,tv
'-"-6.
Two other parents tbink their baby vvas switched at the hospital. The mother hàÈ'61¡tod type
the father has blood type
a.
b.
c.
Mother's
"8,"
a4d tþe baby l¡as,.bÌood type
o, /\ U
o.
,Þ
F-¡^-tR
genot¡p", lll 4
Father's eãnotñe,
IFB--
Babv's
";.t";,t¡at\hows
O. zu*"ttiquare
e.
"4,"
"AB.''
Was the baby switched?
tne Uaby's genotype as a possibiliry:
NIO
a--"7.
Based on the information in this table, which man could not be the father of the baby? Jusri$
your answer with a }ìrnnett
square.
-. +'
¡r}tù^Crir
o øl"tb
þ-0 to
r'ê Bo4
ì
\ 8,7*,_
S<r^^*6*Þ
(+, ì'W"^.
8.
Based on the information in this table, which man could not be the father ofthe baby? Justify
your answer with a Punnett square.
Name
Blood Type
Mother
ryp" 9
Baby
Type AB
Bartender
Type O
Guv at the club
'l ype A.B
Cabdriver
Iype A
Flight attendant
Iype B
/Vr
l.
Ð
\
9. Explain why blood type data cannot prove who the father ofa baby þ, and can only prove who the
lather
þ¡q¡.
È'n
t+
Í'iøk
Table
Processes
Compare,/contrast
Comparing
t/"
#-tlt
i#:;{TÏ'#:,{#i#:,lif,iî;:mpletethecompare/contrcsttøbreberta.'
" uLc t'øbte t0 a¡ríte your attswøs, write tn* *T'
I
\
itp*^t" tl,ot i¡/îpä."-"'
Mitosis
Meiosie
urowrq regeneration of
nerrrt
Locationìn Body
cells
y cells
N-umber of Daughter
),...--
Fou¡
Change in
Chromosome Number
B$ftû
Nu¡rbe¡ of phases
u' rz/
6
ïÈc
Cell Divisions
One
(ô
Between parent Cell
and-Daughter CeIIs
8.
ï'.l)'N-q--
_üomologous chromosomes
assort independentlv, so
each gamefe has a ufoue
combinatíon of alleìes
'
139
eT
In00mplele anû [0dOminanm lv0ilisneel
Name:
Period:
(Non-mendelian monohybrid crosse s )
Date:
Answer the following questions. Províde a punnett square to support lour answers where
ind.icated. Express probøbìlities as percentages. For instønce, a prohøbilíty of one chance ín ten
would be 707o.
'1.
2.
Explain the difference between
in::rnplerglþAlg19e
and codominanc"'
--V n,
þÞhi,,x
T;
a*'-{e7Ns'''P
In some chickens, the gene for feather color is controìled by codimin^ance. The allele for black is
B aa{ the allele fo¡ white is W. The heterozygous phenotype is known as erminette.
a. What is the genotype for black chickens? Þß
b. What is the genotype for white chickens? ¡¿]\)_^
c. What is the genotype for erminette chickens?
Þ14/
If two erminette chickens were
a.
b.
They would have
They would have
u
c¡ossed, what is the probability that:
61u"¡
25
7,
"¡¡s¡r
a white chick I ÉCo
rz
Parents:
P
t
U x $w
\
00
4.
A black chicken and a white chicken are crossed. What is the probability that they will have
eminctta ¡hi¡l¿c? /).---r Ø-
**-
&)r'"
Parenrs:
Vh x
ûJ tA)
1\lB
Nlsrlø,1
ñwM
5. In snapdragons, flower color is controlled by ,n"o*Oß8á**ncç-The two
and white (W). The heterozygous genotype is expiessed as pink
a.
b.
c.
What is the phenotype of a plant lvith the genotype RR?
What is the phenotype of a plant r.vith the genotype W-W?
What is the phenotype of a plant with the genotype RW?
alleles are red (R)
{#.w
'
6. A pink-flowered plant is crossed with a white-flowered plant. lVhat is the probability of
producingapink-floweredptantt
ÇA_v"
"*"no,pil,
tJ!
Llt¿
úWWI
utw
7. What
c¡oss
will produce
the most pink-flowered plants? Show a punnett square to support your
8. Another type of non-mendelian trait: Multiple alleles. Human hair color is controlled by one gene
with four alleles (with some incomplete dominance):
HB'=
brown
HBd =
blonde
hR
=
r9d
= black
hbk
The possible genotypes and phenotypes:
HBdHBd
IJBdhR
HB.ÌrR =
or
HBdhbk
=
cfrcrr¡hc1.rr¡
auburn
blonde
HBdHBT
hlnnde
I{Bq{Br ñr lfBrhù*- l"
hRhR
or
hRhYk
=
- mousy brown
red
'
-r.
hbkhbk = black=
What do you think your parent's phenotypes and genotypes for hair color are?
¡ Ør11Þr?
What a¡e yóu¡ phenotype and genotype fo¡ hair
color?
À
i
.
*liÍ".l "!n^?or*o
rr someone with aubu¡n hai¡ has
wirh red nun,o",
"^+1,"!:':fl":"e
probabilities for their children?
hair), what are the genotype and phenôtype
'nv x
. {-
h'
KO,
oft
r)'h
T
{L
.
V-
h,
t
blc-
,1".
Þ',
11
¡ fL ; aalaa,,t-h-',,-,
-Y
,þirr_
Lunr
w*
€
Class
Acnvlry ¡
--
Date
CHAPTER
Generics
æ
Shoutd This Dog Be Cailed Spot?
Imagine this microscopic dTru'4 sex cerì
from a mare dogjoins with â sex celr from
ü;.äi,å,å*äir,.
ren'ized egg that resurts
:"i,H,:*"T;3*1gi::..r.ã,ì-".-äs
,h;;y;;.;,ìä'Ëkîä:;:fiffi:?.ïrXåi_ä::ffiî*:i.ï"parént.suppose
From the female dog
From the male dog
Each chromosome of the pair contains
genes for the same Faits" But one
a
g"r,.
*-d
ott ei u ."..ssive gene. Use the drawins
foniinan¡
qrru rr¡ç L¡¡¿r¡ l, , i1¡tÐ\ ref tne
questlofui.
:5"i:T*.yt!1v¡
1. Would the new puppy have a spotted
@ Prentice-Hall, lnc.
t¡.
coat?
3.
Does the male dog have a
E".plui,,,
ìl i)
çotted
coat?
f¿C¡$rlâ.a- - a-q
4. Whar would tlre puppy's hair texrure be?
5. Would the puppy have curly or straight hair?
6. a. Does
t̡e female dog have curly hair?
b. Does the male dog have curly hair?
7. Would the puppy be a hybrid or
a
purebred for hair length?
t^vþ Ub^Ð
b-rr,"^)+- r:
trhe eåghter Síde
"You idiot, I meant transfer their genes.',
gnh^'*{'
Name
Frobability and Genetics
ô ilnderstanding Main ldeas
Coffiplete the two Punnett squaræ below, ønd
ihett answer the questimts on a
scparate sheet of paper.
I.
Puanett Square A:
2. Punaett Square B:
Bb
E-h__
'Eünlt
þ2
4ryalø,rl
t_t_-_______l
h
3. In the cross between fwo black g,.rine1
pigs ghown in p¡,¡neä square
theprobabilityrtratanotrspringwillb;6¡*tlrrr,1t"i
*
what is
i
j-.*f ;"tsì"Á*r"";çd¿5al¡þ
.A,,
,
rte cross between rwo btack guinea pigs in punnett
Square A
'
l:^111,,"-:.llt_:
would
not þroduê a white guinea pig r^d"t;.
":,
;;-:
Ë ü-;'ïi:;
5' what color are the guinea pig par.ot"
th...ossl.ho"á-i'ioooll"tt
6. Which guinea pig parent(s) in punnett
Square B is homozygo.
neærozygols3 Expki¡ hqw you know.
el , -
i'
r,.","1ig"*?;;!'kj"jqifr,*.-- et. tt -. ,',
;
,
sq*'.åi 0 b,lr rrw
û*_ = _bL
t}*n".e
:iïff H,"ihäffi n#i;,*affini'p*y"3*
#rlìyl
.Ç,)
T.calcutatethìþ'rob$ffiÍår-",#-hrp,r"*Hrlf
Square B. What is the probabitity thuì
è Fuiidins
s
It¡
T
.9
c
n"rrro"rro.
".
À
o
vbcabutary
ix dfinitíonby
Yrf,!:!,r:::.ith
the line besîàe the term.
t
-A-
9. Punnetr square
!-t'''.no*"
n. codominance
Q
S
rz. probabitity
Cnu.oo^orrroo,
f)
u"ãrrprirrs
b;;i;ä-
% B/ù"
';,;)^"o¡^F
fr"/o øh"\
writingtheteuer of tlrr ron"n a"¡nírlín
ln
z.aía cha¡t that shows all the possible combinations of alleles that
can result trom a genetic cross
likelihood that a particuJar eyent will occur
.;;,.ah organism that has two identical alleles for a trait
-.b,:-. the
,*ãn,organismt
physica.l appearance
;e.án organism's genetic makeup, or allele combinations
.f<áh organism that has two different alleles for a_trait
g, inheritance pattern
nor recessive
r¿. ph.oowp.
*i[
in whích the alleles are neither dominant
- 6o4t M^ Eyr-rs5- g.
:"
ìil
(l
lì
Teaching Resources
Cø17
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