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Atoms and Elements The Atom Atomic Number and Mass Number Isotopes LecturePLUS Timberlake 1 LecturePLUS Timberlake 2 The Atom An atom is the smallest particle that retains the characteristics of an element Atomic Theory Atoms are building blocks of elements Similar atoms in each element Different from atoms of other elements Two or more different atoms bond in simple ratios to form compounds LecturePLUS Timberlake 4 The Parts of the Atom Atoms are composed of three subatomic particles: • Protons have a positive charge (+) • Electrons carry a negative charge (-) • Neutrons are electrically neutral. Subatomic Particles Particle Symbol Charge Relative Mass 0 Electron e- 1- Proton p+ + 1 Neutron n 0 1 LecturePLUS Timberlake 6 Location of Subatomic Particles 10-13 cm electrons nucleus protons neutrons 10-8 cm LecturePLUS Timberlake 7 The Structure of the Atom The protons and neutrons, each with a mass of about 1 amu are found in the tiny, dense nucleus. The electrons are located outside the nucleus. Models of the Atom 9 Atomic Number Counts the number of protons in an atom LecturePLUS Timberlake 10 Atomic Number on the Periodic Table Atomic Number Symbol 11 Na LecturePLUS Timberlake 11 All atoms of an element have the same number of protons 11 protons Sodium 11 Na LecturePLUS Timberlake 12 Periodic Table Represents physical and chemical behavior of elements Arranges elements by increasing atomic number Repeats similar properties in columns known as chemical families or groups LecturePLUS Timberlake 13 Periodic Table 1 2 3 4 5 6 7 8 11 Na LecturePLUS Timberlake 14 Learning Check State the number of protons for atoms of each of the following: A. Nitrogen 1) 5 protons 2) 7 protons 3) 14 protons B. Sulfur 1) 32 protons 2) 16 protons 3) 6 protons C. Barium 1) 137 protons 2) 81 protons LecturePLUS Timberlake 3) 56 protons 15 Solution State the number of protons for atoms of each of the following: A. Nitrogen 2) 7 protons B. Sulfur 2) 16 protons C. Barium 3) 56 protons LecturePLUS Timberlake 16 Number of Electrons An atom is neutral The net charge is zero Number of protons = Number of electrons Atomic number = Number of electrons LecturePLUS Timberlake 17 Mass Number Counts the number of protons and neutrons in an atom LecturePLUS Timberlake 18 Atomic Symbols Show the mass number and atomic number Give the symbol of the element mass number 23 Na atomic number sodium-23 11 LecturePLUS Timberlake 19 Subatomic Particles in Some Atoms 16 O 31 P 65 8 15 30 15 p+ 16 n 15 e- 30 p+ 35 n 30 e- 8 p+ 8n 8 e- LecturePLUS Timberlake Zn 20 Isotopes Atoms with the same number of protons, but different numbers of neutrons. Atoms of the same element (same atomic number) with different mass numbers Isotopes of chlorine 35Cl 37Cl 17 17 chlorine - 35 chlorine - 37 LecturePLUS Timberlake 21 Learning Check Naturally occurring carbon consists of three isotopes, 12C, 13C, and 14C. State the number of protons, neutrons, and electrons in each of these carbon atoms. 12C 6 13C 14C 6 6 #p _______ _______ _______ #n _______ _______ _______ #e _______ _______ _______ LecturePLUS Timberlake 22 Solution 12C 6 13C 14C 6 6 #p 6 6 6 #n 6 7 8 #e 6 6 6 LecturePLUS Timberlake 23 Learning Check An atom of zinc has a mass number of 65. A. Number of protons in the zinc atom 1) 30 2) 35 3) 65 B. Number of neutrons in the zinc atom 1) 30 2) 35 3) 65 C. What is the mass number of a zinc isotope with 37 neutrons? 1) 37 2) 65 LecturePLUS Timberlake 3) 67 24 Solution An atom of zinc has a mass number of 65. A. Number of protons in the zinc atom 1) 30 B. Number of neutrons in the zinc atom 2) 35 C. What is the mass number of a zinc isotope with 37 neutrons? 3) 67 LecturePLUS Timberlake 25 Learning Check Write the atomic symbols for atoms with the following: A. 8 p+, 8 n, 8 e- ___________ B. 17p+, 20n, 17e- ___________ C. 47p+, 60 n, 47 e- ___________ LecturePLUS Timberlake 26 Solution 16O 8 A. 8 p+, 8 n, 8 e- B. 17p+, 20n, 17e- 37Cl 17 C. 47p+, 60 n, 47 e- 107Ag 47 LecturePLUS Timberlake 27 Learning Check AT 5 An atom has 14 protons and 20 neutrons. A. Its atomic number is 1) 14 2) 16 3) 34 B. Its mass number is 1) 14 2) 16 3) 34 C. The element is 1) Si 3) Se 2) Ca D. Another isotope of this element is 1) 34X 2) 34X 3) 36X 16 14 14 LecturePLUS Timberlake 28 Solution AT 5 An atom has 14 protons and 20 neutrons. A. It has atomic number 1) 14 B. It has a mass number of 3) 34 C. The element is 1) Si D. Another isotope of this element would be 3) 36X 14 LecturePLUS Timberlake 29 Masses of Atoms A scale designed for atoms gives their small atomic masses in atomic mass units (amu) An atom of 12C was assigned an exact mass of 12.00 amu Relative masses of all other atoms was determined by comparing each to the mass of 12C An atom twice as heavy has a mass of 24.00 amu. An atom half as heavy is 6.00 amu. LecturePLUS Timberlake 30 Atomic Mass on the Periodic Table Atomic Number Symbol Atomic Mass 11 Na 22.99 LecturePLUS Timberlake 31 Atomic Mass Listed on the periodic table Gives the mass of “average” atom of each element compared to 12C Na 22.99 Average atom based on all the isotopes and their abundance % Atomic mass is not a whole number LecturePLUS Timberlake 32 Atomic Mass Atomic mass is the weighted average mass of all the atomic masses of all the isotopes of that atom. LecturePLUS Timberlake 33 Weighted Average • You have two types of coins: pennies and quarters. The pennies have a mass of 5g. The quarters have a mass of 15g. 57% of the coins are pennies, 43% of the coins are quarters. What is the average mass of your coins? 34 Weighted Average – Atomic Mass • You have two isotopes of Boron: 10B and 11B. The 10B has a mass of 10amu. The 11B has a mass of 22 amu. 57% of the atoms are 10B, 43% of the atoms are 11B. What is the average mass of your atoms? 35 Example of an Average Atomic Mass Cl-35 is about 75.5 % and Cl-37 about 24.5% of natural chlorine. 35 x 75.5 = 26.4 100 35.5 37 x 24.5 = 9.07 100 LecturePLUS Timberlake 36 Problem AT6 Using the periodic table, specify the atomic mass of each element (round to the tenths place): A. calcium ________ B. aluminum ________ C. lead ________ D. barium ________ E. iron ________ LecturePLUS Timberlake 37 Solution AT6 Using the periodic table, specify the atomic mass of each element (round to the tenths place): A. calcium _40.1 amu _ B. aluminum _27.0 amu _ C. lead _207.2 amu_ D. barium _137.3 amu_ E. iron _55.8 amu__ LecturePLUS Timberlake 38 Calculating Atomic Mass Add : Percent (%) abundance of each isotope Multiplied by the Mass of each isotope of that element Weighted average = mass isotope1(%) + mass isotope2(%) + … LecturePLUS Timberlake 39 Atomic Mass of Magnesium Isotopes 24Mg = Mass of Isotope Abundance 24.0 amu 78.70% 25Mg = 25.0 amu 10.13% 26Mg = 26.0 amu 11.17% Atomic mass (average mass) Mg = 24.3 amu Mg 24.3 LecturePLUS Timberlake 40 Learning Check AT7 Gallium is a metallic element found in small lasers used in compact disc players. In a sample of gallium, there is 60.2% of gallium-69 (68.9 amu) atoms and 39.8% of gallium-71 (70.9 amu) atoms. What is the atomic mass of gallium? LecturePLUS Timberlake 41 Solution AT7 Ga-69 68.9 amu x 60.2 = 41.5 amu for 69Ga = 28.2 amu for 71Ga = 69.7 amu 100 Ga-71 (%/100) 70.9 amu x 39.8 100 Atomic mass Ga LecturePLUS Timberlake 42 Finding An Isotopic Mass A sample of boron consists of 10B (mass 10.0 amu) and 11B (mass 11.0 amu). If the average atomic mass of B is 10.8 amu, what is the % abundance of each boron isotope? LecturePLUS Timberlake 43 Assign X and Y values: X = % 10B Y = % 11B Determine Y in terms of X X + Y = 100 Y = 100 - X Solve for X: X (10.0) + (100 - X )(11.0) 100 100 = 10.8 Multiply through by 100 10.0 X + 1100 - 11.0X = 1080 LecturePLUS Timberlake 44 Collect X terms 10.0 X - 11.0 X = 1080 - 1100 - 1.0 X = -20 -1.0 X -1.0 = -20 - 1.0 X = 20 % 10B Y = 100 - X % 11B = 100 - 20% = 80% 11B LecturePLUS Timberlake 45 Learning Check AT8 Copper has two isotopes 63Cu (62.9 amu) and 65Cu (64.9 amu). What is the % abundance of each isotope? (Hint: Check periodic table for atomic mass) 1) 30% 2) 70% LecturePLUS Timberlake 3) 100% 46 Solution AT8 2) 70% Solution X + Y Y = 100 = 100 - X Solve for X: X (62.9) + (100 - X )(64.9) = 63.5 100 100 Multiply through by 100 62.9X + 6490 - 64.9X = 6350 -2.0 X = -140 X = 70% LecturePLUS Timberlake 47