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MATH II Stephanie Ballantine & Altenese Gibbs October 30, 2009 1st Block (White) Special Right Triangles 1st Performance Standard MM2G1: “Identify and use special right triangles.” MM2G1a – Determine the lengths of sides of 30°-60°-90° triangles. MM2G1b – Determine the lengths of sides of 45°-45°-90° triangles. Special Right Triangles {.Vocabulary.} Theorem 5.1 45°-45°-90° Triangle Theorem: In a 45°-45°-90° triangle, the hypotenuse is √2 times as long as each leg. Theorem 5.2 30°-60°-90° Triangle Theorem: In a 30°-60°-90° triangle, the hypotenuse is twice as long as the shorter leg, and the longer leg is √3 times as long as the shorter leg. Find the value of x. 11 x 45° x x 2√6 Solution: Solution: a. Because the sum of the angle b. You know that each of the two measures in a triangle is 180°, the congruent angles in the triangle measure of the third angle is 45°. has a measure of 45° because the So, the triangle is a 45°-45°-90° sum of the angle measures in a triangle, and by the theorem 5.1, triangle is 180°. So, the triangle is the hypotenuse is √2 times as long a 45°-45°-90° triangle. as each leg. Hypotenuse = leg x √2 x = 11√2 Hypotenuse = leg x √2 2√6 = X x √2 2√3 = X Find the value of x and y. Solution: 60° x y STEP 1 Find the value of x. longer leg = shorter leg x √3 4√3 = x√3 4=x STEP 2 Find the value of y. hypotenuse = 2 x shorter leg y=2x4 y=8 30° 4√3 Examples: x x 12√2 • What is the length of the legs? X = ? • Use the formula. (leg) (hyp / √2) X = 12√2 √2 X = 12 (The legs = 12) 6 6 x • What is the length of the hypotenuse? X = ? • Use the formula. (hypotenuse) (leg x √2) X = 6 x √2 X = 6√2 (The hypotenuse = 6√2 ). Special Right Triangles 2nd Performance Standard MM2G1: “Define and apply sine, cosine, & tangent ratios of right triangles.” MM2G2a – Discover the relationship of the trigonometric ratios for similar triangles. MM2G2b – Explain the relationship between the trig ratios of complementary angles. MM2G2c – Solve application problems using the trig ratios. Apply the Tangent Ratio {.Vocabulary.} Trigonometry: A branch of mathematics that deals with the relationships between the sides and angles of triangles and the calculations based on these relationships. Trigonometric Ratio: A ratio of the lengths of two sides in a right triangle. Tangent: The ratio of the length of the leg opposite an angle to the length of the leg adjacent to the angle that is constant for a given angle measures. Complementary Angles: Two angles are like this if the sum of their measures is 90°. Sine: The ratio of the length of the leg opposite an angle to the length of the hypotenuse to that same angle. Cosine: The ratio of the length of the leg adjacent an angle to the length of the hypotenuse of that same angle. Solve a Right Triangle: Find the measures of all its sides and angles. Find sin X and sin Y. “hypotenuse is always across from the right angle.” Y 20 Z 52 48 sin X = opposite of angle X = YZ hypotenuse XY Plug it into a calculator. = 20 ~ 0.3846 52 sin Y = opposite of angle Y = XZ hypotenuse XY Plug it into a calculator. = 48 ~ 0.9231 52 X Find cos X and cos Y. “Adjacent is the side next to the angle you’re solving for, unless it’s the hypotenuse.” Y 20 Z 52 X 48 cos Y = adjacent of angle Y = YZ hypotenuse XY Plug it into a calculator. = 20 ~ 0.9231 52 cos X = adjacent of angle X = XZ hypotenuse XY Plug it into a calculator. = 48 ~ 0.3846 52 Find the sine and cosine of angles X, Y, L, and M of the similar triangles. Then M compare the ratios. Y c b Z 2c 2b a X N 2a sin X = b c cos X = a c sin L = 2b 2c cos L = 2a 2c sin Y = a c cos Y = b c sin M = 2a 2c cos M = 2b 2c So, since triangle XYZ and LMN are similar triangles, sin X = sin L, cos X = cos L, sin Y = sin M, and cos Y = cos M. L Find tan X and tan Y. Y 13 Z 85 “Note that in the right triangle, XYZ, angle X and Y are complementary angles.” X 84 tan X = opposite of angle X = YZ adjacent to angle X XZ Plug it into a calculator. = 13 ~ 0.1548 84 tan Y = opposite of angle Y = XZ adjacent YZ Plug it into a calculator. = 84 ~ 6.4615 13 Find tan X and Y for the similar triangles. Then compare tangent ratios. Y Y c b Z 2b a X Z tan X = b c tan Y = a b 2c 2a tan X = 2b = b 2a a tan Y = 2a = a 2b b The values of tan X and tan Y for the similar triangles are equivalent. X Example: x 15 tan 28° = opposite adjacent tan 28° = X 15 15 x tan 28° = X 15(0.5317) ~ X 8.0 ~ X 28° • What is the value of X? • Use the tangent of an acute angle to find a leg length. • Write the ratio for tangent of 28°. • Substitute. • Multiply each side by 15. • Use a calculator to find tan 28°. • Simplify. Solving Application Problems “Compare real life situations to the use of special right triangles.” The Eiffel Tower: In this image we are given a picture of the Eiffel tower. We are also given the height(longer leg) of the tower along with the width(shorter leg). Now we are to find the length across the bottom-right corner to the top-left corner(hypotenuse). 1. Use the formula to find the hypotenuse. Hyp = 2 x shorter leg 2 x 382 ft. = 764 ft. Drive-in Movie: You are at a drivein movie with your friend. The screen is level with the top of the car. There is 68 ft. between the top of your car and the top of the screen. The angle of elevation from the same distance is 43°. 1. What kind of triangle is this? 45°-45°-90° Triangle 2. Use the formula to find the leg length. Leg = hyp / √2 68 ft. / √2 ~ 48.08