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EOC Warm Up #5 Objectives The student will be able to: 1. find the prime factorization of a number. 2. find the greatest common factor (GCF) for a set of monomials. 3. Factor using the greatest common factor (GCF). A prime number is a number that can only be divided by only one and itself. A composite number is a number greater than one that is not prime. Prime or composite? 37 prime 51 composite Prime or Composite? 89 1. 2. 3. 4. Prime Composite Both Neither 1) Find the prime factorization of 84. 84 = = = 4 • 21 2•2•3•7 22 • 3 • 7 2) Find the prime factorization of -210. -210= -1 • 210 = -1 • 30 • 7 = -1 • 6 • 5 • 7 = -1 • 2 • 3 • 5 • 7 3) Find the prime factorization of 45a2b3 45a2b3 = 9•5•a•a•b•b•b = 3•3•5•a•a•b•b•b = 32 • 5 • a • a • b • b • b Write the variables without exponents. What is the prime factorization of 48? 1. 2. 3. 4. 3 3 2 2 16 4 4 2 3 4 2 2 2 3 The Greatest Common Factor (GCF) of 2 or more numbers is the largest number that can divide into all of the numbers. 4) Find the GCF of 42 and 60. Write the prime factorization of each number. 4) Find the GCF of 42 and 60. 42 = 2 • 3 • 7 60 = 2 • 2 • 3 • 5 What prime factors do the numbers have in common? Multiply those numbers. The GCF is 2 • 3 = 6 6 is the largest number that can go into 42 and 60! 5) Find the GCF of 40a2b and 48ab4. 40a2b = 2 • 2 • 2 • 5 • a•a•b 48ab4 = 2 • 2 • 2 • 2 • 3 • a • b • b • b • b What do they have in common? Multiply the factors together. GCF = 8ab What is the GCF of 48 and 64? 1. 2. 3. 4. 2 4 8 16 6): What is the GCF of 25a2 and 15a? 5a Let’s go one step further… 1) FACTOR 25a2 + 15a. Find the GCF and divide each term 25a2 + 15a = 5a( ___ 5a + ___3 ) 25a 2 5a 15a 5a Check your answer by distributing. 7) Factor 18x2 - 12x3. Find the GCF 6x2 Divide each term by the GCF 18x2 - 12x3 = 6x2( ___ 3 - ___ 2x ) 18 x 2 6x2 12 x3 6x2 Check your answer by distributing. 8) Factor 2 28a b + 2 56abc . GCF = 28ab Divide each term by the GCF 28a2b + 56abc2 = 28ab ( ___ a + ___ 2c)2 28a 2b 28ab 56abc 2 28ab Check your answer by distributing. 28ab(a + 2c2) Factor 1. 2. 3. 4. x(20 – 24y) 2x(10x – 12y) 4(5x2 – 6xy) 4x(5x – 6y) 2 20x - 24xy 9) Factor 28a2 + 21b - 35b2c2 GCF = 7 Divide each term by the GCF 28a2 + 21b - 35b2c2 = 7 ( ___ 4a2 + ___ 3b- ____ 5b2)c2 28a 2 7 21b 7 35b 2 c 2 7 Check your answer by distributing. 7(4a2 + 3b – 5b2c2) Factor 1. 2. 3. 4. 2 16xy 2y2(8x – 12z + 20) 4y2(4x – 6z + 10) 8y2(2x - 3z + 5) 8xy2z(2 – 3 + 5) - 2 24y z + 2 40y