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"Name:
Date: 2-0 C Block: (3
tics: Practice Packet / Honors Bio
nst genetic traits have a stronger, dominant allele and a weaker, recessive allele. In an individual with a
heterozygous genotype, the dominant allele shows up in the offspring and the recessive allele gets covered up and
doesn't show; we call this complete dominance.
However, some alleles don't completely dominate others. In fact, some heterozygous genotypes allow both alleles
to partially show by blending together how they are expressed; this is called incomplete dominance. Other
heterozygous genotypes allow both alleles to be completely expressed at the same time like soots or stripes; this is
called codominance. Examples of each are listed below.
Write what each type would be if they were heterozygous.
1. Complete dominance = If a Red (RR) and White flower (rr) were crossbred, resulting in 100 0/0 Rr, what
phenotype would been seen according to the rules of COMPLETE dominance?
got
2. Incomplete dominance = If a Red (RR) and White flower (rr) were crossbred, resulting in 100% Rr, what
phenotype(s) would been seen according to the rules of IN-complete dominance?
3. Codominance = If a Red (RR) and White flower (WW) were crossbred, resulting in 100% RW, what
phenotype(s) would been seen according to the rules of CO-dominance?
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5-4;
Incomplete dominance practice Problems
6. Snapdragons are incompletely dominant for color; they have phenotypes red, pink, or white. The red flowers
homozygous dominant, the white flowers are homozygous recessive, and the pink flowers are heterozygous.
Give the genotypes for each of the phenotypes, using the letters "R" and " r "for alleles:
a. Red snapdrawk
genotype:
c. White snapdragon
genotype: Ir-C
b. Pink snapdragon
genotype: Ric
Show genetic crosses between the following snapdragon parents, using the punnett squares provided, and
record the genotypic and phenotypic oks below:
a. pink x pink
b. red x white
gg.
r
r
Fir
Genotypic
o%:
k: 13: : 513
2c
0P/oh:enoty3c.,15: o...21.Bc;
ICPto.
c. yink x white
RiP(
rr
Genotypic
ws: D 100;0
Genotypic
0:
%:
Phenotypic
Phenotypic
%:
%:
t1'
?P,
rr
1
Cr) r,
ST-5
e„ -n
so /0 4it-r--cp 90 vac:4-c_
7-9. In horses, some of the genes for hair color are incompletely dominant. Genotypes are as follows: brown hors
are BB white horses are bb and a Bb genotype creates a yellow-tannish colored horse with a white mane And tail, \
which is called "palomino". Show the genetic crosses between the following horses and record the genotypic and
phenotypic percentages:
a. brown x white
b BO ()
b ABC)
Genotypic
%: b: ltt)10
b. browr palomino
b 5b
0
c.talonpno x palomino
Bt3 '3
Bb
Genotypic ,
%:
6
ca bin
Genotypic
%:
R) •
;
Phenotypic
Phenotypic,
Phenotypic
i ce> - 0
%: 5-0:-00
%:
f}:cc
-Pate
cj
10. Can palominos be considered a purebred line of horses? Why or why not?
sy,--
L-kV•r)
o-u,
INcLA-z-r-c-zs
11. Which two colors of horse would you want to e if you wanted to producehe maxi um
palominos
in the shortest amount of time? en
1 1
Bb Ito%
p x ka-D
numbers of
p
12. In Smileys, eye shape can be starred (SS), circular (CC), or a circle with a star (CS). Write the genotypes
for the pictured phenotypes
NS"9-
e.rre I Sit-1--
5 5
C$
SS ss
C
$
13. Show the cross between a star-eyed and a circle eyed;.
What are the pl:nliMpes of the offspring?
(2-b-trks2 co-1r(
What are the genotypes?
1";
Cs
14. Show the cross between a circle-star eyed, and a circle eyed.
Z.
How maw of the offspring are circle-eyed?
How
I
_____nnof
the offspring are circle-star eyed?
C
CC
CS
C
6C
CS
Ca_ 5
15. Show the cross between two circle-star eyed. i
How many of the offspring are circle-eyed?
2—
How many of the offspring are circle-star eyed?
How many are star eyed?
C c_c
S CS SS
Name
Period
2
Date
Codominance Worksheet (Blood types)
Human blood types are determined by genes that follow the CODOMINANCE pattern of inheritance.
/Mere are two dominant alleles (A & B) and one recessive allele (0).
Blood Type
(Phenotype)
Genotype
Can donate blood to:
0
ii (00)
A,B,AB and 0
(universal donor)
AB
AB
IAIB
IAIA or IAi
(IA0)
IBIB or fi
A
B
Can receive blood from:
AB, A
0
A,B,AB and 0
(universal receiver)
0,A
AB,B
0,B
(IND)
1. Write the genotype for each person based on the descriptioB
a. Homozygous for the "B" allele
/
:Gee
A- -
b. Heterozygous for the "A" allele
Po 1 ;)- ii
c. Type 0
(X-)
d. Type "A" and had a type "0" parent
0
711t
/
2it— /
e. Type "AB"
f.
i 3,-/C
0—
Blood can be donated to anybody
g. Can only get blood from a type "0" donor
`ig 4r-
fi1'
j..
0
2. Pretend that Brad Pitt is homozygous for the type B allele, and Angelina Jolie is type "0
What are all the possible blood types of their baby? (Do the Punnett square)
3. Complete the Punnett square showing all the possible blood types for the offspring piec700
by a type "0" mother and an a Type "AB" f ther. What are percentages of each‘df
J °10
A S T "C)
L
6
0
110
eo
eo
4. Mrs. Essy is type "A" and Mr. Essy is type "0." They have three children named Matthew,akEnd
Luke. Mark is type "0," Matthew is type "A " and Luke is type "AB." Based on this inforr
a. Mr. Essy must have the genotype
0
b. Mrs. Essy must have the genotypet because rUkr- - has blood typea
c. Luke cannot be the child of these parents because neither parent as the a lele fTh
fo
(
5. Two parents think their baby was switched at the hospital. Its 1968, so DNA fingerprin,...,
does not exist yet. The mother has blood type "0," the father has blood type "AB,"
and the baby has bloqlcitypecT)
0
a. Mother's genotype: 0
b. Father's genotype:
AB
3
or)
1
or '
_ 4
c. Baby's genotype:
A
d. Punnett square showing all possible genotypes for children produced by this couple.
PO
e. Was the baby switched?
6. Two other parents think their baby was switched at the hospital. Amy the mother has bAod t9De "A,"
Linville the father has blood type "B," and Priscilla the baby has blood type "AB."
a. Mother's genotype: I40 or
b. Father's genotype:
B0
or
)60
1,b9 to
CI AA, /343 '3
AAb1
-
c. Baby's genotype:
d. Punnett square that shows the baby's genotype as a possibility
1' 5
e. Could the baby actually be theirs?
7. Based on the information in this table, which men could not be the father of the baby?
(hint.. look at the baby's blood type only...)
10
I
A
You can use the Punnett square if you need(lielp figurihg it out
Name
Blood Type
Mother
Type A
Baby
Type B
The mailman
Type 0
The butcher
Type AB
The waiter
Type A
The cable guy
Type B
(0:5A2-- tAKP: VV. Y)
oo_c-4-4-er
4e)
9D
8. The sister of the mom above also had issues with finding out who the father of her baby was. She had the
state take a blood test of potential fathers. Based on the information in this table, why was the baby
taken away by the state after the test? (hint.. look at the baby's blood type on/y..)
C_
Sto—
Name
Blood Type
Mother
Type 0
Baby
Type AB
Bartender
Type 0
Guy at the club
Type AB
Cabdriver
Type A
Flight attendant
Type B
uka_.ut 1/2 -kio ki-ew-a (A i
17tcoc5t-11T2-73-
-•
4
8 es M3
BLOOD TYPING & INHERITANCE
In blood typing, the gene for type A and the gene for type B are codominant. The gene for type 0 is
r-sessive. Using Punnett squares, determine the possible blood types of the offspring when:
1. Father is tyr, Mt, is type 0
00
u
00
CO-0 % 0
%A
%B
oC o0
% AB
2. Father is type A, homozygous; Mother is type B, homozygous
5 fn3
b At
0
A
%B
% AB
4. Father 's type A, heterozygous; Mother is type B, heterozygous
ft
cc
5. Father s type 0, Mother is type AB
J3
O 0
*0
FO
6. Father and Mother are both type AB
%0
2-S % A
%B
% AB
V?)
5
n
Pedigree Worksheet
Use the given pedigrees to answer the following questions:
The pedigree to the right shows the passing on
of straight thumbs (recessive) and Hitchhiker's
Thumb (dominant) in a family. Shaded shapes
mean the person has a straight thurobi
1. What is the genotype of IV-1? lik.V■
2. What is the genotype IV-3?
WiN_
3. What is the genotype of III-1? -1-kiA
4. What is the genotype 111-2?
HI
iv
Ok"
5. What is the genotype 11-3? 1-1 0- v-ir *A
6. Is it possible for individual IV-2 to be, a
carrier? \ 5
45
Why? 17>b{ .1L---/
cs“.\--e
Co-ini‘ -t)
rS
•a
7. The pedigree to the right shows the
I
passing on of colorblindness (a recessive,
sex-linked trait). Fill in the numbers for
each generation (generation IV is done for
you).
C
8. What do the half shaded circles mean? &-fl t
rS
-401111±
m
-2_
9. What is the 19)NLY sex carriers of colorblindness
can be?
v.K.Q.
S
iv
10. Which individuals are colorblind?T'
-4- -A-as■g
LI-1-")
9,)
tv- t i c,
it What is the genotype of person 11-2?
l-
1
2
3
6
,3
4
5
6
7
(-9—
12. What is the genotype of person I-1? X
13. What is the genotype of person 111-3?
14. If person W-1 marries a female who is not colorblind and is not a carrier, what are the chances of their
male offspring being colorblind? 0
What about their female offspring?
0
11
ut.-1
c
fc mid t-S
8
•■
= Sickle Cell
Anemia
NOTE- carriers are not shown on this pedigree although Sickle Cell Anemia IS A RECESSIVE DISORDER.
15. Which members of the family above are afflicted with sickle cell , anemia?- -
.11-
C-;54-9
16. How are individuals 111-4 and 111-5 related?
17. How are individuals I-1 and 1-2 related?
14-LL ■,.
18. How are individuals 11-7 and 111-2 related?
Atta+1
19. How are individuals 1-2 and 111-5 related?
Grre'-‘0-alAnAtti•syk
20. How many children did individuals I-1 and 1-2 have?
21. How many girls did II-1 and 11-2 have?
-7,3
3
O-N/4-
t)--kt-ce-
-ec
&OWN
(0
How many have sickle cell anemia?
4r- S
22. Label the possible genotypes for all individuals in the pedigree. One person can have more than one
possible genotype
12
k L