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bsc 4su cce ss.c om QUADRATIC EQUATION FOR IBPS PO MAIN Directions (Q. 1-10): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer 1) if x > y 2) if x > y 3) if x < y 4) if x < y 5) if x = y or no relation can be established between x and y. 1. I. 35x2 – 53x + 20 = 0 II. 56y2 – 97y + 42 = 0 2. I. x = II. 13y + 3x = 246 3. I. x2 – 5x – 14 = 0 II. y2 + 7y + 10 = 0 4. I. x2 – 3481 = 0 II. 3y2 = 5. I. 5x2 + 2x – 3 = 0 II. 2y2 + 7y + 6 = 0 6. I. 20x2 – 67x + 56 = 0 II. 56y2 – 67y + 20 = 0 7. I. x4 = 65536 II. y = 8. I. 2x2 + 11x – 40 = 0 II. 4y2 – 27y + 44 = 0 9. I. 7x = 4y + 85 II. y = 3 17576 10. I. x2 = 14641 II. y = 14641 3 4913 3 3 216000 4096 Answers with Explanation 1. 3; I. 35x2 – 28x – 25x + 20 = 0 or 7x(5x – 4) – 5(5x – 4) = 0 or (7x – 5) (5x – 4) = 0 5 4 , 7 5 II. 56y2 – 48y – 49y + 42 = 0 or 8y(7y – 6) – 7(7y – 6) = 0 or (8y – 7) (7y – 6) = 0 x= 7 6 , 8 7 x < y y= Downloaded From: http://bsc4success.com bsc 4su cce ss.c om 2. 1; I. x = 3 4913 x = 17 II. 13y = 246 – 3x or 13y = 246 – 51 = 195 y = 15 x > y 3. 2; I. x2 – 7x + 2x – 14 = 0 or x(x – 7) + 2(x – 7) = 0 (x + 2) (x – 7) = 0 x = –2, 7 II. y2 + 5y + 2y + 10 = 0 or y(y + 5) + 2(y + 5) = 0 or (y + 2) (y + 5) = 0 y = –2, –5 x > y 4. 5; I. x2 = 3481 x = +59 II. 3y2 = 3 216000 3y2 = 60 y = + 20 No relation 5. 1; I. 5x2 + 5x – 3x – 3 = 0 or 5x (x + 1) – 3(x + 1) = 0 or (5x – 3) (x + 1) = 0 3 ,–1 5 II. 2y2 + 4x + 3y + 6 = 0 or 2y(y + 2) + 3(y + 2) = 0 or (2y + 3) (y + 2) = 0 x = y = – 3 ,–2 2 ie x > y 6. 1; I. 20x2 – 35x – 32x + 56 = 0 or 5x(4x – 7) – 8(4x – 7) = 0 or (5x – 8) (4x – 7) = 0 8 7 , 5 4 II. 56y2 – 32y – 35y + 20 = 0 or 8y(7y – 4) – 5(7y – 4) = 0 x = Downloaded From: http://bsc4success.com or (8y – 5) (7y – 4) = 0 5 4 , 8 7 x>y bsc 4su cce ss.c om y = 7. 4; I. x4 = 65536 x = +16 II. y = 3 4096 y = 16 x<y 8. 3; I. 2x2 + 16x – 5x – 40 = 0 or 2x(x + 8) – 5(x + 8) = 0 or (2x – 5) (x + 8) = 0 5 ,–8 2 II. 4y2 – 16y – 11y + 44 = 0 or 4y(y – 4) –11(y – 4) = 0 or (4y – 11) (y – 4) = 0 x = y = 4, 11 4 x<y 9. 1; I. 7x = 4y + 85 or 7x = 4 × 26 + 85 (Put y = 26) x= 189 = 27 7 II. y = 3 17576 y = 26 x > y 10. 4; I. x2 = 14641 x = +121 II. y = 14641 y = 121 x < y Downloaded From: http://bsc4success.com