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QUADRATIC EQUATION FOR IBPS PO MAIN
Directions (Q. 1-10): In each of these questions, two equations (I) and (II) are given.
You have to solve both the equations and give answer
1) if x > y
2) if x > y
3) if x < y
4) if x < y
5) if x = y or no relation can be established between x and y.
1.
I. 35x2 – 53x + 20 = 0
II. 56y2 – 97y + 42 = 0
2.
I. x =
II. 13y + 3x = 246
3.
I. x2 – 5x – 14 = 0
II. y2 + 7y + 10 = 0
4.
I. x2 – 3481 = 0
II. 3y2 =
5.
I. 5x2 + 2x – 3 = 0
II. 2y2 + 7y + 6 = 0
6.
I. 20x2 – 67x + 56 = 0
II. 56y2 – 67y + 20 = 0
7.
I. x4 = 65536
II. y =
8.
I. 2x2 + 11x – 40 = 0
II. 4y2 – 27y + 44 = 0
9.
I. 7x = 4y + 85
II. y = 3 17576
10.
I. x2 = 14641
II. y = 14641
3
4913
3
3
216000
4096
Answers with Explanation
1. 3; I. 35x2 – 28x – 25x + 20 = 0
or 7x(5x – 4) – 5(5x – 4) = 0
or (7x – 5) (5x – 4) = 0
5 4
,
7 5
II. 56y2 – 48y – 49y + 42 = 0
or 8y(7y – 6) – 7(7y – 6) = 0
or (8y – 7) (7y – 6) = 0
x=
7 6
,
8 7
x < y
y=
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2. 1; I. x = 3 4913
x = 17
II. 13y = 246 – 3x
or 13y = 246 – 51 = 195
y = 15
x > y
3. 2; I. x2 – 7x + 2x – 14 = 0
or x(x – 7) + 2(x – 7) = 0
(x + 2) (x – 7) = 0
x = –2, 7
II. y2 + 5y + 2y + 10 = 0
or y(y + 5) + 2(y + 5) = 0
or (y + 2) (y + 5) = 0
y = –2, –5
x > y
4. 5; I. x2 = 3481
x = +59
II. 3y2 = 3 216000
3y2 = 60
y = + 20
No relation
5. 1; I. 5x2 + 5x – 3x – 3 = 0
or 5x (x + 1) – 3(x + 1) = 0
or (5x – 3) (x + 1) = 0
3
,–1
5
II. 2y2 + 4x + 3y + 6 = 0
or 2y(y + 2) + 3(y + 2) = 0
or (2y + 3) (y + 2) = 0
x =
y = –
3
,–2
2
ie x > y
6. 1; I. 20x2 – 35x – 32x + 56 = 0
or 5x(4x – 7) – 8(4x – 7) = 0
or (5x – 8) (4x – 7) = 0
8 7
,
5 4
II. 56y2 – 32y – 35y + 20 = 0
or 8y(7y – 4) – 5(7y – 4) = 0
x =
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or (8y – 5) (7y – 4) = 0
5 4
,
8 7
x>y
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y =
7. 4; I. x4 = 65536
x = +16
II. y = 3 4096
y = 16
x<y
8. 3; I. 2x2 + 16x – 5x – 40 = 0
or 2x(x + 8) – 5(x + 8) = 0
or (2x – 5) (x + 8) = 0
5
,–8
2
II. 4y2 – 16y – 11y + 44 = 0
or 4y(y – 4) –11(y – 4) = 0
or (4y – 11) (y – 4) = 0
x =
y = 4,
11
4
x<y
9. 1; I. 7x = 4y + 85
or 7x = 4 × 26 + 85 (Put y = 26)
x=
189
= 27
7
II. y = 3 17576  y = 26
x > y
10. 4; I. x2 = 14641
x = +121
II. y = 14641
y = 121
x < y
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